for the first example shouldnt it be -2xcosx-2sinx+c as when you integrate -2cosx it would become +2sinx which then when you takeaway is -2sinx +c from the rest of the equation sorry if this is wrong maybe i didn't follow it through properly
When differentiating, it goes sin, cos, -sin, -cos. When integrating -cos, it goes to -sin. The full formula after integrating -cos was -2xcosx-(-2sinx)+c. Two negatives equal a positive. Therefore -2xcosx+2sinx+c is correct.
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just came across your videos.they r great
for the first example shouldnt it be -2xcosx-2sinx+c as when you integrate -2cosx it would become +2sinx which then when you takeaway is -2sinx +c from the rest of the equation sorry if this is wrong maybe i didn't follow it through properly
When differentiating, it goes sin, cos, -sin, -cos.
When integrating -cos, it goes to -sin. The full formula after integrating -cos was -2xcosx-(-2sinx)+c.
Two negatives equal a positive. Therefore -2xcosx+2sinx+c is correct.
@@felico1100 Thanks bud!
I think im in love with you
Pootis
same
good teaching bro but you made a mistake in the first one