Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️. jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.
1.C6H5-CO-CH=C-CH3C6H5 2.C6H5-COCH=CH-C6H5 are the answers of that last question finally thanks sir for the nice tricks to understand aldol condensation very easily.
Completed... Sir aapne jo last question diya tha vo solve ho gaya... App Etna basic se samajte ho to.. Question solve nhi Ho.. Esa kabhi ho sakta hai.. Thankyou so much Sir.. You are great sir...
Last question ka ans ho gaya. Or mai conform hoon ki mera ans thik ha. Or iski waja aap ho sir. Apne itni achhi tarah se samjhaya. Thank u very much sir❤️💛💛❤️
aap ko bhgwan ji ne hme hi pdane k liye beja h aap to mere liye duniya k best teacher ho 😋😋😋😍😍😍😍😍😘😘😘😘😘😘😘😘😅😅😅😄😄😄😃😃😃😃🤣🤣🤣🤣🤣😍😍😍😍😍😍😍😍👍👍👍👍👍👍👍👍👍👍👍👍👍👍💜💜💜💜💞💝💝💝💝💝💝💟💟💟
Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir
1)C6H5-(CH3)C=CH-CO-C6H5 2)C6H5-CH=CH-CO- C6H5 Sir this is my answer.. Finally thanku so much sir for this awesome lecture.I have seen all your lectures of Organic chemistry... Now I have develope confidence in organic chem... Thanku so much sir💕💕💕💕
P1= c6h5 -(ch3)c=ch-co-c6h5 P2 =c6h5 -ch=ch-co-c6h5 Sir Answer of last question...perfect understood sir.. no word to say..amazing teaching..thanks alot sir for this knowledge aapki wajah se meri organic chemistry aur jayda perfect &easy ho gyi
Sir u r reaaaallllllyyyyy amazing 🙏 mujhe ye pura mechanism samajh aa gaya hai aur woh bhi without repeating . Thank you sir 🙏 for such simple videos ❤️
U gave one question to do and told that if we can't then u will tell us the answer. Bt u r totally mad sir.... apne samjhaya aur hum nahin kar payenge... ye hohi nahin sakta.... 😅😅Love u sir
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1) *C6H5-CH=CH-CO-C6H5*
2) *C6H5-(CH3)C=CH-CO-C6H5*
*Perfectly understood sir no word 2 say Ur teaching just wonderful...👍👍👍👍 thanks a lot sir😄😄*
Right sis ....😀
Ur right Dr shweka
@@chemclasse yes Naziya sis😊😊
@@sumanavadagi7390 yaaa ryt😊
@@Feelings4youu app kaha se hai shweka
Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️. jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.
U r wrong ka bhi iit ka content dekhna coaching ka tab pta chalega sir ki videos r not sufficient for iitjee
Genand mai daal le quality education
1.C6H5-CO-CH=C-CH3C6H5
2.C6H5-COCH=CH-C6H5 are the answers of that last question finally thanks sir for the nice tricks to understand aldol condensation very easily.
YES YOU ARE RIGHT GREAT JOB ARE YOU REPEATER OR IN CLASS 12
i think you are right
You are right bro
👍👍👍👍
Can anyone tellwhat if only 1H is present then how will h20 remove??
Yaaro sach mai....World ka koi bhi teacher itna selfless nahi padha sakta...😍😍😍
Sir...you are master of explanation...💙
(1) self product -- C6H5-CO-CH3 + C6H5-CO-CH3--------C6H5-CO-CH=C-(CH3) C6H5
(2) Cross product--C6H5-CO-CH3 +C6H5-CHO -------------C6H5-CO-CH=CH-C6H5 (LOTS OF THANKS SIR JI )
Sirrr....u r really an idol teacher..... thank u so much sir...for giving us such a phenomenal knowledge
No doubt... he is insane 💯💯
Kya ye trick board exam me lga skte hai
@@Shivam313 Haan lga sakte hai
Maine mere school mein bhi lga ya tha
School k teacher ne toh kuch nhi bola
Yesss, no doubt in this
Sir, I complete this last reaction.
Completed...
Sir aapne jo last question diya tha vo solve ho gaya...
App Etna basic se samajte ho to.. Question solve nhi Ho.. Esa kabhi ho sakta hai..
Thankyou so much Sir..
You are great sir...
4:57 mei jo question hai woh same question iss saal ke board exam mei aaya tha.. code 56/3/1.. set 1..2019
Sir ji itni practice apne krwa di ki 20 sec me answer nikal re hain aldol and cross aldol k .... thank u very much sir
Self Aldol product (1). 3-Methyl-1,3-diphenylprop-2-en-1-one.(C6H5-(CH3)C=CH-CO-C6H5)
cross Aldol product ( 2). 1,3-Diphenylprop-2-en-1-one.(C6H5-CH=CH-CO-C6H5)
superb trick sir ji thank you💖🙏
Hlo
Yr book mein toh inka ek hi product written hai jisme alcohol grp bhi hai.
Please clear this to me
Jaise book mein ch3cho + hcho ka product ohch2ch2cho hai
Hlo karaj
Done sir......really it was the most easy ...effective...smooth..trick i had ever came across regarding aldols...
P1 = C6H5-C(CH3)=CH-CO-C6H5 (self product)
P1 = C6H5-CH=CH-CO-C6H5 (cross product)
Thanks sir 😊💐
👍✌
Perfect
Sir answer ho gya so happy...To solve aldol and cross aldol questions....
Truely a great teacher u are.....🙏
sir ho gya successfully..... ab mey aldol ka product bana paa raha hu vry easily....... thnks to u sir
U are awesome sir ... concepts cleared in the best way ....its the most simple way
Sir you are the best chemistry teacher in the world
Sir paani nikalte nikalte aab haath v paani ki tarah chlne lgee hai ...
Great teaching indeed
Sir ab aldol bhaut easy way Mai product ban Rahi hai thanks sir
Sir really you made us understand everything very easily. So that I could manage to do question in just few seconds.😎
Sir Aap Smjhaye or smjh me Na Aaye Aisa ho hi nhi Skta hai
Thanks a lot ! Sir 🙏🙏
SELF ALDOL--- 1,3diphenylbut-2-ene-one
CROSS ALDOL----- 1,3diphenylprop-2-ene-one 🤞🤞🤞
U r amazing sir ...u made this topic, so much interesting for me ..😃😃
Your teaching is the best on RUclips and most helpful for me👍👍👍👍👍👍👍👍👍👍
Sir 10sec me ho gya last question.. Itna Accha samjhaya apne.. Thank you so much🙏🙇 sir
Sir mera last sawaal solve ho gya very nice explanation
( 1,3 di phenyl 3- Methyl Prop-2-enone) :- ist Product
(1,3 di phenyl Prop-2-enone)
1 galat hai bhai methyl substitute group me Nahi hai
Agr ap jasay teacher ho to Mcat or Ecat koi difficult nai ho saktay
C6H5-CH=CH-CO-C6H5 By self aldol
C6H5-(CH3)C=CH-CO-C6H5 By cross aldol
Thanks sir
You are great
Thank you sir 🙏 Mera ans aa gaya h😊
Mechanism and short trick, dono samjh aa gayi!!!
Thank you so much Sir 🙏
Self: C6H5- (CH3)C=CH-CO-C6H5
Cross aldol: C6H5-CH=CH-CO-C6H5
Thanks a lot sir
superb trick from super sir......................................
Self condensation product--> Ph-CO-CH=C(CH3) -ph
Cross condensation product-->
Ph-CH=CH-CO-Ph
Thank u sir.
We are so much lucky that we have got a teacher like you...
Thank you sir for your greatest efforts from my core of heart
Best Teacher Across RUclips 💗🙏🏼 Thankyou so much sir 🙏🏼
Wow sir u r amazing... Best teacher of chemistry... Sir aap hameaha healthy rahe or isi tarah padhate rahe. Thank u so much sir
Last question ka ans ho gaya. Or mai conform hoon ki mera ans thik ha. Or iski waja aap ho sir. Apne itni achhi tarah se samjhaya. Thank u very much sir❤️💛💛❤️
aap ko bhgwan ji ne
hme hi pdane k liye beja h
aap to mere liye duniya k best teacher ho 😋😋😋😍😍😍😍😍😘😘😘😘😘😘😘😘😅😅😅😄😄😄😃😃😃😃🤣🤣🤣🤣🤣😍😍😍😍😍😍😍😍👍👍👍👍👍👍👍👍👍👍👍👍👍👍💜💜💜💜💞💝💝💝💝💝💝💟💟💟
One of best teacher in the world
Cross aldol product = C6H5- CH= CO-C6H5 and self aldol product C6H5-CCH3=CH-CO-C6H5. Thank you so much sir. Aa gya smjh organic king sir ji
😍😍😍😍😍😍......sir you really amazing...hatts off to you sir.......and im sure your teaching will bring a success in our exams...
Sir question ho gaya easy tha bhaut
Jag ghoomeya aap jaisa techer na koi !!😍😍
Sir you are the best. Everything is clear now. Thank you so much sir 🙏 ☺ ❤
Great trick sir.... 🙏🙏
Wonderful sir soo wonderful your teaching method is Excellent
It's hardly take 10 seconds for me to solve this...
😄😃😃This is really amazing
Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir
hmara sara parivar aapka dhnyawad krta h jiiii
Thnqq so much ..... very very perfect and easy explanations👍👍
Sir mera ho gaya
You are my best teacher on RUclips
Sir ke fan like jarur kare👍👍👍👍👍👍👍👍
Two products -
a) 1,3-Diphenylprop-2-en-1-one
b) 1,3-Diphenylbut-2-en-1-one
Amazing lecture sir ! 👏
yupsss sir...apne jo qustn diya vo ban gya.....ap padhaye or us concept se qustn solve na ho,aisa ho nhi nh skta.....
Sir kya kho ab itna deeply badiya samjhna itna hard work sir thanku so much sir love you from Haryana palwal
Sir mujhse bhai ho Gaya last question! When you teach everything seems easy 🤩
Thank you Arvind Sir!!!!!!
1)C6H5-(CH3)C=CH-CO-C6H5
2)C6H5-CH=CH-CO- C6H5
Sir this is my answer..
Finally thanku so much sir for this awesome lecture.I have seen all your lectures of Organic chemistry...
Now I have develope confidence in organic chem...
Thanku so much sir💕💕💕💕
Nim thara chimistry na easy agi helkodo teacher nan ellu nodilla sir hat's off to you😊
Thanks a lot sir !!! Best trick ever known !!!!
sir ban gya question.. or bohot maza bhi aaya banane me... thanks sir ye short trick batane ke liye
Last question done sir !!
Thanks a lot for all your efforts ☺
Sir the answer for cross aldol product is 1,3-Diphenylprop-2-enone
And the answer for self aldol product is 1,3-Diphenylbut-2-enone
Ji sir bn gye products successfully bhut mja aaya sch m 😊😊
Best teacher on RUclips👌
C6H5-CH=CH-CO-C6H5 , C6H5-C-CH3=CH-CO-C6H5 I had done sir it is a very simple trick thankuu
P1= c6h5 -(ch3)c=ch-co-c6h5
P2 =c6h5 -ch=ch-co-c6h5
Sir Answer of last question...perfect understood sir.. no word to say..amazing teaching..thanks alot sir for this knowledge aapki wajah se meri organic chemistry aur jayda perfect &easy ho gyi
Thank-You Sir ... These Videos 📹 are making my ORGANIC CHEMISTRY ⚗ STRONGER 💪💪💪💪💪💪💪💪💪...
Answer of last question :
1) C6H5-CH=CH-CO-C6H5
(Cross - aldol product)
2) C6H5-(CH3)C=CH-CO-C6H5 (Self - aldol product)
No words sir such an amazing teaching...
Sir meraa last question solve ho gaye haii....bahut hii easily..... because of u... thanku sir...
Thank you sir 😊😊. You made it so easy
Sir u r reaaaallllllyyyyy amazing 🙏 mujhe ye pura mechanism samajh aa gaya hai aur woh bhi without repeating . Thank you sir 🙏 for such simple videos ❤️
*WE REALLY APPRECIATE YOUR AND YOUR TEAM HARDWORK FOR US SIR ❤❤👍👍👍*
SIR LAST WALA QUESTION HO GAYA...
*THANK YOU SO MUCH SIR😀😀😀😀😀😀😀😀😀😀🤗🤗🤗🤗🤗😊😊😊😊😊😀😀😀😀😀😀😀😀😀*
1,3 diphenyl 3methylprop-2-enone
Ho gaya sir home work. It's very easy.
Ans are-
1- c6h5-ch=ch-c=o(c6h5)
2- c6h5-c(ch3)=ch-c=o(c6h5)
Last question ho gya sir . Sir apne to chemistry ko mere liye maths se bhi easy bna diya h thanks a lot sir
1,3-diphenyl-but-2-enone and 1,3-diphenyl-prop-2-enone
U gave one question to do and told that if we can't then u will tell us the answer. Bt u r totally mad sir....
apne samjhaya aur hum nahin kar payenge... ye hohi nahin sakta.... 😅😅Love u sir
I did the homework and understood thanks a lot sir 😊😊😊😊
Best explanation ever heard😊
Good morning my favorite sir, and thanks a lot for your help 😃😃😃😃😃😃😃😃😃😃😃😃
I mean that's really wonderful....I used to b so scared of chemistry...n now I m just loving it...thnkuh so mchh🙏🙏🙏
Wow sir itna ache se to aaj. Tak kisi ne bhi smjhaya thank you very much sir ✨🙏👍👍
Sir Kamal kr rhe ho aap to chemistry itni easy bna di h🆒🆒🆒🆒🆒🆒🆒
I am understand sir g 🌹🌹🌹🌹🌹🌹
Last qsn bn gya h sir......awesome teaching🙇🙇🙇👍👍👍👍😊😊😊
Sir you are indeed amazing. I spent 3 hours but didn't understand anything till i saw your video. Sir i have done the last question.
Hogaya sir, aap kafi achi trick batate hai sir
P1=C6H5-Co-CH=CH-C6H5
P2=C6H5-Co-CH=CH-C6H5
Thankx sir 🌻
Ans 1 = 1,3-Diphenyl, prop-2-en-1-one (cross aldol )
And 2 = 1,3-diphenyl, but-2-en-1-one ( self aldol )
Thank you sir😄😄
sir it took me 10 seconds thank u so much very nice trick
Ur teaching is the simplest....😍
Sir this short trick is very helpful and l have done the last question successfully
Aapke vedeo dekhke to jise chemistry me bilkul b interest n ho use b aa jae qki aap bhut achche se smjhate ho sir
Sir last que hogya😍
Wow sir jabardast pure question ban gae😁😁😁😁
Only a few words
LOVE YOU DEAR SIR JI