3x to the (3/4) power - 6 = 0, Many don’t know where to start…
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- Опубликовано: 19 янв 2024
- How to solve an equation with rational exponents.
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![[(3 - 11) + 2(5 - 6)] divided by (8 - 10) = ? Can You Do BASIC MATH?](http://i.ytimg.com/vi/4-U2GvfJB8s/mqdefault.jpg)
![[(3 – 11) + 2(5 – 6)] divided by (8 – 10) = ? Can You Do BASIC MATH?](/img/tr.png)
Love all these people saying the did it in 30s…It’s not FOR YOU. It’s for people learning it for the first time and it is remarkably well explained.🎉
I think the point is, a lot of this stuff isn't being taught anymore. As is the case for a lot of other things not being taught anymire...
"Many will get wrong", "Many don't know where to start". Nice encouragement you provided there John!
If you did in fact get it wrong, then you won't feel so alone. And if you got it right, you can feel a little bit special.
Greetings. Yes we can. The value for X that satisfies the expression is
2(2)^1/3. The given expression can be written as X^3/4=2 by dividing the entire expression by 3 and transposing the known quantity to the right hand side. Now, moving on, we will raise each side of the expression to the 4th power to get
(X^3/4)^4=2^4, and X^3=16, from which it is determined that X =2(2)^1/3. Lovely.
hi can you say that in English please?
I'm glad I'm not at school anymore
Lot easier just to see that if 3x^3/4 =6 then.... x^3/4 must = 2 then 4th power of both side equation to see the final answer..:)
fun. thanks for the lesson. i knew the exp was inversed, just couldn't remember the whole procedure.
Thank you
Another fun one in my head, mostly thanks to your refresher in a previous video. Keep up the good work!
No bone today. Excellent lesson. Thanks Boss.
Took a different approach via log: logx= 4/3log2, hence x= 2,52...
Solved in my head. It's been a while but I remembered exponent rules.
Thanks Mr. RUclips Math man!
This might be completely wrong but ..
3X^3/4 - 6 = 0 means that
3X^3/4 = 6 and X^3/4 = 2 and X = 2^4/3
2(2)^1/3
I can raise 2 to the 4th power then take the cube root.
Or I can take the cube root, then raise it to the 4th power.
And get the same answer!
I didn't know that.
Cube root of 16
I kept getting 2 (1/4) - 6 = 0 which doesn't add up, so I'm still unsure how to correctly get it to = 0 😅
I was taught to make whole numbers fractions to handle fractions, ie 3 becomes 3/1, so the result is 9/4.
Then again, I barely passed math haha
x^3/4=2
x=2^4/3
2>4/3 but i dont know how to solve it from there without a calculator
Unless x is supposed to be real, there are two other complex number solutions and this video doesn't cover that at all while going unnecessarily long to get the obvious / trivial real value solution.
Why not show that 2^4/3 equals 2 times sqrt 2?
Why do you unnecessarily make stuff hard to follow?
All you need to do is
x^(3/4) = 2
(x^3)^1/4 = (2^4)^(1/4)
Using the power rule
x^3 = 2^4
x = 2^(4/3)
Never mind I get it. Thanks.
Wasnt it friday the movie when craig whistled
2.6 comes very close
I think I did that? Still got 2 cube root 2. So I think good
How you know that. Maybe you were their maths teacher
Dude, if it takes longer than 8 minutes to explain, you can safely assume I aint ever going to get it.
2^(4÷3)
Solved this in 10 seconds in my head. Really doesn't need a 20 minute video.
There we go again with the idea that Mahan will get this wrong. It is such a tiring opening.
Yet true! Everyone named Mahan will get this wrong!
X=2^(4/3)… so what?
x³/⁴ = 2
x = 2⁴/³
John suffers from verbal diarrhea VERBAL DIARRHEA, VERBAL DIARRHEA, VERBAL DIARRHEA 😢😢😢😢😢😢😢😢😢😢THE
I got 2*cubert(2). 😅
I assume you mean 2 * ³√2. This is also correct. If x = 2^(4/3), then we can evaluate (2^4)^(1/3) = 16^(1/3) = 2 * ³√2
@@maxhenderson1890 I know it is, which is why I added the laughing smiley. 😃
@@maxhenderson1890 How can 2 times the cube root of 2 be the same as the cube root of 16? I don't see it.
@@Kleermaker1000Firstly, you could notice that ³√16 = 16⅓ = (2⁴)⅓ = 2^(4/3) = 2 * 2⅓ = 2 * ³√2
Similarly you can solve by doing ³√16 = ³√(4*4) = ³√4 * ³√4 = ³√(2*2) * ³√(2*2) = ³√2 * ³√2 * ³√2 * ³√2 = 2 * ³√2
@@maxhenderson1890 With this part I agree: "Firstly, you could notice that ³√16 = 16⅓ = (2⁴)⅓ = 2^(4/3). But I don't see how "2^(4/3) = 2 * 2⅓", neither how ³√(2*2) * ³√(2*2) = ³√2 * ³√2 * ³√2 * ³√2 = 2 * ³√2. Perhaps my lack of understanding.
Dont invade peoples integers
Good lesson, but is evident that all that manipulation is not necessary. Maths is about making difficult things understandable in an easy way, not the other way around. It seems a show up of manipulation, thing is it's not necessary here. A pupil should be shown immediately to see that x is 2, then briefly explain why, not the other way round. Although I compliment you for your manipulation skills I cannot do for the way you put it unnecessarily.
I agree! His explanations are over-engineered
Wut? x does not equal 2. x = cube root of 16 = 2^(4/3). If you think x = 2, your reasoning is way off.
Qitth westt chemrew yantex we need more and more anmore x yanten righthn allah bmayshr beshta ylkefat aza
Huh?
X^(3/4)=2
X=4
Not even close. How do you get from line 1 (right) to line 2 (false)?!?
Of course we have to raise both sides to ^(4/3) to get the left side exponent to 1, so 2^(4/3)
SORRY, BUT A GRADE 2 STUDENT COULD DO THIS IN UNDER 20 SECONDS.
2nd grade students are barely learning the concept of multiplication. They have no idea what exponents are -- much less, how to deal with fractional exponents (all caps notwithstanding).
@Astrobrant2 Apologize for the caps. I hadn't noticed my keyboard was set on capitals when I posted. My bad.
And you're right. A Second grade student would NOT be expected to know this level of math. Don't know what I was thinking. (Caps intentional this time ).
I'm getting 2*³√2 ≈ 2.5198421