Toughest Question of JEE Advanced 2022 | JEE Advanced 2023 | Arvind Kalia Sir | Vedantu
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- Опубликовано: 3 окт 2024
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🧑🎓 Are you preparing for JEE Advanced 2023 and feeling overwhelmed by the toughest questions that you may encounter on the exam? 😰 In this video, Arvind Kalia sir will guide you through the most challenging problem that was asked in JEE Advanced 2022 exam. 💪 Arvind sir will provide step-by-step solution to this tough question, sharing valuable insights and techniques that you can use to tackle even the most complex problems. 🤔 He'll also suggest strategies for approaching the toughest questions, such as breaking them down into smaller parts and using your reasoning skills to simplify them. 🔍
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Thank you so much for watching the video. We hope, this session will help you get a better understanding of the topic. We would love to get your feedback. Please do comment below in the comment section.
Advanced JEE problems are just like highly theoritical chess openings like Ruy Lopez, Sicilian Najdorf , Grunfeld , or Nimzo Indian defences. U have to know all small nuances. d1d2= b^2 is not enough here, we have to remember about the bisection of angle alpha. Generally students don't go through the trigonometric topic " PROPERTIES OF TRIANGLES ".....JEE ADVANCE exploit this weakness very efficiently.
Seems like a professional chess player you know well about defences as well as openings
@@anonymous.633 No I am a maths teacher and I love to play chess but not a professional. Chess is much harder than Maths. If one knows some opening theory then he/she can enter the middle game without much difficulty.
yeah that's their job by the way they are the toughest lines of queens gmambit declined...🤣
@@saswatasaha9519 There are chess lessons on QGD by Kasparov, Daniel King, Rustom Kashimzanov and many other GM s. This opening is one of the most analysed opening analysed along with Berlin, French, Sicilian Najdorf, Catalan, Petroff , Sicilian Dragon and the King's Indian defence.
@@timirbiswas6785 yeah dude I was just joking
Indians are great to do such great problems at 17-18 of age .
Hats off respect to these guys
Not all... few, very few..like he said 0.4%
Y u acting like a dad?
@@Scofield9975 0.4% of 2,00,000 is 800. Okay ya thats very low lmao
Bahut kam log solve kr pate hai pura bina dekhe baaki sabko solution dekhna padta hai kuch samay baad
No no, there are people like me.
By the way, are you an Indian?
15:37 Thala for a reason
i had done both these results but never saw application in any question till now amazing question
wonderful session every advance aspirant needs to watch this the best maths teacher i have seen . request sir can a new series for advance be there like the unit wise one shot lectures you did for jee mains it will help us a lot
Arvind sir is one of the landed person and very kind hearted and being helpful to all his students
........ thank u so much sir
Awesome qs sir...loved it...and done with the derivation of hyperbola as well...love you sir😊
d1d2= b^2...is given and proved in many books. There are many problems based on this result....just like the parameters of the point of intersections a focal chord with a parabola is related as t1t2= -1, where any point on the parabola is ( at^2 , 2at ).
Sir do you teach maths to bsc students?
Most simplest solution take Point P at vertex. In that case angle alpha will approach to 180 degree and alpha/2 will be 90 degree. and beta*delta= (minor-axis)^2=64/9 answer
but question mentions that alpha is less than pi/2
@@krishnasaraf8828 result will not depend on alpha only. if it were to depend on alpha we will get different answer for different alpha. since no specific alpha is given it can be anything
@@krishnasaraf8828 final result is constant so we can take any alpha. since no specific alpha is given so result is not only depend on alpha. result is dependent on whole quantity so we can take any alpha.
@@pravinkumar4309 it is found that the answer is constant, could have been that answer was something else if alpha greater than pi/2 so to be safe you need to bide by the constraints give in the question
@@krishnasaraf8828 how about alpha -> pi/2 => P -> vertex... in that case everything is still valid. generally we would have gotten undefined form if it was not valid for pi/2.
For Hyperbola done.. Jab bhai ellipse ka kar raha tha tab main vaise sochke hyperbola ka kar raha tha.. Jab bhai chat se pooch raha tha next step tab tak maine hyperbola ka lar diya.. And same chiz dekhke khushi huii...
Love uhh bhaii ❤ kal conic section uda denge ...
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sir hyperbola done
bas line ki equation me x sec theta/a - y tan theta/b = 1 lena tha
thanks bhai iss session ke liye
Super class,.........🎉🎉
Thank you very much sir....... 👍👍👍
Proof for product of perpendicular distance from focus in Hyperbola, ✅️Proved sir, last year when I saw this question but when I tried myself after you explained, I was like how easy it was. You are the best teacher for maths I have got... JAI HO Arvind Sir🙏🙏
The proof for Hyperbolla is done. LOVE YOU SIR.😊
for hyperbola done bhai ....thanks for amazing session mazza aa gya ....Love u bhai ❤❤❤❤❤❤
P point ko x axis pe le to angle alpha ka conflict hai but 2 sec me hi ans aayega
Bhai mja aa gya
For hyperbola Done❤❤
I just fall in love for this channel ❤
Less tricker method but more time taking find s and s' and take p exactly above s and find all other values
Lengthy but answer comes to be 7.95 which gives 7 as answer
Sir i solved this question in just 2 min because I know all imp property of conics
@sirji done
Maza aa gaya
😮😮😮
Sir aj mai solutn nahi dekunga ..beacuse I am not completed hyperbola till now ...after completing ..I hope I am able to solve this...❤️💚 •
Bhai aj dekhle agli bar solve Krna
@एक हितचिंतक kon be tu 🤔
@@user-cn5nn1qj8h mudiji
Abhi tak solution dekha ya nahii....dekh le bhai uska ek viewer badh jayega 😂😂
@@rushivedghodke6336 tu abhyas s kr be
Thank you sir for teaching me
Proof done for hyperbola sir.
amazing question
Done sir, thank you very much
Awesome.liked it.
Prove of hyperbole is done sir
Nah it's not toughest
Simple mathematics I love ❤ it hard question
Maza nhi aaya 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂. But you are always right sir ❤❤😊
Take point P on vertex, alpha=π/2... everything simplifies.. ans=64/9
Answer aa gaya par question mein mentioned hai *alpha < π/2*
Proof for hyperbola done ✅🔥
Sirji aappka shera prove kiya turan jaise hi aapne ellipse ka kr k batatya!!!!!!!!!!!
derivation of formulae are very important
Sir ne bola tha 30 sec mein solve krenge 😢
Proved for hyperbola sir👍
Thanks for providing such problems with their most effective solutions☺️
Thank you Sir
God bless to mera bhai❤️❤️❤️
Arvind ji, this question nedded d.d1 = b.b which is highly un expected of IIT exams. Many students wont even remember such property.
Understanding the structure of a thing is what I personally believe in maths not that learning things from a question.
This q i did in seconds just take point as vertex 😂
Great Sir...
But students cant take 17 mins to solve 1 question like you
Explain bhi Kiya na sath me
NICE QUESTION
No need of result if you use parametric form...folks
Iss question ko mein exam mein 5 minutes mein solve kar diya tha 😂
sir ji done
Should have written minimum distance then one infers perpendicular. Distance cud be be from any point.
bhia me advance k liye registration nhi kr paya 😭😭, mera mains to clear h, ab advance ki date nikl gayi, kya kru, 😭 kaise bhru form
Plzzzz help
Iss question mein alpha = pi rakhdo , s1 p s will become colinear or question easily solve ho jayega under 30 sec without any result
alpha is less than pi/2
Sirji proved
Amazing session Bhai Love u bhai❤️🙏
Can the same work for acoustic ?? Awesome vid btw
Ans is 7 thala for a reason
Answer is 7 thala for a reason
Sir ji dil khush ho gya
Great 👍
Bhai done . Love u bhai for this amazing trick
Haan bhi hyperbola le liye bhi wo relation prove kar liya
Thank you sir 😊
Mene kr lia 5min me mja aagya 😂
thank you sir ❤️
Proof done
I had left the topic hyperbola so can't watch this session 😢💔
Osm 🎉
Good teacher
thanks sir❤🙏
30second = 18 min
Whatever sir has taught...it has gone above my head....
Fun fact-Right now I am in class 10th 😂and I have no intention in doing jee
I was flabbergasted😅
Beauty of direct results
Sir plzz asa hi conic aur straight line ka sara result Jo asa use hota h unka session le lo app
These type of questions are just gimmicks. Knowing this will not make you successful in life. Not knowing it will not make you a failure. It is used to eliminate candiates. This is understandable since the number of seats in IIT are limited.
Sir bhagwan kasam yeh question mein 2 min ke ander kar diya tha😇😇😇
me being in 10th, dropping maths and watching this masterpiece
Skill issues
Skill issues
@@thenotableguy6438 bro im icse rank 5 wtf😂😂
Mene jab ye solve Kara tha mere dimag mien bhi yahi approach aai thi and it took me almost 2-3 mins to solve, mujhe laga ki ye toh assan hai
Ha toh Bhai result pata hoga toh aasaani se banega
Asli khel hai wo result khud se nikalna..i doubt anyone did that in exam and got it right
@@blackholealchemist9493 bhai almost har coaching mien ye result karvaya jaata hai i think usme geometry ka jo use tha usse ye question tough laga ho
I don't think I'll clear IIT JEE if I take the exam now. Things were not so crazy in the 90s.
Obviously
But paper used to be tough then also, no?
@@DoorKaRaahi there was no jee advanced
@@DoorKaRaahi there was a prelims exam (1) and then the main exams (3). The main exams were evaluated only if one cleared the cutoff marks in prelims. But the JEE rank was determined by the main exams marks only.
@@ssarkar2996 ok thanks
Le me who cant even solve board problems😂😂😂
Hamare sir ne to isse 5 min me lallu que. Bolke karwa diya tha 😢
Par apne tho 30 sec mein krne ka kaha tha🙂
30 seconds???you have taken 30 seconds only to read it😂😂
sir ap to youtube ke ad me unacdamy ma ate ho aur solve vedantu ma
kara rahe ho
Sir mane apke name se ek book ke author ka name yaad kr liya Book name jeete Jee Allahabad written by Mamta Kaliya. Jaise Arvind kalia sir Jee advance ko lekar obsessed h according to m Jee equal to Kalia😂😂😂
Sir please try to talk in English, plz help us also😔😔😔
😮lajawab
Kon 2024 me ye video dekha Raha he
bhia me advance k liye registration nhi kr paya 😭😭, mera mains to clear h, ab advance ki date nikl gayi, kya kru, 😭 kaise bhru form
Nice question and good trick and attempt to solve it😎👍
Sir aap check kaise krte ho ki koi question kitne bacho ne shi kiya h
sir i read class 6 my name is yuvraj singh i am 14 years old
Ez question
How did you know 0.4 percent only did first problem ?
iit release data in its press release pdf on result day
Proof for hyperbola done ✅ love you sir ❤
Crackied in 1st attempt. Idea came to me within 10-12 seconds
Just simple geometry
The 0.40% students who got it correct 🧠💯
Proud to say, I m one of those 0.4% :)
Wow buddy. Did you solve like he told. What was your advance rank ?
@@DoorKaRaahi There is so much animosity in ur statement
@@inanis6707 no
Maine to y = 0 pe P baithake solve kr lia 10 second mai 😂
Itna clear drawing banaya ki mujhe dekhte hi result yaad aa gaya😅 aur orally solve ho gya but itna lengthy question statement😢
Bro i need ur help I'm in 12th rn can you guide me how to clear all the upcoming exams with a great marks
And best of luck for your exams
Need to learn concepts thoroughly
😮balle ballleee😶❤️