Simplifying resistor networks | Circuit analysis | Electrical engineering | Khan Academy

Courses on Khan Academy are always 100% free. Start practicing-and saving your progress-now: www.khanacadem...
A systematic approach to simplify a complicated resistor network by looking for series and parallel resistor patterns. Created by Willy McAllister.
Watch the next lesson: www.khanacadem...
Missed the previous lesson? www.khanacadem...
Electrical engineering on Khan Academy: A summary of the math and science preparation that will help you have the best experience with electrical engineering taught on Khan Academy. Become familiar with engineering numbers and notation, and learn about the two most important electrical quantities: current and voltage.
About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan Academy’s Electrical Engineering channel: / channel
Subscribe to Khan Academy: www.youtube.co...

[@nat1XP]

such a great, clearly shown idea to help with curcuits-an always more complicated than necessary part of an interesting subject. thank you!

[@physicsjee-adv5272]

So loving comment

[@thepeakoflife]

This would have helped 4 years ago when I was in college.

[@cullenmiller4627]

How does it feel it’s been 12 years since you have been in college

[@abdulwahidnagi861]

I wish you were my professor
Because ours is horrible and this is so clear and step by step teaching thnks

[@Rawkeeb]

Thanks Khan, that was a great explanation.

[@adilaahsan3491]

Thank you so much sir for explaining precisely

[@Monodori1]

Great finally learning something that i like

[@curtpiazza1688]

Very well explained! 🎉

[@markganus1085]

I waited for this for too long. thanks

[@TheCompton1963]

Great explaination!!!! Thnk u so much for the video.

[@shadiyasamreen5177]

Thank you soo much for this video 😊

[@oliverszegedi7575]

Brilliant video!

[@simplysweetjn]

You are a very cool man

[@Nshiime]

wow,goodness amazing

[@spiralifcrasengan8685]

thanks guys

[@dorfinhorg9458]

Wow amazing

[@aselim20.]

I wrote it.

[@grraul01]

Which Software is this ??

[@akeemwillacy2418]

How did u get three and 2 at the end

[@du42bz]

1+2=3

[@liammchugh9439]

Where did you get 1+3+2?

[@RaisedByOcelots]

Those are the numerators you get when you find the common denominator of 12 and add the fractions together

[@Rick-gd6pe]

Is this accurate?

[@darealslimbacca908]

Where is Khan?

[@BradCozine]

WE are Khan.

[@mariakhan6090]

Yeah, I'm Khan

[@RubberDingBat]

I don't get the common denominator part D:

[@red5t653]

It's 1/12, 1/4, and 1/6, 4 and 6 are factors of 12, so convert 1/4 and 1/6 into twelfths and see what you get.

[@YarblekRW]

Wait... WHAT? so the current is 3 Ohms? I think we need to know the voltage of the source to solve for i

[@Rawkeeb]

He solved for resistance; 3-ohms. Current is measured in Amps. Correct, we need to know Voltage and Resistance in order to solve for 'i' (current).

[@guriyasinghsingh2340]

Jj

[@mariakhan6090]

That wasn't complex :( I was searching for more complex ones they give in high school exams here in India

[@0briang0]

Another example of a teacher passing on the poor habits he was taught. Calculators have had a key marked x^-1 or 1/x forever. Using that key makes parallel resistor calculations trivial:
12 [1/x] + 4 [1/x] + 6 [1/x] = [1/x].
The calculation even looks the same as the parallel resistor formula

[@ThePDog74]

+Brian Greenfield What do you mean by poor habits? This is how it's done without a calculator so I don't see a poor habit.

[@0briang0]

Calculating resistors in parallel using the product-over-sum formula given in the video is a poor habit.
Other than classroom problems where the answer is often a nice round number, nobody solves resistors in parallel without a calculator.

[@srikarsaireddy8845]

. . in this ved he's explaining the basics of calculating the total resistance . . if you already know that . . why on earth did you watch it . . rather you could have taken ur calculator "on which you perfectly know how to do it" . . by the comment you made . . evidently you made a fool out of yourself

[@luongmaihunggia]

You still haven't find the current and you didn't give us the voltage value