Ohmite, a resistor manufacturer and Friend of CircuitBread, is supporting this tutorial, making it possible for us to make more content! We not only appreciate their help, we think they're a great resource for seeing what these electronic components look like in real life (and buying them, of course!) We recommend you go to their site at www.ohmite.com/power-resistors/ to see what some of these resistors and other electronic components look like in real life.
Thanks Yazeed! We had a bit of a hiccup this summer in consistency but I think we should be back to regular now. I'm also hoping to finish our Circuits 101 series before the end of the semester. But we have some other series in the works (plus our client work that pays the bills) that may distract us. Fingers crossed!
that was great! explained well with 'its a beautiful day' jejeje i watched always your video because i understand well the way you speak, continue making videos.
TS ~ 13:00, he says finding voltage divider value between R1 & R2 is difficult. It's easy - add R1 & R2 values. R1 + R2 = Rt then I = V/R , you're using Rt here. Since series circuit, current ( I ) is same for both resistors. So ... then take I * R1 = V to find voltage drop across R1.
Thanks Hassan! The developers are currently working on that because, I agree, the navigation is messy at the moment. I'm hoping it'll be done by early January.
at time 7:33 when you added that other resistor, that part of the circuit is no longer a series. it has become a parallel branch because if you send current through the circuit, the current will have two paths to flow..
I admit, I was a bit concerned saying that - it introduces a bit of confusion. But the two parallel resistors (TOGETHER) are in series with the top resistor. That's what I was trying to say and I'm sorry if it wasn't as clear as I was hoping it would be.
This series and channel are great, definitely appreciated. Can you think of any books that would cover a similar level of topics as this Circuits 101 series, that would have a good selection of practice exercises as well? Would be helpful to jam stuff into my brain I think.
hi I have a question and my only learning platform is youtube so ill be appreciated if you help me with this how does ampere works if I have an LED strip that needs 12v and 2 amps and I have an output of 12v but the ampere is like 18 does LED strip only uses 2 amps needed or it will burn?
Led burns when the voltage exceeds the give voltage of the led I mean think of it like a flow of water through a pipe where the pressure is voltage and the flow rate is current, a diode accepts the needed amps of current, even if it's high it doesn't matter because amps does not damage the led but if voltage is high the the led could burn , if the voltage is low the intensity of light would be less so do keep in mind that all leds except some work with 5 volt dc and amps depend on how much led you have connected if the leds are more you would need more amps and do keep in mind that the voltage should be 5v
Hi Mahdi, in summary of what Flurican said - as long as you match the voltage requirements and can provide at least how many amps it needs, you're fine. So, in your case, it's fine.
You are absolutely correct - if you invert the 1/R(eq) from what I put down, you get what you have: (R1 x R2) / (R1 +R2) It can be very confusing, at least for me. Thank you!
You should have explained why the resistance in parallel is always lower.. and why THAT reason will fry the lowest path of resistance over time and why that's stupid to begin with etc etc
Yeah, we wonder sometimes how in-depth we get in these tutorials. Sometimes I feel like I focus too much on small unimportant details and other times I worry that they're too high level. I think that's going to be an ever moving target...
Haha! I do love my Macbook. I got it four years ago refurbished and I use it *all the time* and I'm impressed by the build quality. Fortunately, I don't do anything too demanding with it, because it was so expensive I'm not looking forward to replacing it.
Ohmite, a resistor manufacturer and Friend of CircuitBread, is supporting this tutorial, making it possible for us to make more content! We not only appreciate their help, we think they're a great resource for seeing what these electronic components look like in real life (and buying them, of course!) We recommend you go to their site at www.ohmite.com/power-resistors/ to see what some of these resistors and other electronic components look like in real life.
How can one Man be so good teaching 🥺
Thanks Alot was really helpful
As an overthinker, this helps me: For series add resistance and for parallel add coductance. Conductance is the inverse of resistance.
It's absolutely helpful especially for freshman year students. I like the way you explain the subjects. Keep up this amazing content. 👏🏼👏🏼👍🏼
Thanks Yazeed! We had a bit of a hiccup this summer in consistency but I think we should be back to regular now. I'm also hoping to finish our Circuits 101 series before the end of the semester. But we have some other series in the works (plus our client work that pays the bills) that may distract us. Fingers crossed!
@@CircuitBread All the best🤞🏼.
Plzz keep making videos it's very helpful for my studies ❤ all the way from India
Honestly, you're second to none
Extremely helpful amd explanatory...
if my lab instructor was half as competent as you i''d be in heaven
Right !!
Great explanation 👌
Thank you so much for creating this!
this video is exactly what i was searching for! thank u very much
that was great! explained well with 'its a beautiful day' jejeje i watched always your video because i understand well the way you speak, continue making videos.
Thank you, you did a great explanation here. Please continue 🙏
TS ~ 13:00, he says finding voltage divider value between R1 & R2 is difficult. It's easy -
add R1 & R2 values. R1 + R2 = Rt
then I = V/R , you're using Rt here.
Since series circuit, current ( I ) is same for both resistors.
So ... then take I * R1 = V to find voltage drop across R1.
Thank you so much for this helpful video sir.
This guy's voice is crazy soothing.....
A small recommendation, you should add a series feature in the website. It's really hard to navigate in thousands of tutorials.
Thanks Hassan! The developers are currently working on that because, I agree, the navigation is messy at the moment. I'm hoping it'll be done by early January.
I like the way you correct yourself after the video 😅💔
Thank you so much it’s really helpful ♥️
at time 7:33 when you added that other resistor, that part of the circuit is no longer a series. it has become a parallel branch because if you send current through the circuit, the current will have two paths to flow..
I admit, I was a bit concerned saying that - it introduces a bit of confusion. But the two parallel resistors (TOGETHER) are in series with the top resistor. That's what I was trying to say and I'm sorry if it wasn't as clear as I was hoping it would be.
@@CircuitBread no! Don't be sorry... It wasn't confusing to me because I fully understand series, parallel and series-parallel circuits...
@@james77011 nonchalant
Amazing sir
This series and channel are great, definitely appreciated. Can you think of any books that would cover a similar level of topics as this Circuits 101 series, that would have a good selection of practice exercises as well? Would be helpful to jam stuff into my brain I think.
actually, you are incredible for teaching
great informational video :)
awesome
Thanks a lot for the detailed video. Thanks a millioin
My pleasure, glad it was helpful!
thank you
hi I have a question and my only learning platform is youtube so ill be appreciated if you help me with this how does ampere works if I have an LED strip that needs 12v and 2 amps and I have an output of 12v but the ampere is like 18 does LED strip only uses 2 amps needed or it will burn?
Led burns when the voltage exceeds the give voltage of the led
I mean think of it like a flow of water through a pipe where the pressure is voltage and the flow rate is current, a diode accepts the needed amps of current, even if it's high it doesn't matter because amps does not damage the led but if voltage is high the the led could burn , if the voltage is low the intensity of light would be less so do keep in mind that all leds except some work with 5 volt dc and amps depend on how much led you have connected if the leds are more you would need more amps and do keep in mind that the voltage should be 5v
Hi Mahdi, in summary of what Flurican said - as long as you match the voltage requirements and can provide at least how many amps it needs, you're fine. So, in your case, it's fine.
@@flurican3485 thank you man big help.
@@CircuitBread thanks that really helped me out.
17:09 sir I think you are wrong about calculating the equivalent resistance in parallel R(eq) = (R1 x R2) / (R1 +R2) but your explanation was awesome
You are absolutely correct - if you invert the 1/R(eq) from what I put down, you get what you have: (R1 x R2) / (R1 +R2) It can be very confusing, at least for me. Thank you!
@@CircuitBread I get it now thank you very much sir I appreciate your work
You didn't show how to invert r one or r two
You should have explained why the resistance in parallel is always lower.. and why THAT reason will fry the lowest path of resistance over time and why that's stupid to begin with etc etc
Yeah, we wonder sometimes how in-depth we get in these tutorials. Sometimes I feel like I focus too much on small unimportant details and other times I worry that they're too high level. I think that's going to be an ever moving target...
4:24 meshes? Or super meshes 🤓
10:02 volteg hahah
edit: nvm
😂
🧡🧡
can you give that macbook to me plz..😋
Haha! I do love my Macbook. I got it four years ago refurbished and I use it *all the time* and I'm impressed by the build quality. Fortunately, I don't do anything too demanding with it, because it was so expensive I'm not looking forward to replacing it.