Always look for substitutions to make the problem solution easier. Substitute x=y+5/2 into the given equation and rearrange to: (y+5/2)^4-(y-5/2)^4=2*4[y^3(5/2)+y(5/2)^3]=0 Divide by 8(5/2)y to obtain y^2+(5/2)^2=0, which has roots y=±i5/2. Also y=0 is a root. Thus, x=y+5/2=(5±5i)/2 or x=5/2
2.5; (5+5i)/2; (5-5i)/2
Always look for substitutions to make the problem solution easier. Substitute x=y+5/2 into the given equation and rearrange to:
(y+5/2)^4-(y-5/2)^4=2*4[y^3(5/2)+y(5/2)^3]=0
Divide by 8(5/2)y to obtain y^2+(5/2)^2=0, which has roots y=±i5/2. Also y=0 is a root.
Thus, x=y+5/2=(5±5i)/2 or x=5/2
Well done.
Thanks so much!
Xpand
Why bother with complex numbers? Are real numbers not enough?
Bro, 2x² - 10x +25 = 0 or 25-10x = 0, because a * 0 = 0🤓🤓🤓