For #1, since all of the answer choices are equivalent to each other, pick any of the answer choices and graph it into desmos. Then graph the line y=48(27). This is because 48 needs to be increased by a factor of 27 and is our goal. The x value of the intersection point should be the value of c, which is gonna be 6.
I appreciate this video very much. I'm confused about the last problem. I typed the problem into desmos, kept p=1 and saw the solutions on the graph and their sum was 8. I see that I can calculate p by solving 8-p=20/3, but I don't know why that equation works? Why do you subtract p from the sum of solutions when p is 1 in order to get the sum of solutions when p = 4? Thank you.
If you're trying to solve the problem in Desmos what you would do is graph the function and then you need the sum of all the solutions (x-ints) to add up to 20/3. So you have to adjust the p value (slider) until you get them all to equal 20/3. " I see that I can calculate p by solving 8-p=20/3," No the equation should be 8 - p/3 = 20/3 "Why do you subtract p from the sum of solutions when p is 1" This method of setting up and solving the equation is different from trying to use Desmos to solve. Here I find the sum of solutions from each individual ()'s and add them together to = 20/3. The middle () is -3 + 3 = 0. The last () is 8 (comes from the formula -b/a). The first () is -p/3 which you get by setting = 0 & solving for x. P should not be = 1, p is what you are solving for to make that equation true, which ends up being 4.
@@jwmathtutoring Your explanation helped me so much. Not only in answering the question, but in understanding how confused I was. Thank you! It makes so much sense to me now.
@@jwmathtutoring Also, am I correct that you so far haven't posted a video for Bluebook Practice test 6? I can find it on other channels, but I was wondering because I prefer your style of teaching. Thank u.
That is correct. I've been so busy with tutoring this summer I haven't been able to record as many videos as I wanted to. I have one more video on June 2024 problems and then after that, I plan to record PT 6.
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For #1, since all of the answer choices are equivalent to each other, pick any of the answer choices and graph it into desmos.
Then graph the line y=48(27). This is because 48 needs to be increased by a factor of 27 and is our goal.
The x value of the intersection point should be the value of c, which is gonna be 6.
Yes, this is a good alternate way to find the value of c.
Your a lifesaver, I had no idea you could just add a slider for question 6 that made that problem 100x easier thank you so much
Thanks.
I appreciate this video very much. I'm confused about the last problem. I typed the problem into desmos, kept p=1 and saw the solutions on the graph and their sum was 8. I see that I can calculate p by solving 8-p=20/3, but I don't know why that equation works? Why do you subtract p from the sum of solutions when p is 1 in order to get the sum of solutions when p = 4? Thank you.
If you're trying to solve the problem in Desmos what you would do is graph the function and then you need the sum of all the solutions (x-ints) to add up to 20/3. So you have to adjust the p value (slider) until you get them all to equal 20/3.
" I see that I can calculate p by solving 8-p=20/3,"
No the equation should be 8 - p/3 = 20/3
"Why do you subtract p from the sum of solutions when p is 1"
This method of setting up and solving the equation is different from trying to use Desmos to solve. Here I find the sum of solutions from each individual ()'s and add them together to = 20/3. The middle () is -3 + 3 = 0. The last () is 8 (comes from the formula -b/a). The first () is -p/3 which you get by setting = 0 & solving for x. P should not be = 1, p is what you are solving for to make that equation true, which ends up being 4.
@@jwmathtutoring Your explanation helped me so much. Not only in answering the question, but in understanding how confused I was. Thank you! It makes so much sense to me now.
@@jwmathtutoring Also, am I correct that you so far haven't posted a video for Bluebook Practice test 6? I can find it on other channels, but I was wondering because I prefer your style of teaching. Thank u.
That is correct. I've been so busy with tutoring this summer I haven't been able to record as many videos as I wanted to. I have one more video on June 2024 problems and then after that, I plan to record PT 6.
Hi, just wanted to let you know that the solutions to Bluebook Practice Test 6 are now posted for 3 Math Modules (1, 2A, 2B).