Day 5: Solving Walmart SQL Interview Questions | 100 Days Challenge

Welcome to Day 5 of my 100 Days Challenge! Today, we're diving into Walmart SQL interview questions to help you ace your next tech interview. Join me as I walk through each problem step-by-step, providing detailed explanations and practical tips. Don't forget to like, subscribe, and hit the bell icon to stay updated with daily challenges!
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[@anirbanbiswas7624]

with cte as(select *,sum(sales_amount) over(partition by store_name rows between unbounded preceding and current row)as running_sales,
lag(sales_amount,1,sales_amount) over(partition by store_name)as prev_month_sales from sales)
select *,round((sales_amount-prev_month_sales)/prev_month_sales*100,2) as growth_rate from cte
i think null value on the 1st row or in the other cases for the first month we may assume the initial value as the value instead of null & to get that i have used--- lag(sales_amount,1,sales_amount)

[@Chathur732]

select *,
case when lagging is not null then round(((sales_amount - lagging)/lagging) * 100,2) else 0 end as growth_ratio
from(
select * ,sum(sales_amount) over(partition by store_name order by sale_date) as sum,
lag(sales_amount) over(partition by store_name order by store_name) as lagging
from sales) as Subquery

[@devarajululanka6427]

SOLUTION IN SQL SERVER :
with cte as (
select store_name,DATEPART (month,sale_date) as sale_month,sum(sales_amount) as total_sale_amount
from sales
group by store_name,DATEPART (month,sale_date)
),
cte2 as (select *,
sum(total_sale_amount) over (partition by store_name order by total_sale_amount ) as running_sale_amount,
lag(total_sale_amount,1) over (partition by store_name order by total_sale_amount ) as previous_sale_amount
from cte
)
select *, (total_sale_amount - previous_sale_amount)/previous_sale_amount*100 as diff
from cte2;

[@omkarshinde8154]

Hey will u explain the way of approch step when,what,how to analyse what is to use..I am facing dificulty to analyse the same

[@zero_analyst]

Sure!