React Interview Questions | JavaScript Interview Questions | React Interview Experience

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  • Опубликовано: 3 фев 2023
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Комментарии • 69

  • @giannizamora7247
    @giannizamora7247 4 месяца назад +1

    The final challenge of grabbing data, displaying, pagination, ect is probably one of the closest challenges you'll have as a dev especially if you have several years of exp. I appreciate the consice approach of adding pagination functionality, there were different places while coding along where I had a different idea but ended up taking up more time to solve. Thank you

  • @RavindraSingh-lp9pl
    @RavindraSingh-lp9pl 9 месяцев назад +7

    @its coding Doctor...we need more such projects in React. I checked your channel has just 2 projects in React please build few more. I like your teaching style.

  • @vishwasgupta605
    @vishwasgupta605 Год назад +13

    It was helpful please keep doing !
    my solution for que3
    const person = {
    name: "ram",
    age: 30,
    };
    const arr = [];
    for (let value in person) {
    arr.push([value, person[value]]);
    }
    console.log(arr);

    • @itscodingdoctor
      @itscodingdoctor  Год назад

      Awesome

    • @imam.k8114
      @imam.k8114 10 месяцев назад

      for in loop will also include properties from object.prototype chain which may not be desirable

  • @HarshitGupta-sm9cf
    @HarshitGupta-sm9cf 10 месяцев назад +1

    Great work sir, appreciate

  • @somnathtiwari5593
    @somnathtiwari5593 Год назад +11

    Thank You so much for this, I have tried learning Pagination from other youtubers too but was never able to keep the logic to write the code behind it in my mind but and you took one step at a time with explaining every step was remarkable. I dont think I will ever forget how this works now.

    • @itscodingdoctor
      @itscodingdoctor  Год назад +1

      Glad to hear 😊. Keep learning

    • @berndeveloper
      @berndeveloper 8 месяцев назад

      @@itscodingdoctor ​ It's important to know that this is not the best approach to deal with pagination, it needs to be handled on the server side, not in front. This approach can be used when the total number of items is relatively small and can be easily handled by the client.

    • @jaia466
      @jaia466 7 месяцев назад

      ​@@berndeveloperim with this too. Imagine having to paginate a data set of thousands of data on client. This should be handled on the server. What i do is just i only pass limit and offsets from the client to my backend to grab all necessary data per page

  • @140_nihalborkar3
    @140_nihalborkar3 11 месяцев назад +1

    amazing🎉

  • @AjayYadav-zp7yl
    @AjayYadav-zp7yl Год назад +2

    Good work bro......keep it up👍

  • @PrasathGururmoorthy
    @PrasathGururmoorthy Год назад +2

    Excellent questions and coding challenge. Coding covers many concepts.

    • @itscodingdoctor
      @itscodingdoctor  Год назад

      Thanks 🙏

    • @itscodingdoctor
      @itscodingdoctor  Год назад

      Find more MNC Interview Experiences: ruclips.net/p/PLGZJDzu5NntRmgwjCg0OwFpt9yHh68Muc

  • @aveesp1
    @aveesp1 Год назад +3

    var person = {
    firstname: "john",
    lastname: 'doe',
    age: 30
    };
    const getDetails = (obj) => {
    let arr = [];
    for(let i in obj){
    arr.push([i, obj[i]]);
    }
    return arr;
    }
    getDetails(person);
    //output as follow
    [
    [
    "firstname",
    "john"
    ],
    [
    "lastname",
    "doe"
    ],
    [
    "age",
    30
    ]
    ]

  • @do_u_dsa
    @do_u_dsa Год назад

    Quality content, good job!

  • @arijitroy5695
    @arijitroy5695 Год назад +10

    Ok. I have an little improvment idea which is some times I have seen, something in pagination like this 1 | 2 | 3 | 4 | .......| 9 | 10 | 11 | 12 . when pagination number rapidly grows and you don't have option to select number of pages. So, could you please demonstrate how to do that?

    • @itscodingdoctor
      @itscodingdoctor  Год назад +3

      Sure, that's a great idea. I'll try to upload it soon.

  • @savatabachhav7593
    @savatabachhav7593 5 месяцев назад +1

    Thank you so much for this. We want more such videos.

    • @itscodingdoctor
      @itscodingdoctor  28 дней назад

      More to come!
      You can check the MNC interview experience playlist on this channel

  • @meenatchieel7730
    @meenatchieel7730 Месяц назад +1

    Its great..Really Thanks a lot for duch wonderfull real time problem solving

  • @MohitKumar-in3we
    @MohitKumar-in3we 7 месяцев назад +1

    Worth Varma Worthuu.... mindblowing........

  • @user-ec3ik2ll3u
    @user-ec3ik2ll3u 9 месяцев назад +2

    Question 3
    const person={
    name:"Ram",
    age:30
    }
    const Newarr=[]
    for(let item in person){
    Newarr.push([item,person[item]])
    }

  • @sanddeep66666
    @sanddeep66666 Год назад +1

    3rd ways to solve this.
    const person = {
    name: "ram",
    age: 30,
    };
    const output = [];
    for (let key in person) {
    output.push([key, person[key]]);
    }
    console.log(output);

  • @Shivamtech30
    @Shivamtech30 16 часов назад

    let persne={
    name:"shivam",
    age:27
    }
    let array =[]
    let output = Object.entries(persne).map((items,id)=>{
    array.push(items)
    })
    console.log("mdbvsjd",array)

  • @InDCoOk84
    @InDCoOk84 Год назад +2

    Very helpfull 🔥🔥

  • @ankitgiri6874
    @ankitgiri6874 Год назад +1

    amazing bro

  • @user-dl4hx1oe3u
    @user-dl4hx1oe3u 8 месяцев назад +1

    Helpful

  • @shubhamdas6519
    @shubhamdas6519 8 месяцев назад +1

    thanks a lot sir....

  • @maheshappaji1273
    @maheshappaji1273 Год назад

    thank you👍👍👍

  • @decryptbykd6714
    @decryptbykd6714 11 месяцев назад

    const persons = {
    name: "Ram",
    age: "30"
    };
    let output = [];
    for (let key in persons) {
    output.push([key, persons[key]]);
    }
    console.log(output);

  • @ashundale
    @ashundale 9 месяцев назад +1

    const person={
    name: "ram",
    age: 50,
    }
    const array = [];
    for(const key in person) {
    array.push([key, person[key]]);}
    array;

  • @ayushporwal5950
    @ayushporwal5950 10 месяцев назад

    span as buttons?

  • @BhavinKalsariya-yc6gm
    @BhavinKalsariya-yc6gm 9 месяцев назад +1

    const person = {name:"Ram", age:"30"};
    // OUTPUT
    // [
    // ['name', 'Ram'],
    // ['age', '30']
    // ]
    let arr = [];
    for(const key in person){
    arr.push([key, person[key]])
    }

  • @sarathnath4991
    @sarathnath4991 5 месяцев назад

    12:00 how that we can achieve by JavaScript. Bcz sometimes anchor tag to append through loop rendered as string in html page. One more q, if its cause csr then why Amazon using this approach and what are the solutions to prevent this? Pls reply

  • @ShubhamSharma-vk9iq
    @ShubhamSharma-vk9iq 9 месяцев назад +1

    const getObjectEntries = (obj) => {
    let arr = [];
    for (let key in obj) {
    arr.push([key, person[key]]);
    }
    return arr;
    };

  • @hazemkhaled9416
    @hazemkhaled9416 4 месяца назад

    The video is greate I actually learned some valuable things here
    but wanted to point out that I think there will be a bug in the code if the last page has different no of elements than other pages
    For Example:
    if there where 197 items last page will contain only 7 items not 10
    the bug bec indexOfLastTodo= currentPage * todosPerPage will be equal to 199 but which is wrong since the last element index will be 196
    when you try to slice the todos using the indexOfLastTodo in the last page it will cause an error as there is no item of index 199

    • @itscodingdoctor
      @itscodingdoctor  Месяц назад

      I haven't tested it. I tried to create a happy flow.
      There might be more bugs/improvement space in my code (i kept it really simple to achieve the basic functionality)

  • @dukesoni5477
    @dukesoni5477 9 месяцев назад

    interview for candidate with how much years of experience

  • @shankar1050
    @shankar1050 7 месяцев назад

    the method you used to fill the array with page numbers is not good. simply you can map an index with index+1.
    but you wrote complex code(for beginners it is complex)

    • @itscodingdoctor
      @itscodingdoctor  28 дней назад

      One problem has many solutions. Hardly matters (for small things) , but if you know a better solution use it by all means.

  • @nitishgupta8393
    @nitishgupta8393 Год назад +2

    const output = Object.entries(person).map(([key, val])=> {
    return [key, val]
    })

  • @arijitroy5695
    @arijitroy5695 Год назад +11

    Are questions really for Experienced interview. I am telling because These are really very basic and easy questions for experienced. isn't it right??

  • @ShreyanshMehta-ov8ze
    @ShreyanshMehta-ov8ze 8 месяцев назад

    how many years of experience is required to crack this types of interviews?

  • @mkfacts3250
    @mkfacts3250 8 месяцев назад

    how much salary was offered to you after this interview??

    • @itscodingdoctor
      @itscodingdoctor  8 месяцев назад

      I had a counter offer as well. So it won't be same for everyone.

  • @Bankey_Bihari_Sarkar_Vrindavan

    const person = {
    name : "Akshay",
    age : 22
    }
    let arr = [];
    for(let x in person) {
    arr.push([x, person[x]]);
    }
    console.log(arr, Object.entries(person));

  • @wij8044
    @wij8044 9 месяцев назад

    All these ways to avoid using TypeScript 🤦‍♂️

    • @itscodingdoctor
      @itscodingdoctor  8 месяцев назад

      Typescript is gaining a lots of popularity and is highly recommended. In this interview didn't consider it though.

  • @rajesh.geesala7565
    @rajesh.geesala7565 7 месяцев назад +1

    thanks

  • @shubhambarore5548
    @shubhambarore5548 4 месяца назад +1

    const getObjectEntries = (obj) => Object.keys(obj).map((key) => [key, obj[key]]);

  • @sagarninave
    @sagarninave 8 месяцев назад +1

    const user = {
    firstName:"sagar",
    lastName:"ninave",
    age:27
    }
    const result = Object.keys(user).reduce((acc, curr) => {
    const value = [curr, user[curr]]
    return [...acc, value]
    }, [])
    console.log( result);