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Actually iam a UG physics student... So In your playlist not all but many of the topics are very helpful... And i gonna download the app... Your way of teaching is very good sir❤❤
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I was measuring with an oscilator and the part output I was measuring included a resistor, a coil and a capacitor. when I calculated my theoritical values my Q factor came out at 0.033 but through the V=f(frequency) graph(and I was using peak values so I maltiplied my max voltage value with 0.707 to get the rms and I found my BW at around 4khz and my Fr was 1592. anyways using a formula I found out that my Q factor using the graphs BW came out at almost 0.4. A significant amount more that expected. I did not account for the phase though. should I or it doesnt matter in this kind of scenario? and if it does matter do I take in mind only the output resistor for the impedance or do I take the whole sum of the circuit? I am confused help
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But then it is a rlc ckt so why doesn't everything is in parallel...I mean why aren't there three branches one with resistance one with inductor and one with capacitor
sir i think total impedence should increase with freyuency on x axis as total impedence is a square function of frequency z=r*r+(2*3.14*f*L)(2*3.14*f*L)/r
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Bcoz at resonance, the circuit is purely resistive.There are no reactances in the circuit(neither capacitive nor reactive) And impedance=(resistance) +or- i(reactance) So if reactance is zero imaginary part is zero.
At resonance what happens is , inductive and capacitive reactances ie XL and XC are equal. Hence, it is observed that the phase angle between current and voltage turns out to be zero. (In a resistance circuit, the phase angle is always zero). Hence the circuit is simply resistive at resonance condition. Now when the complex equation is obtained, there only resistive ie, the real part exists
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my left earphone really understood it
Your explanation of this topic was flawless my good sir, thank you.
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From Egypt,thanks 💙💙😍
thank u so much sir
excellent,you are really genius,indian teacher are real gem,iam from bangladesh,keep me in your prayer
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I am from morroco.. Thank you teacher 😉
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Here to just get quick notes for an assignment I need to submit tomorrow but I haven't attended a single class of this unit😂
Sems are near thanks for these lessons
Excellent explanations. Can u explain the derivation of current and Q factor and BW of parallel resonance circuit.
What is y1 here can u explain in hindi to me
@@ankitSingh-tu5on admittance
Clear and understandable! Thanks Sir!
Awesome experience of learning under your explanation
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Saaalaa itna mast btaya kabhi nhi bhul Sakta Banda....
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From Iraq Thank you so much Teacher
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Nice explanation sir
Thanku sir..... 🎍💞💞💕👌
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Actually iam a UG physics student...
So In your playlist not all but many of the topics are very helpful...
And i gonna download the app... Your way of teaching is very good sir❤❤
Nice teach sir .......👌👌👌👌
In hole series missed this paper video 🥲 finally it's here
nice sir ,, bhut hiii sundarrrrrrrrrrrrrrrr
Well understood Iam
Thanks from canada
Thanks Sir
Beautiful....ThanQ very much sir...!
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In this vedio 5:27 who gone from bottom in y1 equation
Thank you SIR
Babbal sir !!!
I was measuring with an oscilator and the part output I was measuring included a resistor, a coil and a capacitor. when I calculated my theoritical values my Q factor came out at 0.033 but through the V=f(frequency) graph(and I was using peak values so I maltiplied my max voltage value with 0.707 to get the rms and I found my BW at around 4khz and my Fr was 1592. anyways using a formula I found out that my Q factor using the graphs BW came out at almost 0.4. A significant amount more that expected. I did not account for the phase though. should I or it doesnt matter in this kind of scenario? and if it does matter do I take in mind only the output resistor for the impedance or do I take the whole sum of the circuit? I am confused help
খুব ভালো
amazing sir
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most under rated teacher on youtube
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Sir what about phase angle
superb
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explain how a parralel tuned LC Eddie Nketiah's second goal for Arsenal. Super talent. achieves selectivity
Series or parallel ka formula same hota hai kya?
how do you elimate the -j at 6:07 sir?
padika rathuku uhmmj^2= 1
Sir in the expression for Zmax, the XL term remains. So how can we say that the circuit is purely resistive and has no reactances?
thank you soooooooooooooooooooooooooooo much sir... subscribed :)
What is y1 here can u explain me in hindi
Can you also discuss about variable C and L at resonance condition? T.Y.
With oné video class l subscribéd your chànnél
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make a video series resonance
Why did u multiplied and divided by the conjugated at 4:38???
sir how to find time constant for rlc circuit pls help me thanks
resistor inductor k saath series mein kion lga hai .parallel kion ni hai.?????
muhammad shaheer because the resistor shown is the internal resistance of the practical inductor
But then it is a rlc ckt so why doesn't everything is in parallel...I mean why aren't there three branches one with resistance one with inductor and one with capacitor
sir i think total impedence should increase with freyuency on x axis as total impedence is a square function of frequency
z=r*r+(2*3.14*f*L)(2*3.14*f*L)/r
Why this R + jXl. Is used why not R+Xl
VIKAS DHANDA
you should using rectangular because (+)
what is j?
j is same as i which is use in complex number called iota its value is √-1
nice
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So many ads in between.
Meanwhile me to ad "Roti khake jayega? Jaa."
why most of the videos have the audio channel issue 😫
where is the audio??
Sir explain the term "j"? Why the term j is eliminated?
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explain how a parralel tuned LC circuit achieves selectivity
Hi friends in this Video we going to watch 9 ads ,why
Sir Hindi mae samjha ogae to Jada acha rahega
No volume please
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Are your teachers busy? Look for androidcircuitsolver on google
Not good explanation but it's ok
Why at resonance imaginary part will zero
Bcoz at resonance, the circuit is purely resistive.There are no reactances in the circuit(neither capacitive nor reactive)
And impedance=(resistance) +or- i(reactance)
So if reactance is zero imaginary part is zero.
At resonance what happens is , inductive and capacitive reactances ie XL and XC are equal. Hence, it is observed that the phase angle between current and voltage turns out to be zero. (In a resistance circuit, the phase angle is always zero). Hence the circuit is simply resistive at resonance condition. Now when the complex equation is obtained, there only resistive ie, the real part exists
And normally the total impedance is
Z = R +/- iXL / iXC
So if the circuit is purely resistive then the part with i vanishes
Sound nhi hai q
❤️
Why did u take j
Sir ho sake to Hindi me
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is this the part of jee mains?
Jyada view ayege
Can't you clearly explain it. Without any mistakes
YOU CHANGE YOUR SPEAKER, SO NOT GOOD.
14 minute ki video m 6 advertisement daal rakhe h
Kya chahte ho
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explain how a parralel tuned LC circuit achieves selectivity
explain how a parralel tuned LC circuit achieves selectivity