I actually use this to explain the dynamics of forklift operations to practicing operators and how it works in the real world. Most forklift operators are not instructed on this basic principle of force and distance relative to the load and fulcrum of a forklift and how they determine the relative stability of the forklift when operating. Too bad more operators don't understand this because most forklift accidents and injuries result from a failed set up of the pick and placement of the loads when analyzed using these determinants.
For F4, shouldn't we only count the vertical component of the force when calculating the moment? Isn't the horizontal force zero because it is parallel? Thank you
Hey Abdulaziz, did you watch to the end of the video? If you want to use the distance of 0.3m (from A to the point on the wrench where the force is acting) then yes, you will only consider the vertical component of the force for the moment calculation, because it is perpendicular to the 0.3m line that happens to be horizontal. You don't actually need to pick a line for d that actually touches the object, it needs to touch the line of action of the force. The only point on the line of action of the force that touches the wrench was the one at the end, mentioned above. In the video, I also identify a point on the line of action of the force such that the position vector d is perpendicular to it, and then we need to take the full magnitude of the force vector. Don't just jump to only taking the vertical component without thinking why. For the calculation, the force and the position vector must be perpendicular, and so if the position vector that you are using is not purely horizontal, then the components of your force that you take will not be purely vertical. I do go over both ways that I just mentioned in the video. Check it out again and maybe it will make more sense now!
line of action is mentioned here: ruclips.net/video/smoPlJiLmac/видео.html - it just means the line of the action = the line on which the force acts = the direction in which the force acts = the direction of the force. Given that the position and rotation of the cartesian system on which we measure is arbitrary - we can put it wherever we want, it means that when a force is not parallel with 0x or 0y axes, when its at an angle, then it can be decomposed in the component forces which are parallel with 0x and 0y axes. So our non parallel force is just a composition of this axis based vectors by the parallelogram rule.
+Parth Sas there is a good discussion of the difference here: www.quora.com/What-is-the-difference-between-torque-and-moment-3 but pretty much at this level you don't need to worry about it.
+Sean roze Moment is directly proportional to the perpendicular distance from the line of action of the applied force to the point where the moment is occurring. It's easy if the force is applied at 90 degrees to the object, because if you increase the distance x2, the moment will increase x2. It's not as apparent when the force is not applied at 90 degrees, but if you extend the line of action, then find the perpendicular distance to the point from that line, you can find moment. If the distance was increased or decreased, the moment would also increase or decrease linearly with the change in distance.
I actually use this to explain the dynamics of forklift operations to practicing operators and how it works in the real world. Most forklift operators are not instructed on this basic principle of force and distance relative to the load and fulcrum of a forklift and how they determine the relative stability of the forklift when operating. Too bad more operators don't understand this because most forklift accidents and injuries result from a failed set up of the pick and placement of the loads when analyzed using these determinants.
Glad to hear it!! Thanks for letting me know.
Congrats bro, first helpful vid I've seen with zero dislikes
Hey nice! I didn't even realise :)
Thank you
You’re welcome!!
youuu are great.
A moment is a short period of time
Lol
what program do you use for doing your sketches?
thanks
can u plz explain line of action in more convenient way i shall feel grateful to u 4 that.....
For F4, shouldn't we only count the vertical component of the force when calculating the moment? Isn't the horizontal force zero because it is parallel? Thank you
Hey Abdulaziz, did you watch to the end of the video? If you want to use the distance of 0.3m (from A to the point on the wrench where the force is acting) then yes, you will only consider the vertical component of the force for the moment calculation, because it is perpendicular to the 0.3m line that happens to be horizontal. You don't actually need to pick a line for d that actually touches the object, it needs to touch the line of action of the force. The only point on the line of action of the force that touches the wrench was the one at the end, mentioned above. In the video, I also identify a point on the line of action of the force such that the position vector d is perpendicular to it, and then we need to take the full magnitude of the force vector. Don't just jump to only taking the vertical component without thinking why. For the calculation, the force and the position vector must be perpendicular, and so if the position vector that you are using is not purely horizontal, then the components of your force that you take will not be purely vertical. I do go over both ways that I just mentioned in the video. Check it out again and maybe it will make more sense now!
Thanks!
thank u sir u are rock...
plz explain line of action to me that's a initial concept that often confuse me although thats been implied often here
line of action is mentioned here: ruclips.net/video/smoPlJiLmac/видео.html - it just means the line of the action = the line on which the force acts = the direction in which the force acts = the direction of the force. Given that the position and rotation of the cartesian system on which we measure is arbitrary - we can put it wherever we want, it means that when a force is not parallel with 0x or 0y axes, when its at an angle, then it can be decomposed in the component forces which are parallel with 0x and 0y axes. So our non parallel force is just a composition of this axis based vectors by the parallelogram rule.
Whats a moment
can you please tell me the difference between torque and moment?
+Parth Sas there is a good discussion of the difference here: www.quora.com/What-is-the-difference-between-torque-and-moment-3 but pretty much at this level you don't need to worry about it.
these sorts of initial concepts often confuse me and that really sucks so plz get me helped
why do we multiply by 50N instead of 100N at 9:30?
cuz the force is 100sin30 on y axis
Why is the distance 3m in f2?
Oh okay i get, .15*2=3
what is directly proportional?? in that??
+Sean roze Moment is directly proportional to the perpendicular distance from the line of action of the applied force to the point where the moment is occurring. It's easy if the force is applied at 90 degrees to the object, because if you increase the distance x2, the moment will increase x2. It's not as apparent when the force is not applied at 90 degrees, but if you extend the line of action, then find the perpendicular distance to the point from that line, you can find moment. If the distance was increased or decreased, the moment would also increase or decrease linearly with the change in distance.
thank you so much! your video help me pass my 2nd exams xd!