Remainder Estimate for the Integral Test

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  • Опубликовано: 13 дек 2024

Комментарии • 38

  • @bpjones2
    @bpjones2 9 лет назад +39

    Why is it that you plug in 1/ln(10) when the tenth term is at n=11 not 10, when starting at n=2?

  • @Blam0492
    @Blam0492 14 лет назад +3

    PatrickJMT you are THE LIFE SAVER! You have no idea how much I have suffered from my professor's nonsensical lectures and explanations. THANK YOU for finally clearing the clouds!

  • @dorood
    @dorood 14 лет назад +3

    these integration test vids should be part of your series playlist! it would make it easier to find them :)

  • @akshaybodla163
    @akshaybodla163 6 лет назад +1

    Helping calc people ten years later...thanks so much brother!

  • @B.A.Gondal
    @B.A.Gondal 11 лет назад +3

    WoW....Math videos in 1440P....way to go Patrick!!!

  • @patrickjmt
    @patrickjmt  14 лет назад +1

    @dorood yea, i know. it seems like keeping things organized takes more time than actually making the vids!! and if there is one thing i hate to do, it is to organize things.... zzzzzzzzzzzzzz.........

  • @JohnFRobinson
    @JohnFRobinson 11 лет назад +2

    You're awesome, for a left-handed dude... Thanks for the help!

  • @kenikozo
    @kenikozo 12 лет назад

    @patrickJMT Well if you really hate organizing, I seriously don't get how your teaching method is SO organized.. and precise!

  • @HeatherRoseMusician
    @HeatherRoseMusician 11 лет назад

    Saving my butt again Patrick! Thanks for all your videos. They're TRULY appreciated! You're a great teacher!

  • @sgwyoshi
    @sgwyoshi 14 лет назад +1

    I have an exam on series later tonight
    thanks for the help :D

  • @tamerachristopher6002
    @tamerachristopher6002 8 лет назад

    Thank you Patrick!!!! I Aced my exam because of you!!! Much Love :)

  • @pierspolkiss
    @pierspolkiss 10 лет назад +1

    you are saving my life everyday. THANK YOU SO MUCH

  • @TanksPokemon
    @TanksPokemon 12 лет назад

    Did you just skip the steps when you make sure the function is positive and deceasing or do you not need it for the remainder estimate?

  • @whatitdoes
    @whatitdoes 14 лет назад

    wow...u r a neat freak!! lol i dunno how u write it soo clean and neat. thanks for the vids

  • @fakecrime
    @fakecrime 11 лет назад

    Is it 11 to infinity or 12 to infinity? And do you happen to have an example explaining the remainder estimate for the comparison tests?

  • @aznlalaland
    @aznlalaland 13 лет назад

    Please do a video about lower integrals and upper integrals. I know the definitions but the definitions are very contradictory!

  • @sergekamga915
    @sergekamga915 4 года назад

    What paper and eraser do you use? Are you using a document camera?

    • @jcarlos4458
      @jcarlos4458 3 года назад

      That is a whiteboard with expo pens

  • @patrickjmt
    @patrickjmt  16 лет назад

    no worries... someone asked for it, and i can not remember if it was you or not.
    in any event, hope it helps

  • @patrickjmt
    @patrickjmt  12 лет назад

    @kenikozo well, that is different :) i figure you all are all internet search savvy by now!

  • @Rickmand
    @Rickmand 16 лет назад

    Shouldnt we integrate with 12 as the lower bound instead, since the series starts at 2?

  • @donovanvaughan6053
    @donovanvaughan6053 6 лет назад

    Why is there a + c at the end of the first integral despite having been integrated between specified bounds?

  • @Bakugantsuvai1
    @Bakugantsuvai1 11 лет назад

    Hey if I have a question on a final calc 2 exam that says: Use the Remainder Estimate for the Intergral test to determine how much terms are needed to get around 3 digits of accuracy would 0.001 be my R sub n? Anyone who can answer this question can battle me on Showdown.

  • @patrickjmt
    @patrickjmt  16 лет назад

    it is very clever!!

  • @jcarlos4458
    @jcarlos4458 3 года назад

    Anyone know why he didn't update the limits for his definite integral when he did the u-sub where u=lnx? So the new limits would have been ln(2) and ln(t)

  • @ueiwqoak
    @ueiwqoak 12 лет назад

    wait, if your using the first 10 terms in the series which starts at 2, shouldn't the integral be from 12 to infinity?

  • @kalef1234
    @kalef1234 9 лет назад

    that's pretty neat!

  • @TheCoconutBlues
    @TheCoconutBlues 11 лет назад

    In a way this is basically Riemann sums for series, huh.
    Very helpful video as always.

  • @GizmosShow
    @GizmosShow 12 лет назад +1

    11 to infinity. 2, 3,...10, 11. That would be 10 terms. But ya, I was gonna say the same thing. But with 11.

  • @adisaini6347
    @adisaini6347 3 года назад

    If we are using the first 10 terms then don't you think that upper limit should 11 not 10.

  • @xbllethality4588
    @xbllethality4588 11 лет назад

    240p, 360p, 1080p
    Well...That escalated quickly.

  • @tarrook10
    @tarrook10 11 лет назад

    thanks

  • @gregschuster6272
    @gregschuster6272 11 лет назад

    Thank you for being left handed

  • @VanNoortMusic
    @VanNoortMusic 13 лет назад

    So instead of having ln(x) squared, we're gonna have YOU squared :P lol

  • @miguelaphan58
    @miguelaphan58 5 лет назад

    .....in most universities...this explanation is missing...

  • @kpatel7176
    @kpatel7176 11 лет назад

    i'll organize it for u...

  • @akiv3854
    @akiv3854 11 лет назад

    why dont you appoint someone trustworthy to do it for you?

  • @SrgntLoveGaming
    @SrgntLoveGaming 7 лет назад +1

    Why is it that you plug in 1/ln(10) when the tenth term is at n=11 not 10, when starting at n=2?