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Mam in reversing the digit question you are using left shift right,so while using left shift we will be appending 0 to the vacant bit right,so how the shifted bit get appending back ,its possible only in bit rotation right
Mam share the eda link for reference
Mam in reversing the digit question you are using left shift right,so while using left shift we will be appending 0 to the vacant bit right,so how the shifted bit get appending back ,its possible only in bit rotation right
Mam share the eda link for reference