How To Calculate The Fractional Volume Submerged & The Density of an Object In Two Fluids
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- Опубликовано: 13 ноя 2017
- This physics video tutorial explains how to calculate the fractional volume of partially submerged objects and the density of an object in two fluids (oil and water) using archimedes principle, free body diagrams, and the upward buoyant force exerted by the weight of the displaced molecules in the surrounding fluid.
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It's what I'm looking for😭😭😭 Thank youuuu so much!!! May God bless you a lot! You saved me
you're saving my life every day of my college!!!!
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Still saving my life today!! -Civil Eng Student
U made it so simple for me ! Thanks soooo much!
Such a perfect explanation ✌️.
helped me so much, thank you
Dude, you are like superhuman. Thanks for the lessons
youtube legend
Well explained.
YOU ARE THE BEST THANK YOU SO MUCH
This guy is basically my 'Mathematics for civil engineering' lecturer at this point
ahem and my mechanical engineering lecturer
perfectly explained
Had little knowledge about it.... thank you for your help sir... Much love from Zambia (Africa)
@@robertowisconetti2732 yes, 'Africa' does
Excellent !!!!!
Thank you ...
man I love you
So helpful 😎😎
It took me 2 hours thinking how to solve my homework , then this video saved my day😇😇😇
Am from Ethiopia dude you're sooooooooo great
Dear Sir............Example Problem : One hydraulic cylinder, the end is connected to the Threaded rod so that it can be rotated. Cylinders with a bore size of 18 mm, 10 mm rod and a stroke of 300 mm single acting in a condition that is filled with oil. If the cylinder is rotated 10 mm.
a. How to calculate it
b. What is the gauge pressure
You cleared my 4 day confusion.........
A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?
For any hollow object what density should i consider??
My first time being lost watching these videos
Where did you get the 1, that you subtracted to the fraction of iceberg beneath under the surface of the water?
cuz the total of iceberg is 1 and a part of it(that is above) is smaller and a decimal
it is kinda like finding out how many pieces did u get of one pie?
you gotta take the total as 1 and the part taken by u is 1/4 or 0.25
Hope you understood!👍👍👍
THE GOAT
Thank You very much!! If you were sitting in front of me right now I might have hugged you really hard.
I love you ❤️
Hey how do you derive (p_f)(V_s) = (p_o)(V_o) on 6:13 ??
Thank you...but you say Pf is the density of the fluid but its not p its rho. It's a Greek letter. P usually stands for Pressure in Physics. if i'm wrong correct me.
You are correct. Thank you
it does not matter!! as long as he uses Pf as the density... Of The fluid!! but for him pf is like rho 😊😁😁
Yeah you are correct
for question 3, Don't we need to convert the height in cm to m?
Yes because it is fraction then
It cancel out
You saved my exam, and im not even English XD
7:15
For that I used
X = density of the metal
Xkg/m^3
----- = .7
13’600 kg/m^3
Xkg/m^3 = (.7) (13’600 kg/m^3)
Is that correct?
ya you are correct you can take 70% as ratio between the density of the body to liquid
Which app have you used for making this video? Which writing app?
its paint from windows its free and good
Does partially submerged and floating has a difference
I'm confused cuz Archimedes priciple says upthrust of a partially submerged object= weight of the liquid displaced but law of flotation says upthrst =weight of the object
Look I also had the exact same doubt but I cleared it by giving away my 3 hours to this and I have concluded to a point so I am giving a disclaimer that I am not sure if it's the answer to your q but this was the most I could have thought of
I agree that Archimedes Principle says that upthrust = weight of liquid displaced but the law of floatation says that if a body is floating in any liquid then the upthrust is equal as the weight of the body and it's true because the body can only float and stay still at that point if the force acting on it becoz of liquid (upthrust) = the (mg) or weight of that body and I guess you might be thinking that what if it is completely submerged in the liquid then the upthrust will be different and it's correct but the thing is that it's density is constant and everytime you will place it in a liquid that you were putting into it then it everytime gets partially submerged in it and therefore it everytime displaces the same weight of water and it everytime gets the same upthrust which is equal to the weight of body (becoz it is still at one place and the net force acting on it is zero)
Hope I helped 🙂🙂
@@somethingabouttech thank youuu!
@@TS-vh9rs it's my pleasure bro I am so happy that I made someone happy 😊😊
@@somethingabouttechi have the same question.... can u explain it kinda easily than the previous maybe as I can't still understand plsssss
How did u get that 10m³😢
What if I only have the mass of the object and the density of the liquid
Hi why 1-0.895 to get the fraction about
How come that the volume of a wooden cube is Ah? isn't it s3?
I love u
at which class do you guys study this concept in? like in school or in uni or what?
tenth grade actually here in my country 😫😫😫
great
👏👏👏
Machallah
Does W mean weight of object?
Yes
In example 3.
how come that the length turned 10cm in oil, and 5 cm in water? Can someone enlighten me?
thank you!
Its showing the length of the block submerged in the water and oil.
Its just a part of the question, there's no need to worry the exam will provide all these measurements for calculations.
On the last problem wouldnt you have to convert cm to m to get the correct answer?
yes, he made a mistake
doesn t need to because the ratio of the unit will cancle itself, therefore give you the same answer.
What's the mean of F?
Failure
fluid probably
You won't believe but this actually came to an exam of 8th class.
which country bruh? china?!!
Anybody watching it in 2025???😅
Its still 2024, I ll come back next year if I still need to review about archimedes principle
Sir, I have doubt in 1st question you solved.
You had taken submerged volume of object upon total volume of object which is equal to 0.894 g/cm3.
Then what is the value of total volume (Vo)
assume total volume as 1cubic meter then you can get Vs=0.894 and volume of not submerged part becomes 1-0.894=0.106