Worked example: motion problems (with definite integrals) | AP Calculus AB | Khan Academy
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- Опубликовано: 22 авг 2024
- What can you say about the velocity and position of a particle given its acceleration. Created by Sal Khan.
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Yay more physics videos. I'm glad the physics section is getting some love.
I didn't found this enjoyable only but I did find this very useful also. A lot. Thank you very much sir
everything that is related with physics is not enjoyable
Not even a minute in and this man saved me 10 hours of madness if i had tried to figure this out myself
Thank you so much! For the first time, these kind of problems are starting to make sense.
Very cool relation between maths and physics...
Schrodinger's equation please !!!
Thanks so much, your videos make so much sense!!! Excellent teacher!!!
I have a question: how does one determine the original function of s(t) that you use the derrivitives of? I ask this because in all the example questions I did they always say that s(t) is given by (lets just say) t^2 -5t - 3 .
How does one determine the function that gives you the position?(when you dont have the function that gives v(t) or a(t)
you use anti-derivatives, if none is given then you can't really find it.
thanks simple and good
I appreciate your existance
its very function thanks
Succinct and clear !
It was very helpful. Thanks a lot.
love videos like this one
So dope; first time I was able to get it. Thanks so much!
What if we take derivative of the acceleration? What will I get?
I think you would get the velocity at one specific point. Because that's what a derivative tells you, the rate of change at a singular point.
@@jcfilms2641 No man, you will get jerk which is the third derivative.
Slay
Help meee I need to answer this problem:
When a train is traveling along a straight track at 4.0m/s, it begins to accelerate at a= 32/v^5 where v is in m/s. Determine its (1) velocity and (2) position, 6seconds after the acceleration.
But he didn't mention the constants
PLEASE PLEASE take the time to write well. Your "t"s turned into plus signs and your 'd's turned into 0s. Its hard to digest visually