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5x-y=42x+y=105x+2x-y+y=4+107x=14x=25(2)-y=410-y=4-y=-6y=62(2)+y=104+y=10y=6(x, y)=(2, 6) ❤
😮😮😮!!!!!!!¡!!!!!!!!
Good❤❤❤❤
After x=2 at 0.48 by elimination, substitute for x into either equation and solve for y. No need for a second elimination process. 🇦🇺
Thank you for the sentiments. This depends on what your professor was testing; if the instructions are ’use elimination method’ then don’t mix with substitution, just eliminate one variable to solve for the other in turns
Nhi hua
5x-y=4
2x+y=10
5x+2x-y+y=4+10
7x=14
x=2
5(2)-y=4
10-y=4
-y=-6
y=6
2(2)+y=10
4+y=10
y=6
(x, y)=(2, 6) ❤
😮😮😮!!!!!!!¡!!!!!!!!
Good❤❤❤❤
After x=2 at 0.48 by elimination, substitute for x into either equation and solve for y. No need for a second elimination process. 🇦🇺
Thank you for the sentiments. This depends on what your professor was testing; if the instructions are ’use elimination method’ then don’t mix with substitution, just eliminate one variable to solve for the other in turns
Nhi hua