I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor
Bend pulley is used to change the direction of conveyor belt in gravity take up system. Take up pulley is used to provide necessary tension on conveyor belt to run without slippage smoothly.
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
The specific energy consumption for a conveyor system can be calculated using the following equation: SEC=P/Q⋅V where: SEC is the specific energy consumption in kWh/ton/km P is the power consumption in kW Q is the material flow rate in tons per hour (Mt/Hr) V is the belt speed in meters per second (m/s) The power consumption (P) can be calculated using the following equation: P=T⋅L⋅1000/3600⋅η where: T is the tension in Newtons L is the belt length in meters η is the overall efficiency of the conveyor system (usually assumed to be around 90-95%) The tension (T) can be calculated using the following equation: T=2⋅S⋅L⋅cos(α)/g+V2/R where: S is the belt cross-sectional area in square meters α is the trough angle in radians g is the acceleration due to gravity (approximately 9.81 m/s²) R is the radius of curvature of the conveyor belt in meters (assumed to be the radius of the pulley) The belt cross-sectional area (S) can be calculated using the following equation: S=B⋅(H+h)/2 where: B is the belt width in meters H is the height of the material in the trough in meters h is the surcharge height in meters Given your inputs: B=1,200 mm = 1.2 m H=150/2 mm = 0.075 m (assuming the lump size is evenly distributed in the trough) ℎ=25 mm = 0.025 m α=30 degrees = π/6 radians V=2.5 m/s Q varies from 3,500 to 4,000 Mt/Hr (use the average for simplicity) L=5 km = 5,000 m η=0.92 (assuming overall efficiency is 92%) Using these values, you can calculate SEC in kWh/ton/km for the given conditions.
Really good sir
Thanks for this🙏🙏
Thank you ❤️❤️ for your appreciation.
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor
Best sir
Good information ki
Sir what is function of bend pulley?? Take-up pulley???
Bend pulley is used to change the direction of conveyor belt in gravity take up system.
Take up pulley is used to provide necessary tension on conveyor belt to run without slippage smoothly.
Resilance coupling spring size code
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
I have found some calculations perhaps it will definitely help you.
The specific energy consumption for a conveyor system can be calculated using the following equation:
SEC=P/Q⋅V
where:
SEC is the specific energy consumption in kWh/ton/km
P is the power consumption in kW
Q is the material flow rate in tons per hour (Mt/Hr)
V is the belt speed in meters per second (m/s)
The power consumption (P) can be calculated using the following equation:
P=T⋅L⋅1000/3600⋅η
where:
T is the tension in Newtons
L is the belt length in meters
η is the overall efficiency of the conveyor system (usually assumed to be around 90-95%)
The tension (T) can be calculated using the following equation:
T=2⋅S⋅L⋅cos(α)/g+V2/R
where:
S is the belt cross-sectional area in square meters
α is the trough angle in radians
g is the acceleration due to gravity (approximately 9.81 m/s²)
R is the radius of curvature of the conveyor belt in meters (assumed to be the radius of the pulley)
The belt cross-sectional area (S) can be calculated using the following equation:
S=B⋅(H+h)/2
where:
B is the belt width in meters
H is the height of the material in the trough in meters
h is the surcharge height in meters
Given your inputs:
B=1,200 mm = 1.2 m
H=150/2 mm = 0.075 m (assuming the lump size is evenly distributed in the trough)
ℎ=25 mm = 0.025 m
α=30 degrees = π/6 radians
V=2.5 m/s
Q varies from 3,500 to 4,000 Mt/Hr (use the average for simplicity)
L=5 km = 5,000 m
η=0.92 (assuming overall efficiency is 92%)
Using these values, you can calculate SEC in kWh/ton/km for the given conditions.