Does this imply that the idea of deconstructive interference is somewhat a misnomer? Since it seems to deconstruct the signal wave in its forward progress, but it does seem to constructively interfere through back propagation intensity? Would that be correct or am I missing something?
I think if the same principle of light splitting was IF spectroscopy made by nasa to scan the moon and moving part was moving by one driver (like a piezoelectric spiker ) to change angle of light. I like to see some video about sun spectrum drive type because I don’t understand how work if have protection filters in top ( is not possible to see full spectrum)
You state the beam is split into 2 equal parts. What beam splitter did you use? I have yet to find a beam splitter that produces only 2 beams. Beam splitters produce what are called ghost images. The simulation looks nice but not accurate.
@@HuygensOptics The animation is inaccurate because it states the beam splitter splits the beam into 2 equal parts. I have been unable to find a beam splitter that produces only 2 beams. For the animation to be accurate it would have to include the additional beams. You are misleading the viewer.
@@HuygensOptics Perhaps a warning to the viewers would be appropriate. The statement 2 equal beams is not accurate. Not everyone is aware of the "ghost beams". see ruclips.net/video/4y8dOqZ0--Y/видео.html it may help explain my point. The simulation you present can not be accurate because it does not show where all the photons are going.
@@QuantumLab-bt7yq As you can see, the beam splitter featured in the simulation is a plate beam splitter, not a cube beam splitter. A good plate beam splitter is thin and has a semi reflective coating on one side and an anti-reflection coating on the other. They generally do not exhibit ghost reflections of significant intensity.
@@HuygensOptics i have a plate splitter. It produces 1 transmitted beam and 2 reflected beams. The second reflected beam is referred to as a ghost beam. Your video is great. Just to be accurate. A beam splitter does not split a beam into 2 equal beams.
I am not sure this really demonstrates where the energy goes. Two photons can cancel each other out but for some reason, when this happens, the energy really just ends up in a different direction?
Why did the change in mirror position by a quarter wavelength turn the wave intensity 90° clockwise? Would a half wavelength move it 180°? Would a 1/8th wavelength turn it 45°? Or does the intensity just raise and lower between the two rotational positions as it phases back and forth? I'd love to see an animation where you take samples of the mirrors position at intervals over a whole wavelength so I could see how the intensity evolves.
In reflection, the wave covers a change in distance twice, resulting in a net phase shift of 1/2 lambda (or 180 degrees), which is the difference between being in phase or in "anti phase".
It went back to the source? In the case of an interference not in an interferometer, where does it go? For example in the case of an RF beam steering antenna array?
I like to think of it as the ability to do one type of work becomes the ability to do a different type of work. Just like shg lasers, the different wavelengths react with different elements but the energy is still there albeit after losses.
I tried to follow along with the simulation on Python, but when I run it, I get much less distinction between the peaks of the intensity profile... I tried cchanging the parameter "source_fequency_scale" to a number smaller than 1, but it still really doesn't look as nicely contrasty as yours... The image you provided in the description is the destructive interference case, right? Anyway, how do you save the video from Python? And how do you add the optical elements overlay? Thank you
Wait, this is light cancelling out light? I though photons reached their destination instantly? If they cancel each other out they remove energy from the universe...
just use miniforge/mamba to install as was suggested in the README.md file and it will automatically install the correct versions. You should use separate installation commands for numpy, opencv, matplotlib and cupy. Each command looking somenting like this: mamba install numpy. Hope this helps.
You don't understand the question .When two single wave interfere to nothing - there is no energy in this point - and then waves go from this null point to again get full energy .
@@mltonsorangestapler interference means out of phase, the energy is still there, it doesn’t just go back to the source it is simply redistributed, same with EM waves
You are on a roll!
These simulations are awesome, and you make great cases for displaying interesting phenomenon.
This is the same reason why there are less losses in lenses and optics with antireflective coatings
Exactly, it's just interference. Summing up all the waves, the reflected wave goes to zero and the transmitted to 100%
Awesome video! And cool usage of the simulation code. I spent my weekend doing simulations too, really fascinating stuff!!
😊👍👍🐈🐾🐾
Indeed that code is really awesome.
Where is this code???
@@cylosgarage It can be found at the @DiffractionLimited channel as a link in the description of the last couple of videos.
@@HuygensOptics sweet thank you!!
This is the best visual explanation of the E&M going on here I've ever seen. Well done
Love these wave visualizations
So energy is always conserved!
Yes, unlimited shelf life!
Thank you! This really cleared things up for me!
Een van mijn favoriete Nederlandse RUclipsrs 😁 ps: ik hoop dat je ooit eens een lezing of iets komt geven op de TU Delft
The only kind of Shorts I'll allow in my subscription feed.
Where did it go?
Exactly, he didn't even say it 😭
back towards the source
Does this imply that the idea of deconstructive interference is somewhat a misnomer? Since it seems to deconstruct the signal wave in its forward progress, but it does seem to constructively interfere through back propagation intensity?
Would that be correct or am I missing something?
Yes indeed. Destructive interference is actually the result of the intensity routed elsewhere, due to the phase relationships present in the field.
@@HuygensOpticsis this also the same mechanism that allows a laser to create a feedback loop with itself?
If there is destructive interference somewhere, there will also be constructive interference somewhere nearby.
@@mrmotl1 no, that process is called stimulated emission, basically it is the emission of an amount of energy in phase with the existing field.
@@HuygensOptics Thanks, now I've learned something today already.
In ham radio we have a measurement gage for reflected power
Nice! Of course this is true, but it is something else to see this explained by these clear simulations. It really adds another layer of depth!
Cool, can you do one where you show how holography works?
Does anything truly cancel to zero in the universe?
Fascinating
Btw the reason why this happens is because one wave is phase shifted by 180° with respect to the other
Just think of the intensity as a probability likelihood. Energy doesn't go away, it just doesn't go where the probability is near zero.
Thanks
Great explanation & visuals.
Unrelated high shower thought: How deep is a sea of light?
Waves are co-mingled, the emitance is light shadow and refraction.
I think if the same principle of light splitting was IF spectroscopy made by nasa to scan the moon and moving part was moving by one driver (like a piezoelectric spiker ) to change angle of light.
I like to see some video about sun spectrum drive type because I don’t understand how work if have protection filters in top ( is not possible to see full spectrum)
Give your source a gaussian distribution so it looks nicer
What about the case where two coherent and 180° phase locked sources are fired directly at each other (rather than using a beam splitter)?
Fired in the same direction or shooting at each other?
@@JCAtkeson3 I was thinking "at each other" but coincident at a focal point on a surface is also a valid query.
Ok so the energy is still going somewhere, so it's not really destructive interference? I feel like I need more explanation on this phenomenon.
So it gets reflected? makes sense.
So this is how beam forming is done? By destructively choosing where the energy gets focused?
You state the beam is split into 2 equal parts. What beam splitter did you use? I have yet to find a beam splitter that produces only 2 beams. Beam splitters produce what are called ghost images. The simulation looks nice but not accurate.
I used a simulated beam spitter. You cannot find them in regular shops. ;-)
@@HuygensOptics The animation is inaccurate because it states the beam splitter splits the beam into 2 equal parts. I have been unable to find a beam splitter that produces only 2 beams. For the animation to be accurate it would have to include the additional beams. You are misleading the viewer.
@@HuygensOptics Perhaps a warning to the viewers would be appropriate. The statement 2 equal beams is not accurate. Not everyone is aware of the "ghost beams". see ruclips.net/video/4y8dOqZ0--Y/видео.html it may help explain my point. The simulation you present can not be accurate because it does not show where all the photons are going.
@@QuantumLab-bt7yq As you can see, the beam splitter featured in the simulation is a plate beam splitter, not a cube beam splitter. A good plate beam splitter is thin and has a semi reflective coating on one side and an anti-reflection coating on the other. They generally do not exhibit ghost reflections of significant intensity.
@@HuygensOptics i have a plate splitter. It produces 1 transmitted beam and 2 reflected beams. The second reflected beam is referred to as a ghost beam. Your video is great. Just to be accurate. A beam splitter does not split a beam into 2 equal beams.
I am not sure this really demonstrates where the energy goes. Two photons can cancel each other out but for some reason, when this happens, the energy really just ends up in a different direction?
Which sofware do you use to create these animations, sir.❤
See video description
optics, like antennas are black magic
Back to sender😂
Why did the change in mirror position by a quarter wavelength turn the wave intensity 90° clockwise? Would a half wavelength move it 180°? Would a 1/8th wavelength turn it 45°? Or does the intensity just raise and lower between the two rotational positions as it phases back and forth?
I'd love to see an animation where you take samples of the mirrors position at intervals over a whole wavelength so I could see how the intensity evolves.
In reflection, the wave covers a change in distance twice, resulting in a net phase shift of 1/2 lambda (or 180 degrees), which is the difference between being in phase or in "anti phase".
It went back to the source? In the case of an interference not in an interferometer, where does it go? For example in the case of an RF beam steering antenna array?
How’s that work with the double slit experiment, are you saying the energy is the same both sides of the slits ?
The ability to do work can quickly become the ability to do nothing.
Burnouts be like:
I like to think of it as the ability to do one type of work becomes the ability to do a different type of work. Just like shg lasers, the different wavelengths react with different elements but the energy is still there albeit after losses.
It is not obvious where it went, could you elaborate on that?
See video description for more info.
I tried to follow along with the simulation on Python, but when I run it, I get much less distinction between the peaks of the intensity profile... I tried cchanging the parameter "source_fequency_scale" to a number smaller than 1, but it still really doesn't look as nicely contrasty as yours... The image you provided in the description is the destructive interference case, right? Anyway, how do you save the video from Python? And how do you add the optical elements overlay?
Thank you
It goes backwards in the direction of the incident beam?
where does the energy go during then after cancellation ?
And if there is no beam splitter? And mirrors? And where photons go? o)
how? they reflect off of each other?
Wait, this is light cancelling out light?
I though photons reached their destination instantly? If they cancel each other out they remove energy from the universe...
So it just went up
Does this mean if light interferences destructively, somewhere else the light interferes constructively?
Yes always, it is essentially how waves work.
What if u have identical beam from left , can the splitter cause perfect cancellation interfernce ?
It’s just like noise canceling headphones, just bc you don’t hear the noise doesn’t mean it isn’t still there.
true spiritual successor to Leeuwenhoek!
would it be fair to say that the parts between mirror and beam splitter are standing waves?
Yes, I guess so, If you look at the amplitude of the beams after they have reflected of the mirrors you see exactly that: a standing wave pattern.
Does it turn to heat?
Energy is redistributed😊
Quanta cannot be destroyed, it's always somewhere :)
Is that open source code? If so, where can I find it?
see video description
Ah, did not know that shorts even have a description. Nice of DiffractionLimited to publish the code! Thank you for the answer!@@HuygensOptics
Could you elaborate which python pagkage versions (numpy, cupy) you used@@HuygensOptics ? On my machine the code throws errors.
just use miniforge/mamba to install as was suggested in the README.md file and it will automatically install the correct versions. You should use separate installation commands for numpy, opencv, matplotlib and cupy. Each command looking somenting like this: mamba install numpy. Hope this helps.
Dutch accents are cool. 👍
Ah yes, i know some of those words.
LIGO detector
Algorithm, are you tracking this? More of this, you can cut the "💯 Respect!" memes, I'll be fine.
and yet youll still bang on about fauxtons
What form is that energy? Kinetic? How is it measured?
clear, the wave reads the sign " wrong way go back!"
Nederlands accent gedetecteerd
You don't understand the question .When two single wave interfere to nothing - there is no energy in this point - and then waves go from this null point to again get full energy .
Ik zie het niet. Gaarne aangeven waar de energie heen gaat.
Zie de video description voor meer info.
back to the SOURCE
no
@@TheBigFatVladimir yes
@@mltonsorangestapler interference means out of phase, the energy is still there, it doesn’t just go back to the source it is simply redistributed, same with EM waves