I should have looked at the comments sooner lol I was like wait a second...2(0) is 0...and 3(1) is 3 soooo...how the heck did he get 2? Glad I wasn't the only one, phew!
if you understand these fundamentals, everything just becomes harder algebraically. Understand these concepts and you wont have to worry about the prep
Don't get me wrong, I truly appreciate the presenter's ability to greatly simplify the concept but the first answer is a profound arithmetic blunder that does not build confidence, leaving possibly subsequent problems in question.
1:19 the linear combination should be [3 6 31], no? That aside, thank you for the video because you explain it way better than my uni lecture and textbook combined...
Just to clarify, b is a linear combination of v1 and v2 because there is a solution, and we know there is only one solution because there are no free variables in the reduced echelon form?
hello, In the second example, how did you come up with the scalars -1,0 and 1/2?? even the first example why 2 and 3? i did note you made an error on the first example the resulting vector should be 3,6,31
I just picked arbitrary numbers. Any choice of three scalars would give a "linear combination" of those vectors. And, yes, there is an arithmetic error in that example (there are several other comments pointing that out).
1:36 2u+3v=(3,6,31)
Thanks, was wondering the same
I should have looked at the comments sooner lol I was like wait a second...2(0) is 0...and 3(1) is 3 soooo...how the heck did he get 2? Glad I wasn't the only one, phew!
Thank god I thought I was tripping
Thanks!
Thought so
Did in seven minutes what my prof spent an hour explaining
And I understood this faster - thank
:v
Love your math videos; it would be awesome if you can upload more of them with hard problems to prep for tests
You had made a mistake in 2u + 3v
if you understand these fundamentals, everything just becomes harder algebraically. Understand these concepts and you wont have to worry about the prep
shouldn't the first problem result in [3 6 31] not [2 6 31]?
Don't get me wrong, I truly appreciate the presenter's ability to greatly simplify the concept but the first answer is a profound arithmetic blunder that does not build confidence, leaving possibly subsequent problems in question.
Yes it’s [3,6,31]
yeah that was just a mistake
1:19 the linear combination should be [3 6 31], no?
That aside, thank you for the video because you explain it way better than my uni lecture and textbook combined...
Thank you!
I was going crazy trying to figure out what I was doing wrong.
@@RobertManzano same here
Just to clarify,
b is a linear combination of v1 and v2 because there is a solution, and we know there is only one solution because there are no free variables in the reduced echelon form?
Excellent intro to Vector Equations
You teach soo well
This video is so helpful
thanks for your videos sir
it was so helpful
Helpful like all the videos in your L.A. playlist. All hail King James!
thanks for the video . please can someone explain to me how the scalars are choosen pleasee
great series...really appreciate you taking the time to do this...now maybe one on complex variables??
pivotal step of the solution is omitted in the vector equations part.
What does it mean by "no pivot"?
very helpful . Upload more please.
You teavh very amzingly keep it up
thanks. your explanation was very good!
thanks you for your help 🙏
Man you are a legend
Amazing
Thank you, great explanation.
excellent content
very clear, thank you
so beautifully put man thank you
hello, In the second example, how did you come up with the scalars -1,0 and 1/2??
even the first example why 2 and 3? i did note you made an error on the first example the resulting vector should be 3,6,31
I just picked arbitrary numbers. Any choice of three scalars would give a "linear combination" of those vectors. And, yes, there is an arithmetic error in that example (there are several other comments pointing that out).
Thanks!
Thank you for these videos! Very helpful.
you the man!
U should break things down
why is it vector (2, 6, 31)? Is that supposed to be vector (3, 6, 31). Thanks
It's just a mistake. The correct answer is (3, 6, 31) :)
Hi, can you show how you got the equation to be reduced row echelon form?
This video explains the row-reduction process: ruclips.net/video/72ysuwtYA0c/видео.html
I just spent an entire hour trying to figure out why that was 2 instead of 3 D:
Shit happens though. Great video!
thank you jaes
there is a mistake in the first example
could you clarify the pivot in the last column to determine if there are solutions or not? Does that mean non-zero entires?
I recommend watching Lecture 5 (ruclips.net/video/kDbBTFvQgig/видео.html) where I explain this concept.
@@HamblinMathdo you have complete series on youtube? The playlist I used skipped lecture 4 and 5. Ok I will watch them. Great videos btw loved it!
much helpful
This made things click, thank you ^_^
thx
thanks
ok but why do you teach better than my prof?
I don’t get it. Doesn’t that give you 3 equations and 2 variables? Sure, there is A solution, but also others.
What part of the video are you asking about?
👍
صياف محمد خلف
You teavh very amzingly keep it up