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Why in RHS of imaginary part it c4 is not R4 .....plz ..tel me..
you saved my life thanks Bro
I can't realate how R4 is on the right side of imaginary part?
c4 will be there
In right side of imaginary part it is c4 not R4 , I Think
Yes....
I was stuck there too
its c4 in imaginary part right?
yes its c4
Excellent bro👍
C4 is in series with R4
Thank you sir❤
Bhai mere thodi video bdi bna le km se km pura explain to kra kro last dimag khrab hojata hai ye last me C4 ki jgh R4 kha se agya
Yeh j or omega kuu liya ?? Z1 MAIN
Good explanation tq sir
Negative sign kaise huwa sir.
j2 = -1
J square = -1
Thank you ❤❤❤❤❤❤❤
Why minus
Nice
Thanks
Bass R4 hata do bhaaiyo answer sahi aajaega
The diagram itself is wrong. The resistor needs to be in parallel with the capacitor. Equation is also wrong to the given figure in the video.
if it is parallel.. than it will become Maxwell capacitance bridge
Plss also show how u open the bracket bcoz it is difficult to understand for some students.......!
Kon smjhaye chut**n ko
Solution incomplete, your L1 still depends on R1 but in this case R1 should be unknown
Or mahnat kroo samjh aaa jayega 😂😂
@@LVP635bhai kal end sem hai kaha se Karu mehnat aur to aur ye aadha adhura padhate hai 😢😢
Ye L1 ki value glt h
Last line itni nhi aa rhi
C4hai bhi
Abe pura solution dikha deta aache se
video nahi chal raha hai suwar(ara ji)
Tumne glat solve kiya hai.
Ye to galat calculated hai
Galat calculated he bro
sorry but i have not understood your concept\
Why in RHS of imaginary part it c4 is not R4 .....plz ..tel me..
you saved my life thanks Bro
I can't realate how R4 is on the right side of imaginary part?
c4 will be there
In right side of imaginary part it is c4 not R4 , I Think
Yes....
I was stuck there too
its c4 in imaginary part right?
yes its c4
Excellent bro👍
C4 is in series with R4
Thank you sir❤
Bhai mere thodi video bdi bna le km se km pura explain to kra kro last dimag khrab hojata hai ye last me C4 ki jgh R4 kha se agya
Yeh j or omega kuu liya ?? Z1 MAIN
Good explanation tq sir
Negative sign kaise huwa sir.
j2 = -1
J square = -1
Thank you ❤❤❤❤❤❤❤
Why minus
Nice
Thanks
Bass R4 hata do bhaaiyo answer sahi aajaega
The diagram itself is wrong. The resistor needs to be in parallel with the capacitor. Equation is also wrong to the given figure in the video.
if it is parallel.. than it will become Maxwell capacitance bridge
Plss also show how u open the bracket bcoz it is difficult to understand for some students.......!
Kon smjhaye chut**n ko
Solution incomplete, your L1 still depends on R1 but in this case R1 should be unknown
Or mahnat kroo samjh aaa jayega 😂😂
@@LVP635bhai kal end sem hai kaha se Karu mehnat aur to aur ye aadha adhura padhate hai 😢😢
Ye L1 ki value glt h
Last line itni nhi aa rhi
C4hai bhi
Abe pura solution dikha deta aache se
video nahi chal raha hai suwar(ara ji)
Tumne glat solve kiya hai.
Ye to galat calculated hai
Galat calculated he bro
sorry but i have not understood your concept
\
Thanks