Nice! Can you please let me know what whiteboard you are using and what projector and app you are using to project slides and be able to erase and change slides? Awesome!
you mean how to find 0.24 and 0.4j So after marking the circle there is a resistance circle and 0.4j is reactance circle so these circle intersect each other at that point.
yoo are better than 10000 idiot university lecturers who just want to finish their lecturers and get paid ... just for the sake of ther salaries ... well done and a lot of respect
The impedance circle is on the other side of vswr. Remember that when we wanted to plot the normalized load impedance we took our j from the upper part of the chart. Now since our input impedance has its j on the lower part, it is negative. You can also see the -ve sign on the chart. Hope this helps
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"Nothing" but a good explanation
Sir,you have explained very well and Thankyou.
Fantastic refresher. Many thanks. I haven't touched a Smith Chart in years.
It is now become nothing but Easy.
Thanks a lot bro
lmao, the arbitrary circle looks like a perfect ellipse. Excellent explanation btw.
great video sir.....
Thank you sir...!!! Made my day...!!!
Sir thank you so much... Very helpful for students like us
very helpful explanation
I counted around 50 Nothing but in this video, personal record for my guy
we counted 208 ''correct'' in our college lectures....that too in 50 minutes ....correct
Very helpful I was very worried about Smith chart thank you ♥️😊
Thank you so much sir 😌
How to take lamda values canu explain it clearly please
Very well explained sir....thank u
Great thankful to you sir for ur wonderful explanation 🙏
Nothing but thank you kind sir
Actually input admittance u have obtained in smith chart is normalized in order to get input admittance divide with characteristic impedance
Nice! Can you please let me know what whiteboard you are using and what projector and app you are using to project slides and be able to erase and change slides? Awesome!
chusna padega pehele
Thanks a lot 😵💫
Thank you so you had made my day
Great lecture
I got to know nothing but something but nothing. I wanna say nothing but thank you
you are great
Thanks mate. Much appreciation.
Very useful, thank you
nice lecture mahn
Thank you very much ..bhai
Thanks Mr
Great videos thank you!!
Good expalaination sir
thank you very much dude. its really a good job. i really appreciate.
Ichi padesnav kali💯👍😂
How to find normalized input admittance and normalized output admittance on smith chart
Tq sir nice explanation
point 1,0 is any arbitrary point point taken for the center of circle
You have done Very good job explaining sir.
If the length is not in terms of lamda
What should we do..!!
How to get the value of input impedance after marking it in the circle
you mean how to find 0.24 and 0.4j
So after marking the circle there is a resistance circle and 0.4j is reactance circle so these circle intersect each other at that point.
Great thanks
we want 3.3 lambda so we should add (0.135+0.165)*lambda=3.3*lambda approximate???.why are you want 3.43 *lambda sir??
why did you consider 1,0 as centre ?
yoo are better than 10000 idiot university lecturers who just want to finish their lecturers and get paid ... just for the sake of ther salaries ... well done and a lot of respect
I can't understand input impedance calculation how to write 0.3 value please apload another vedieo sir
Thanks
why u take axis (1,0)
If do you know the answer plz rply me..
reactance circles passes through (1,0) axis
Thanks ra
they should put a "nothing but "counter
Awesome
Tank you
if Zin is given, is the procedure to find ZL the same?
Nice sir
Why u draw a circle (1,0)
point 1,0 is any arbitrary point point taken for the center of circle
Super Sir
Good
What is ( 1,0) how to take origin while drawing axis
Same doubt
How to draw VSWR circle ??
The point at which load impedance is found,take the radius from centers to that point and draw vswr.
how u can take (1,0) as a centre point
I didn't got how to trace Zin please explain sir
see that point as intersection of 2 circles, resistance and reactance ones.
Pls tell me again input impedance
👌
👍
God
It's gamma right and not tow ?
Yeah
sir how you get the minus in input impedene
The impedance circle is on the other side of vswr. Remember that when we wanted to plot the normalized load impedance we took our j from the upper part of the chart. Now since our input impedance has its j on the lower part, it is negative. You can also see the -ve sign on the chart. Hope this helps
Why you take 1,0 point
I think you have made a mistake
please reply answer