Let's do this together, Concept Crunch!

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  • Опубликовано: 8 ноя 2024

Комментарии • 56

  • @jeesimplified-subject
    @jeesimplified-subject  Месяц назад +1

    Join Tele for regular updates!
    t.me/jeesimplified

  • @nishants8185
    @nishants8185 Месяц назад +33

    Start with Conic sections Please!

  • @ShivamSharma-xs4uy
    @ShivamSharma-xs4uy Месяц назад +12

    TELESCOPIC METHOD OF FINDING GENERAL TERM

  • @JustTakezo
    @JustTakezo Месяц назад +1

    Letsssss goooooooo

    • @Prabhu108.
      @Prabhu108. Месяц назад

      You ain't ubermensch bro

    • @JustTakezo
      @JustTakezo Месяц назад

      @@Prabhu108. I am Ubermensch 🦅

    • @Prabhu108.
      @Prabhu108. Месяц назад

      @@JustTakezo I'm also ubermensch 🗿

    • @JustTakezo
      @JustTakezo Месяц назад

      @@Prabhu108. 🗿we are brothers from now

    • @Prabhu108.
      @Prabhu108. Месяц назад +2

      @@JustTakezo Always were ✅🥶

  • @PURVA_PATEL637
    @PURVA_PATEL637 Месяц назад +4

    rolles theorem , lagranges mv theorem and cauchy mv theorem

  • @firehydrant51
    @firehydrant51 Месяц назад +2

    love u bhaiya

  • @JitakaharKalita
    @JitakaharKalita Месяц назад +32

    Daily 50 MB data quota for you , saved .

    • @An_anshika710
      @An_anshika710 Месяц назад +2

      😂

    • @TypoSid
      @TypoSid Месяц назад +2

      💯

    • @Naitik_Barnwal
      @Naitik_Barnwal Месяц назад

      ​@@An_anshika710 50MB data is actually enough for 2 minutes video which bhaiya makes

    • @bhoju_
      @bhoju_ Месяц назад

      ​@@An_anshika710😂

  • @Mayank-xo5lg
    @Mayank-xo5lg Месяц назад +5

    Bhaiya ye to hota rhega 💀unmute me 🥺🥺🥲

  • @abhinavmartandjha0369
    @abhinavmartandjha0369 Месяц назад

    Bhaiya you are growing you only need some top ranks to increase your fame.

  • @yuvrajsingh-wk3py
    @yuvrajsingh-wk3py Месяц назад +4

    Suppose k > 0. Let c and d be the roots of x² - kax - (k + 1)b = 0 and a, b be the roots of x² - kcx - (k + 1)d = 0, and a + b + c + d = 180, then k is equal to
    A. 11
    B. 9
    C. 7
    D. 5

    • @SanatR001
      @SanatR001 Месяц назад +1

      5 ?

    • @yuvrajsingh-wk3py
      @yuvrajsingh-wk3py Месяц назад

      @@SanatR001 can you tell the solution please.
      I don't know the answer.I am searching for it.

    • @rohan.jadhav.6179
      @rohan.jadhav.6179 Месяц назад

      You have to find relarion between a and c
      Just use sum and product
      And also put c and a in the respective ​ eqn @@yuvrajsingh-wk3py

    • @AkshayxV7
      @AkshayxV7 25 дней назад

      B 9

    • @yuvrajsingh-wk3py
      @yuvrajsingh-wk3py 25 дней назад

      @@AkshayxV7 a + b = Kc - (i)
      c + d = ka - (ii)
      (i) + (ii)
      a + b + c + d = k(a + c)
      180 = K(a + c)
      a + c = 180/k ->eqn 1
      ab = - (k + 1) * d - (iii)
      cd = - (k + 1) * b - (iv)
      (iii)×(iv)
      abcd = (k+1)^2 bd
      ac = (k + 1) ^ 2 ->eqn2
      → Put x = a in eqn x^2 -kcx -(k+1)d=0
      a^2- kac - (k + 1)d = 0 - (v)
      → put x = c in eqn x^2 - kax -(k+1)b=0
      c^2 - kac - (k + 1)b = 0 - (vi)
      (v) + (vi)
      [a^2 + c^2 - 2kac - (k + 1)(b + d) = 0] [main eqn.]
      → from eqn. a + b + c + d = k(a + c) (i) + (ii)
      b + d = k(a + c) - (a + c)
      b + d = (a + c)(k - 1) ->eqn3
      Squaring Both side in eqn 1(because to find [a^2+c^2]for main eqn.)
      (a + c)^2 = (180/k)^2
      a^2 + c^2 = (180/k)^2 - 2ac ->eqn 4
      Substitute (b+d) and (a^2+c^2) from eqn 3 and 4 in main eqn
      (180/k)^2 - 2ac - 2kac -(k+1)(k-1)(a+c)=0
      → Now Substitute (a+c) and (ac) from eqn 1 and 2 in above eqn
      (180/k)^2 -2(k + 1)^2 -2k(k + 1)^2 -(k^2 - 1)(180)/k) = 0
      On simplifying,
      2k^5 +6k^4 +186k^3 + 2k^2 -180k -(180)^2 = 0
      → Now by using calculator put all four options value, which are value of K & you will see only 5 is satisfying the Eqn.
      So,5 is answer.

  • @Ace-y7t
    @Ace-y7t Месяц назад +5

    Sir sequence and series me miscellaneous series tough lagta hai sir

    • @Rahul_Singh1729
      @Rahul_Singh1729 Месяц назад +1

      Try higher alegbra book. They have very good questions and you can learn alot from them.

    • @Ace-y7t
      @Ace-y7t Месяц назад

      @@Rahul_Singh1729 what books I can try to get my sequence and series better or a book for overall improvement in all maths topic as im hell weak in mathematics

  • @rudransh118
    @rudransh118 Месяц назад +7

    complex nuber me geometry wala part

  • @Rahul_Singh1729
    @Rahul_Singh1729 Месяц назад +3

    Bhaiya flexing his mac 👀

  • @blurryface602
    @blurryface602 Месяц назад +2

    bhaiya chemistry aur olympiad-type level course bhi ho skte h kya?

  • @aayushgupta8292
    @aayushgupta8292 Месяц назад +1

    Bhaiya please do two blocks system friction

  • @sanjeevkumarsingh8141
    @sanjeevkumarsingh8141 Месяц назад +6

    Sir coordinate geometry mein geometrical approach mein problem aati hai

  • @divyanshlotra6414
    @divyanshlotra6414 Месяц назад

  • @ABSOLUTE-ASPIRANTS
    @ABSOLUTE-ASPIRANTS Месяц назад +1

    bhaiyaa please thoda sa jee relevant rakhna it is a request

  • @ParshadAyare
    @ParshadAyare Месяц назад +1

    Ok sir, thanks btw😢😢

  • @bhavya407
    @bhavya407 Месяц назад

    Conjc section

  • @pushkarnarayan3658
    @pushkarnarayan3658 Месяц назад +1

    Maths mein beggar method mein problem aa rhi h

  • @Horizon24129
    @Horizon24129 Месяц назад +4

    i feel we need transformations of graph video

    • @aamir2915
      @aamir2915 Месяц назад

      Aasan howe follow cengage

    • @Horizon24129
      @Horizon24129 Месяц назад

      ​@@aamir2915ik but it strengthen a lot of topics

    • @Kai2.0B
      @Kai2.0B Месяц назад

      Okays

    • @Prabhu108.
      @Prabhu108. Месяц назад

      @@aamir2915 tnx bhai 😘

  • @ammarmahmood3812
    @ammarmahmood3812 Месяц назад

    Bhai conic sections kaa bhi laana bhai plzzzzzzzzzzzzzzzzzzzzZzzzzzzzzZzzzzzzzz

  • @PSE-i99u
    @PSE-i99u Месяц назад

    Okk

  • @Allinchannel123
    @Allinchannel123 Месяц назад

    Conic sections

  • @Plspadhleyourfutureselfpls
    @Plspadhleyourfutureselfpls Месяц назад

    12th ke topic se suru karo

  • @SwJSnG_IITDelhi
    @SwJSnG_IITDelhi Месяц назад

    Chashme bekar hai

  • @abhinavmartandjha0369
    @abhinavmartandjha0369 Месяц назад

    Bhaiya you are growing you only need some top ranks to increase your fame.