Hi Lawrence. Great video. I don't understand when you would use this approach and the convolution of two functions approach (which is also the sum of two independent r.v). Wouldn't both the bivariate transformation and convolution probability yield the same results?
Video is missing the most important part which is how to find the support of the transformed RV
4:04 mins.... can you kindly explain how are you plotting the graphs?
vikrant bhattacharjee The graph is easy, it’s the integration to get Y1 that’s tricky. For Y1=x1+x2, choose all possible values for 0
Hi! Could you recommend me a bibliography where I can find this procedure and more detail? Thank you!
I which I could understand your dummy transformation!!!!
Hi Lawrence. Great video. I don't understand when you would use this approach and the convolution of two functions approach (which is also the sum of two independent r.v). Wouldn't both the bivariate transformation and convolution probability yield the same results?
What if X and Y follows exponential distribution then X|X+Y follows what?
Is you have an example of direct method for solving two random variables
great video!
awesome video!!!! pls keep doing this wonderful stuff!