*Make sure to take a look over on **stemerch.com/** if you are interested in geeky STEM products! =D Get 8% off most of the products by using the code 420STEM at checkout! :)*
Ein freund: Brüder, dieser equation is sehr schwierig... Ich: Was häst du dir gedacht? Ich brech' mir mein Genick? Bitte hören Sie mich das ich bin nicht eine noob.
Summing the two fractions at 4:54 you may multiply numerator& denominator of the second one by e^x, and write it as e^x/(e^x+1) , whence it is clear that the sum is 1
Hey papa flam. This question was on my latest Newtonian mechanics exam. I hope you can help me because I have no idea how to solve it. Here goes: Which of the following differential equations systems have periodic solutions: a) x' = y y' = 3x^2 - y - y^5 b) x' = y y' = x^2 + y^2 + 1 c) x' = y y' = (x^2 +1)y - x^5
@@user-un7gp4bl2l I'm sorry you're totally right. I confused the dependent variables with the independent variable (I was thinking about laplace transform of t^n)
Math & Coding I’m assuming periodic implies continuous. If this is the case, x’ and x’’ must pass through 0 periodically and when x’ is 0 x’’ has to take on both positive and negative values (otherwise the function would increase/decrease indefinitely). For b), x’’=x^2+x’^2+1, x’’>0 for all t (assuming real x lol), so that’s out of the question. A) is x’’=3x^2-x’-x’^5. At the points where x’=0, x’’=3x^2>=0, so x’’ cannot take on negative values there. So the only one that could admit such solutions is c), although I cannot prove that it does.
i'm watching this video immediately after the one on the identity related to e/(1+t^o) and it's so satisfying to just see it put into action right away.
In the Flammy's Method vid yesterday, you called the base in the denominator t, and didn't restrict it much. Today you presented it as an even. Is it only guaranteed for t=e(x) ?
I have a question: What a about the odd functions ⁉️ For example (especially this one) if we have odd function in the numerator (like x^3 )❓(integration over zero to infinity)
int(x^n/(exp(x)-1)^k, x = 0 .. infinity) this can be solved by int(x^n*exp(x)/(exp(x)-1)^k, x = 0 .. infinity) and my technique of solving this is through integration by parts.....i do not know how to generalise it because the coefficients dont seem to have a pattern....Still they spew out rienmann zeta and gamma functions. Its interesting tho.
Trieste comment 😁😁 I am in grade ten and I absolutely love your videos mannn Keep up the good work for making people love such a beautiful subject MATHEMATIC BYE
@Atharva Sharma forgive my curiosity, but how come you know integration even though you're in grade ten ? As far as I know, in India we learn basic integral calculus in grade twelve.
*Make sure to take a look over on **stemerch.com/** if you are interested in geeky STEM products! =D Get 8% off most of the products by using the code 420STEM at checkout! :)*
Imagine writing this identity on a test and annotating "idk if this has a name but flammablemaths proved it"
xD
Isn't this integral just a corollary of that super OP symmetry technique from the previous video?
Edit: yeah -- ¡¡ retroactive spoiler warning !!
:DDD
time for my daily dopamine and serotonin boost
2:20 Highest quality integral sign on this channel.
fucking fabulous
@@PapaFlammy69 o_O
0:00 i apples? Unreal!
It's complex :/
Fun fact: If you’re sad you’re not happy
ri🅱
Thank you Einstein, very cool!
Every 7 days in Africa, a week passes, together we can stop this.
hmmm... another one:
If u die, you will not survive
@@mastershooter64 I remember this line from Obama's inauguration speech, come on, give him some credit.
this kind of looks like the even-odd integral technique you mentioned before!
edit: nvm you brought it up lolol
:p
Kermit loves integration
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
@@PapaFlammy69 r/ihadastroke
xD
Can we just take a moment to admire how perfect the Integral symbol in 2:19 is?
:^)
@@PapaFlammy69
Goddamn I love these videos, also this integral was brilliant, keep it up!
Thanks Dozzco! =)
An overkill method for such a sexy integral..NOICE
:3
Ein freund: Brüder, dieser equation is sehr schwierig...
Ich: Was häst du dir gedacht? Ich brech' mir mein Genick? Bitte hören Sie mich das ich bin nicht eine noob.
The result at 5:42 is both hilarious and amusing, please keep those cool bois coming.
:D
Papa flammy makes me appreciate my math degree a lot more. Keep the content coming.
Summing the two fractions at 4:54 you may multiply numerator& denominator of the second one by e^x, and write it as e^x/(e^x+1) , whence it is clear that the sum is 1
Hey papa flam.
This question was on my latest Newtonian mechanics exam.
I hope you can help me because I have no idea how to solve it.
Here goes:
Which of the following differential equations systems have periodic solutions:
a) x' = y
y' = 3x^2 - y - y^5
b) x' = y
y' = x^2 + y^2 + 1
c) x' = y
y' = (x^2 +1)y - x^5
I'll give it a shot! =)
@@PapaFlammy69
Thanks!
Less than three
Geometry Dash Mega They are not linear equations
@@user-un7gp4bl2l I'm sorry you're totally right. I confused the dependent variables with the independent variable (I was thinking about laplace transform of t^n)
Math & Coding I’m assuming periodic implies continuous. If this is the case, x’ and x’’ must pass through 0 periodically and when x’ is 0 x’’ has to take on both positive and negative values (otherwise the function would increase/decrease indefinitely). For b), x’’=x^2+x’^2+1, x’’>0 for all t (assuming real x lol), so that’s out of the question. A) is x’’=3x^2-x’-x’^5. At the points where x’=0, x’’=3x^2>=0, so x’’ cannot take on negative values there. So the only one that could admit such solutions is c), although I cannot prove that it does.
Whole lotta crackhead energy lmaooooo
love the way you write your integral sign
Thx Suga :3
0:21 #relatable
i'm watching this video immediately after the one on the identity related to e/(1+t^o) and it's so satisfying to just see it put into action right away.
Damn my PAPA done it again!
:)
The Single Most Overpowered Integration Technique in Existence ^^
:p
@@PapaFlammy69 You could call it SMOITE and it'll still work
Oddly satisfying. Overpowered integral generalization indeed...
:)
Mad respect PAPA !!!
In the Flammy's Method vid yesterday, you called the base in the denominator t, and didn't restrict it much. Today you presented it as an even. Is it only guaranteed for t=e(x) ?
Yup! I made a pinned comment stating it! =)
this integration technique is so strong i had to manually write it into my book of integrals
Truly an integral part of happiness😯😯😯
indeed! :D
😱😱😱 symmetric boi!
ayyyyyyyyyyyyyyyyyyyyyyyyyy
According to your clock, that was just one take!
What would u even call the technique? Flammy’s technique of integration?
yeye
Yaaas new flammy video :D
Werner :000000000000000000000000000000000000000000000000000000
when are you gonna integrate the inverse gamma function or "ni" papa flammie pp?
Oh boi, that sht horrible m8 ngl ;_;
Another great integral.
Next time do a video on solving the same integral in 10 ways.
:D
I have a question:
What a about the odd functions ⁉️
For example (especially this one) if we have odd function in the numerator (like x^3 )❓(integration over zero to infinity)
the dots over the "i" on the right side of the t-short need to be situated vertically, not horizontally.
Uh- maze - ING
:3
int(x^n/(exp(x)-1)^k, x = 0 .. infinity) this can be solved by int(x^n*exp(x)/(exp(x)-1)^k, x = 0 .. infinity) and my technique of solving this is through integration by parts.....i do not know how to generalise it because the coefficients dont seem to have a pattern....Still they spew out rienmann zeta and gamma functions. Its interesting tho.
Out of 100 i would rate this only 5!
( if you know what i mean)
:p
5 factorial o_O
papi flam, maybe if u want, upload video about trading math with calculus ? 😂😂
Good integral. If n is not an integer but is a positive real number, n is never equal -1/2. what happen if n=-1/2?
Came here from the even(x)/1+even(x)^odd(x) integration trick and can instantly tell it is int x^2n dx from 0 to t
nice! :D
I love abstract apples mlem
I wish apple analogies worked for the multiplicative identity :( if you have one apple, and you divide it in to 1 apple, idk
That really is an overpowered technique :0 appreciate it.. need to go watch back that vid. Didn't have time :(
@@PapaFlammy69 uwu
Nice.
I'm studying a double degree in math and physics
Does that make me gae?
How is that theorem called? I am looking for the proof.
He has a video titled "the most overpowered integration technique" or something like that. The proof is his, since he discovered it
Trieste comment 😁😁
I am in grade ten and I absolutely love your videos mannn
Keep up the good work for making people love such a beautiful subject
MATHEMATIC
BYE
@Atharva Sharma forgive my curiosity, but how come you know integration even though you're in grade ten ? As far as I know, in India we learn basic integral calculus in grade twelve.
@@PapaFlammy69 yeah... I'm in grade ten too.
@@BerkayCeylan nice.
Varun A K Mandokhot I learned it through RUclips
Deja vu :)
:3
Oh 0 views and 3 likes.
nice.
@@PapaFlammy69 Illuminati confirmed!!! that's it shutdown the Doritos factories!
Maths gang
Best
doctors tend to stay away from your videos I've heard
but the euler's number is not an even number 🤦
not sure if troll
bruhv
@@PapaFlammy69 omg i have been blessed by His mathematical presence 😳
High five Papa Flammy! I have joined the Engineer hater's club too because of sinx=x, cosx=1, and e=π=3.
:'D
who's yo daddy
ma mom
I hate that shirt though
It will be short video , if you apply the formula: (integral from -a to. +a)f(x)dx=(integral from 0 to a)(f(x)+f(-x))dx. Please , think about this.
thank you random pajeet, very cool
Aight, this apple is joke is getting annoying now ngl
xD