The Smartest Way to Search Arrays in JavaScript

In today's video, we have a look at different ways to search arrays in JavaScript - things such as includes(), find() and findIndex() can be used to do this 😎
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[@Sayvai]

Great video 😎 Already personally familiar with all those approaches.
There is also an alternate version of searching an array and returning a boolean to indicate whether an even number exists in this example, using the Array.prototype.some() function.
The Array.prototype.some() function will traverse through the array until the expression evaluates to find a match and returns true, or false if the expression doesn't ever evaluate / match, thereby returning false. Powerful, yet can be performant, as it can break out of an array iteration on first match, without traversing through the whole array.
See an example snippet below:
```
const numbers = [5, 9, 2, 4, 3];
const containsEvenNumber = numbers.some(n => n % 2 === 0);
console.log(containsEvenNumber); // true
```

[@UsernameUsername0000]

Great video. Array.prototype.some would’ve been perfect to introduce after the Array.prototype.find example, since it is similar but returns the Boolean like wanted.

[@lounes03b99]

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[@raphaeljaggerd3585]

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[@farazk9729]

Hi Domenic,
Thanks for your very helpful videos; I am going through them one by one. I was wondering if you also have videos on React. I did a quick search, but I didn't find any.
Thanks,
Faraz

[@lounes03b99]

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