Hey! Meggen033 here. Thanks for solving my puzzle! It was fun to watch. After all this time I forgot how it solved and was actively on the edge of my seat trying to figure it out with you! Well done!...Also, I will be checking my discord more often. Thanks!
Tricky but rewarding puzzle! Got it in 21:04, enjoyed the various deductions for the lines, especially figuring out how the 9-length line resolved (initially I didn't think it could 😅). Props to Meggen033, and thanks to BremSter for highlighting this puzzle!
11:15 the reasoning that BremSter uses here, i applied it to all the lines. a) a 7-cell renban can omit {12}. {89}, or {19} the remainder sums to 42, 28, or 35 one of them is divisible by 4, and one by 3 b) a 5-cell renban, divisible by 3, can start with 1, summing to 15. starting with 2, add 5 --> 20 --> X starting with 3, add 5 --> 25 --> X starting with 4, add 5 --> 30 --> X, because 10 is not a sudoku digit c) a 5-cell renban, divisible by 2, with 1 or 2 on it for sure, cannot have a 1 on it. this can be invoked at 13:00
11:00 - Just as a little hint for the next time: Since 45 is divisible by 3, you don't need this subtraction stuff. If 8 and 9 are left off, just check if 8 + 9 (17) is divisible by 3, you don't have to calculate 45-17 or add up the numbers 1 to 7. It makes it a bit easier. ;)
Hey! Meggen033 here. Thanks for solving my puzzle! It was fun to watch. After all this time I forgot how it solved and was actively on the edge of my seat trying to figure it out with you! Well done!...Also, I will be checking my discord more often. Thanks!
Tricky but rewarding puzzle! Got it in 21:04, enjoyed the various deductions for the lines, especially figuring out how the 9-length line resolved (initially I didn't think it could 😅). Props to Meggen033, and thanks to BremSter for highlighting this puzzle!
It is not a hard puzzle, but if not for your help I would be lost for more time than I have! 😅 Thanks!!
11:15
the reasoning that BremSter uses here, i applied it to all the lines.
a) a 7-cell renban can omit {12}. {89}, or {19}
the remainder sums to 42, 28, or 35
one of them is divisible by 4, and one by 3
b) a 5-cell renban, divisible by 3, can start with 1, summing to 15.
starting with 2, add 5 --> 20 --> X
starting with 3, add 5 --> 25 --> X
starting with 4, add 5 --> 30 --> X, because 10 is not a sudoku digit
c) a 5-cell renban, divisible by 2, with 1 or 2 on it for sure, cannot have a 1 on it.
this can be invoked at 13:00
Really enjoyed this one. The way the lines interacted with each other made it flow really smoothly.
28:20 for me. Great one, very fun thks a lot !!
45:47 to solve. A hard puzzle for me with some tricky logic required on the renban sum lines.
11:00 - Just as a little hint for the next time: Since 45 is divisible by 3, you don't need this subtraction stuff. If 8 and 9 are left off, just check if 8 + 9 (17) is divisible by 3, you don't have to calculate 45-17 or add up the numbers 1 to 7. It makes it a bit easier. ;)
A great combo of constraints, a really clever and fun puzzle! Awesome!
48:56 .... this was tough for me!!!
32:54 for me
nice puzzle