Sir, in some books the sign convention for finding the shear stress is opposite means while we go from right to left then the upward forces are taken as '-ve' and in the downward forces are taken as '+ve' . Sir plz.. tell me is there any chance of deduction of marks in exm. Besides this U'r lectures are very nice sir thank you.
Sir i got confused with sign convetion...in my college lecture teached reverse way ...full confusion please help ...iam from karnataka.. Visvesvaraya technological University belagum🙏
Sir... Ur explanation is good... But I got a doubt.. You have considered section from the right and took moments sign negative even though it is clockwise as per sign conventions you prescribed... Can you please clarify this?
Is it possible that two figures of Shear force of identity question ( both figure is symmetrical but different in sign negative or positive) and also says same thing about bending moment for identity question?
Thank you Sir! 🙏 It has helped me tremendously. Your concepts are crystal clear, consistent and easy to understand. Your English, flawless. I am thankful to God that I found this channel. Continue imparting more of your knowledge to people like me who need clarity of concepts.
Why is the bending moment at point C (left side portion of the beam )with force V is anticlockwise while the force V is downward ? Unable to understand . Kindly explain Sir .
Thanks for appreciating my work Nikhil Do watch all the videos on drawing and mechanics...... And also let your your friends know about this Channel so that they can also benefit.......
Sir in this question you find out shear at B is p/2 but when you take section from D to A, you find out shear at B is -p/2 If we take p/2 then the garph found out to be wrong
Sir I am Abhi.Sir in SOM by R.S. Khurmi, the way they have done S.F.D is different. I am practising by your way of conventions but my diagram comes to be positive and in the book it comes to be negative...What to do Sir??? I am in a problem..
Yes nikhil you can do that....No issues...The values that you will get are same as i did... Go ahead...I appreciate that you are thinking about taking section from left..... All the best...
You asked a long time ago but no one answered. I hope you worked it out but for anyone else: The internal moment is what resists the forces on the beam. If the external forces make the beam sag the external/applied moment is positive by convention. Inside the beam the resisting moment caused by forces between atoms is trying to lift the beam back up so it is hogging and negative. We can either say that the external moment M equals the moments from the applied loads, so M=M1 + M2 ... OR, we can say that the sum of the moments is zero and assuming that the beam is sagging the internal resisting moment Mr is negative so -Mr+M1+M2 etc = 0. Unfortunately, when we look at the section diagram we might see the moment arrows appear to make the beam on the right sag. Then we think that the left AND right hand moments are positive BUT NO, they are moments on the section. If you imagine twisting the SECTION clockwise against the beam, it will try to go up (hogging). That's why the moment on the left of the section is negative and not positive like I thought for a long time!
![Chino Pacas - Modo Capone (with Drake & Fuerza Regida) [Video Oficial]](http://i.ytimg.com/vi/zjv8TQ0gBkg/mqdefault.jpg)
You teaching style is very clear and smooth. Cleared a lot of concepts from this video . Thank you Sir .
Sir, in some books the sign convention for finding the shear stress is opposite means while we go from right to left then the upward forces are taken as '-ve' and in the downward forces are taken as '+ve' . Sir plz.. tell me is there any chance of deduction of marks in exm. Besides this U'r lectures are very nice sir thank you.
Your way of teaching is very good it enables to understand easily
Sir i got confused with sign convetion...in my college lecture teached reverse way ...full confusion please help ...iam from karnataka.. Visvesvaraya technological University belagum🙏
You are right my college teacher too reverse the sign so m too confused🤔
@@ritika223 I think the Professor at your college takes left side of the section .
great teaching style
Why would a downwards net force on the right side of a beam cause the moment to be counter clockwise and vice versa?
Bubba Gumption just a convention to be followed for universality.
You are good at explaining the concept
Thanks Farhan... and all the best
Thank you Sir!! U got a great teaching style and lots of love and respect from Pakistan...
Thanks 🙏🙇abdul and keep learning......
Mst welcome
sir, shear force acts downwards, Moment acts anti-clock wise how it is possible?
In some books I have seen clockwise moment is positive and anticlockwise is negative
Sir... Ur explanation is good... But I got a doubt.. You have considered section from the right and took moments sign negative even though it is clockwise as per sign conventions you prescribed... Can you please clarify this?
I too confused with that 😐
Please tell if you've cleared that doubt
Is it possible that two figures of Shear force of identity question ( both figure is symmetrical but different in sign negative or positive) and also says same thing about bending moment for identity question?
Thank you Sir! 🙏 It has helped me tremendously. Your concepts are crystal clear, consistent and easy to understand. Your English, flawless. I am thankful to God that I found this channel. Continue imparting more of your knowledge to people like me who need clarity of concepts.
Why is the bending moment at point C (left side portion of the beam )with force V is anticlockwise while the force V is downward ?
Unable to understand .
Kindly explain Sir .
Why it is not clockwise ?
Sir ji really extraordinary
Keep it up
the concept was well explained, but we would have loved it if u solved a question for us aside from the concept
Sir u r great sir u r doing a very good job sir tq tq so much sir
Thanks for appreciating my work Nikhil
Do watch all the videos on drawing and mechanics......
And also let your your friends know about this Channel so that they can also benefit.......
Sir in this question you find out shear at B is p/2 but when you take section from D to A, you find out shear at B is -p/2
If we take p/2 then the garph found out to be wrong
Thanks sir ❤❤❤
All the very best Khagendra and do share it with your friends
Sir may I know the name of software u used for teaching in this vedio
Thankyou sir your video clear all my doubts.....
You are welcome Ajay all the best
Sir I am Abhi.Sir in SOM by R.S. Khurmi, the way they have done S.F.D is different. I am practising by your way of conventions but my diagram comes to be positive and in the book it comes to be negative...What to do Sir??? I am in a problem..
Don't worry....that's just sign convention.....
I would encourage you to go through
Vector Mechanics by Beer and Johnston
@@ManasPatnaikofficial Ok Sir
Sir can we get this video in left to right will doing bending moment and shear force calculation
Yes nikhil you can do that....No issues...The values that you will get are same as i did...
Go ahead...I appreciate that you are thinking about taking section from left.....
All the best...
sir shear force sign conventions are from the right of the section downward force is positive..and upward force is negative
Sir, please also make the video series how to make these types of presentation, which is very impressive.
I saw all of u r lectures on sfd and bmd. One doubt sir instead of clockwise -ve can we take +ve and solve the problem
Concepts God ❤☺
Sir, how do you decide the direction of BM? Clockwise direction or anticlockwise direction??
Take any direction......If the answer comes out to be -ve , The actual direction is opposite to what was assumed
the way of lecturing is very nice sir..
YOU EXPLAINED VERY WELL
THANKS
Thanks sir
Very nice
Sir bahut Dino baad apse padh raha Hoon I am sorry Kuch bhi samajh nahi aaya
Sir Ra horizontal force why you are not considering
great explaination ❤️🙏
sir U told that sagging moment is postive But U take take negative in this how it is possible ?
You asked a long time ago but no one answered. I hope you worked it out but for anyone else: The internal moment is what resists the forces on the beam. If the external forces make the beam sag the external/applied moment is positive by convention. Inside the beam the resisting moment caused by forces between atoms is trying to lift the beam back up so it is hogging and negative. We can either say that the external moment M equals the moments from the applied loads, so M=M1 + M2 ... OR, we can say that the sum of the moments is zero and assuming that the beam is sagging the internal resisting moment Mr is negative so -Mr+M1+M2 etc = 0. Unfortunately, when we look at the section diagram we might see the moment arrows appear to make the beam on the right sag. Then we think that the left AND right hand moments are positive BUT NO, they are moments on the section. If you imagine twisting the SECTION clockwise against the beam, it will try to go up (hogging). That's why the moment on the left of the section is negative and not positive like I thought for a long time!
Mx should be positive here ?
Xlent one
Nice👍👍👍 sir
Love uh sir... Uh r a great teacher....
thanks..sir
6:08
Sir, these video was confusing
Hindi me. Samjao sir 😡😡😡😡😡😡😡
Apni language change kro..Make lecture in..Hindi..Because in english ur very poor