Factor (- x squared + 9)/x + 3 LEARN this LITTLE Factoring TRICK to do this!

How to factor polynomials, simplify rational expressions and difference of two squares.
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[@larrystuder6378]

Rotate -x2 + 9 to 9 -×2 and it assumes the form of ( a+b) * ( a-b). So it becomes ( 3 + x) ( 3-x). Rotate the denominator to 3+×. Comutative property. The (3+×)'s cancel 3-× is all that's left.

[@russelllomando8460]

got it (-x+3) diff. of 2 sqrs. reversed. thanks for the fun.

[@seibertmccormick184]

I'm 71 and a bit rusty, but I got this right off.

[@ernestcook4285]

Simplified X + 9 divided by 3

[@panlomito]

Oké, this one looks complex but is quite easy:
- ( x² - 9 ) / ( x+ 3 ) = - ( x + 3 ) . ( x - 3 ) / ( x + 3 ) = - ( x - 3 ) = - x + 3

[@user-gx1rk8yw6l]

the
@panlomito All indeed OK, except the ASSUMPTION that the "-x^2" means "-(x^2)". For that to be true, the "x^2" MUST be VISIBLY grouped. Because, so far as *I* know, NO convention exists for the meaning of the "-" in such situations, ie whether it is a sign or an operator.

[@richardshearer8623]

2x

[@johnplong3644]

This Algebra 1 need to know how to factor

[@greglear50]

X-3

[@mollymam7153]

3-x

[@pollyj4jam157]

No.. still don't get it. Thank you 😊

[@kjellg6532]

12 minutes!?

[@user-gx1rk8yw6l]

This CAN be factored, but ONLY if the "-x^2" is intended to mean "-(x^2)". Factoring is not possible when it is intended to mean "(-x)^2".
This is a situation where grouping is a MUST for clarity, because simply ASSUMING that it means 1 or the other is an ass-maker.
The video-maker, DESPITE his decades of experience as (maths?) teacher, simply skips over this point. THAT is why I give this video a thumbs-DOWN. 👎

[@rogeraffleck8677]

You are wrong. There is no ambiguity. By the order of operations exponents must be done before multiplication, so x must be first squared and then multiplied by -1 (which is what the negative sign in front of x means) If you intend to do the negative first then the problem would have been written (-x)^2

[@user-gx1rk8yw6l]

@@rogeraffleck8677 Ahhh... this is where that (silly-&-ambiguous) PEMDAS or BODMAS or whatever MIGHT come into play. The thingie that, being a fairly-local mnemonic, is NOT GLOBALLY known & CERTAINLY NOT globally taught. (It is local to some countries.)
But even then, the exponentiation is of the REST of the term, which can be either "-2" or "2" or "+2". And since NO grouping-symbols clarify the situation, the statement is ambiguous in the sense of that symbol representing a sign or an operator.
Prove THIS POSITION wrong with an at-minimum GLOBALLY recognized convention, OK? Better yet, do so with a mathematically rigorous statement. For any such convention MUST be deducible from THAT, or be too ambiguous to be taken seriously.

[@harrymatabal8448]

3-x