త్రిభుజ కేంద్రాలు ఏ పోటీ పరీక్షలో అయినా ప్రొబ్లెమ్స్ వచ్చే ఛాన్స్ ఉండే టాపిక్ -

[@boddupallyshirisha316]

Hai sir In a cube each edge increase d by 50% find the% increased in surface area

[@HaraGopal]

125%

[@boddupallyshirisha316]

Plz explan it sir

[@maruthihariprasad]

@@boddupallyshirisha316
Example let a side of a cube is a=100
Then surface area A = 4×100×100. (since A =4a^ ^ is 2)
=40,000
According question edge increased by 50%
I.e side a =150
Surface area of a cube is A=4a^. (^ = 2)
A= 4×150×150 =90,000
Increased in area = 90,000 - 40000
= 50,000
Therefore increased % = 50,000÷40,000 ×100
=125%

[@prasadkanna95]

Good explanation sir,maths bags ravalante EMI cheyyali EMI telusukovali sir,i preparing dsc,non maths pls suggestion sir.

[@HaraGopal]

ఈ వీడియో చూడండి
ruclips.net/video/XyjUBhn4xPo/видео.html

[@prasadkanna95]

Ok sir

[@ganeshreddy4082]

Thank you sir

[@priyakondi0609]

Good explanation sir...

[@lavanyayadav9961]

Sir TGT, PGT related videos cheyyandi sir

[@priyayenibera7]

Thank you sir🙏

[@manjulasree4497]

Thank you sir

[@ramunallala2307]

Thank you Sir