Ballistic trajectory math - max range

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  • Опубликовано: 21 янв 2025

Комментарии • 22

  • @que6827
    @que6827 4 года назад +1

    If the thing I'm taking the distance from is on another altitude then me what do I need to do to correct it, if anything?

  • @henrydawes3144
    @henrydawes3144 9 лет назад

    This video helped me out so much, really got the point across.

  • @theoverengineer
    @theoverengineer  11 лет назад +1

    All things fall at the same rate regardless of their masses - since about Galileo Galilei, 1586. Drag, side wind, upwind are not considered hence the title "max range" in sharp contrast to "actual range - a practical approach that works factoring in air density, altitude, surface finish and shape, plus wind".

  • @WadcaWymiaru
    @WadcaWymiaru 4 года назад

    Do the mass matter? Or only the angle?

  • @NavyGunner1980
    @NavyGunner1980 11 лет назад +1

    What about mass and drag of the projectile?

    • @watersxo
      @watersxo 2 года назад

      I know I am 9 years late but to answer your comment the mass of the projectile does not affect the gravitational speed but it will make the object harder to accelerate

  • @thegloriousquran1208
    @thegloriousquran1208 4 года назад

    How can this help me to intercept the cannon ball mid air?

    • @theoverengineer
      @theoverengineer  4 года назад

      You tell us how or why, we can only crunch the numbers here.

  • @dantheman9534
    @dantheman9534 9 лет назад

    Very well explained!! thanks.

  • @talal9038
    @talal9038 7 лет назад

    if the initial speed for AK-47 is 715 m/s based on your equations the flight time will be 103 seconds !! (can you explain please)

    • @theoverengineer
      @theoverengineer  7 лет назад

      Explain 103? Explain time? On a video titled RANGE? Explain AK-47?

    • @talal9038
      @talal9038 7 лет назад

      If the initial speed for gun is 715 m/s
      V.vertical = 715 sin 45 = 505 m/s = V.horizontal
      t=(2*V.vertical)/g= (2*505)/9.8 = 103 s
      103 second is very long time as flight time.

    • @theoverengineer
      @theoverengineer  7 лет назад

      Yup, correct math, good suspicion. Angled at 45 degrees, projectile will be in air for 103 sec. In textbook theory.
      Now here is a real-world check: shoot at 90 degrees vertically up, time it how long it takes to get the bullet to land. Calculated time is 145 sec. Note the actual hang time. Divide actual time by theory time to get a correction factor (for air resistance and other things). Then multiply the 103 by this correction factor to get a close, more realistic figure.
      Makes sense?

    • @talal9038
      @talal9038 7 лет назад

      if you can make a video explaining this matter it will be great.

    • @dibitafpsm-tr9292
      @dibitafpsm-tr9292 5 лет назад

      because of air resistant its more and more and more in real life condition watch this and see reals of life ruclips.net/video/J_VxOf15J1I/видео.html

  • @ETH1World
    @ETH1World 10 лет назад

    Thank You man you are a saver!

  • @gustavebbesen1
    @gustavebbesen1 11 лет назад +1

    this video helped me alot!! thanks :)

  • @guitarmancentral
    @guitarmancentral 7 лет назад

    It's actually not though. This implys that the projectile is in a vacuum with no air resistance. The projectile will actually fall shorter than that in real life

  • @Radim24
    @Radim24 2 года назад

    This calculation gives unrealistic results. Give a angle 22° at speed 200 mps which is extremly slow bullet, it should according my result flight max range 1361m, which is non-sense, because that would be like bullet shot from a sniper rifle. It must stop somewhere because it will hit ground because of resistance of the air, it will drop down definitely before 1km.