At 04:30 instead of "slice out the rectangle", it would have been much more clearer if you had drawn a parallel through P to AC, that intersects BC in C". There you have the similar triangles APQ and PBC"; the proportional bases are x and (2A/h-x) , the same proportional heigths are (H-y) and y
At 04:30 instead of "slice out the rectangle", it would have been much more clearer if you had drawn a parallel through P to AC, that intersects BC in C". There you have the similar triangles APQ and PBC"; the proportional bases are x and (2A/h-x) , the same proportional heigths are (H-y) and y
How did he take angle AQP=angle PCB
Enjoyed