Great video as always, I did have a small concern though, when taking the d/dx of sqrt(r^2-a^2) why was the d/dx of r^2 within g(x) not at all acknowledged, If I understand the chain rule correctly when taking the d/dx g(x) shouldn't it have been =(2r-2a)as appose to (-2a). I understand I'm wrong in assuming this but I'd like to know why, any clarification would be much appreciated
It's easier if you take the angle alpha. Then you have A=2R^2cos(alpha)sin(alpha). Amax is reached when you have alpha = pi/4.
Easy to understand
Great video as always, I did have a small concern though, when taking the d/dx of sqrt(r^2-a^2) why was the d/dx of r^2 within g(x) not at all acknowledged, If I understand the chain rule correctly when taking the d/dx g(x) shouldn't it have been =(2r-2a)as appose to (-2a). I understand I'm wrong in assuming this but I'd like to know why, any clarification would be much appreciated
In this problem, R is a constant and "a" is a variable.
Clears up my confusion completely Thank you.
is that quadrilateral which is inscribed a square
not all hero wear cape
all that just for r^2. wow thanks obama
lol
Amazing!!
and this question cam in cat 2023 slot 3😮💨😞
We are not familiar with the CAT test.
amazin
i dont get it
sorry that is not triangle that is rectangle