Complex analysis: Weierstrass elliptic functions

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  • Опубликовано: 15 янв 2025

Комментарии • 33

  • @xiaokangzhang3077
    @xiaokangzhang3077 3 года назад +25

    Thank you Professor, these lectures are real gems

  • @faisalal-faisal1470
    @faisalal-faisal1470 3 года назад +42

    "The other good thing about saying something is 'locally uniformally convergent' is that no one can quite remember the definition of it, so they'll probably give you a pass for whatever you want to claim for it" :)

    • @xcl9189
      @xcl9189 3 года назад +3

      jesus christ ! that is the only thing I can remember the definition of at the moment

  • @dane4ka474
    @dane4ka474 Год назад +1

    Good sense of humor combined with deep knowledge is a blessing

  • @SG-kj2uy
    @SG-kj2uy 3 года назад +6

    Watching your interview video, I became a big fan of you.

  • @peisun1215
    @peisun1215 3 года назад +5

    Does anyone know any good lectures on Riemann geometry like this? I love watching lectures like these.

  • @reinerwilhelms-tricarico344
    @reinerwilhelms-tricarico344 Год назад +3

    Just looked it up: In LaTeX the Weierstrass P is \wp ($\wp$ in math mode).

  • @zubin8010
    @zubin8010 2 года назад +1

    at 8:32 I was feeling guilty about not knowing the conditions for this property, then felt a lot better about my ignorance within the following 30 seconds :)

  • @narutosaga12
    @narutosaga12 3 года назад +9

    Wow that bit about the Tripos example questions, so darn glad that those kinds of questions are out of style now! Yikes

  • @JesusHernandez-xv7lf
    @JesusHernandez-xv7lf 3 года назад

    Can anyone explain me more why the series in 2:42 does not converge absolutely?

    • @jussari7960
      @jussari7960 3 года назад

      You can bound the terms |1/(mω₁ + nω₂)|² from below by 1/((m+n)²r²), where r = max{|ω₁|, |ω₂|}. Summing that over m,n ∈ ℤ, you should be (if I didn't make any mistakes) able to bound the series from below by the Sum (m-1)/m², which diverges

    • @dannycrytser7268
      @dannycrytser7268 2 года назад +1

      I think that the @Jussari approach is great, but you can also apply the same sort of informal reasoning that Borcherds uses in the previous video (Elliptic Functions). For an integer N >0 look at the circle of radius N centered at z, and consider the concentric circle of radius N+1. The area of the disc contained between these two is proportional to N, and the number of lattice points (which are, at large scale, uniformly distributed) is therefore about a constant times N. Now if you look at that sum you'll get that this disc contributes a constant times N*(1/N^2) = constant/N. Summing over all such discs gives you a constant times the harmonic series, which diverges.

  • @larspos8264
    @larspos8264 3 года назад +6

    The Riemann zeta function is locally uniformally convergent, therefore all it's non trivial zero's have real part 1/2

  • @kilogods
    @kilogods Год назад +1

    ℘-function

  • @dmit10
    @dmit10 3 года назад +4

    I've found an interesting animation of the function ruclips.net/video/WnaUZrPnZ30/видео.html , I guess this comes from Eisenstein series

  • @digosen9870
    @digosen9870 3 года назад +1

    This is possibly a very dumb question and has a simple solution, but is there any reason why the number of poles has to be an integer? Couldn't there be some function that effectively behaves as having a noninteger pole? (whatever that would mean). If so couldn't we use that to get an elliptic function of the same order?

    • @lordabizi5807
      @lordabizi5807 3 года назад +1

      We are dealing with holomorphic functions, where everything can be written as power series. The order of a pole is exactly the minimal degree of non-zero coefficient in your expansion near the pole. It has to be an integer. In real analysis we have some weird functions like 1/sqrt(x) which have " a pole of order 1/2" at 0, but these formulas are not legitimate holomorphic functions (since sqrt(z) is not really well defined as a holomorphic single valued function for z near 0).

    • @digosen9870
      @digosen9870 3 года назад +1

      @@lordabizi5807 I agree with your logic about the power series expansion, that's why I framed the question as "effectively behaves as having a noninteger pole". I was hoping that there was something like this but I guess being multivalued like the 'sqrt' is the closest people have come to this.

    • @richarde.borcherds7998
      @richarde.borcherds7998  3 года назад +10

      There are indeed (multivalued) generalizations of elliptic functions with "poles of non-integer order". However these are excluded from the discussion in the lecture by the condition that the functions are meromorphic.

    • @digosen9870
      @digosen9870 3 года назад +1

      @@richarde.borcherds7998 thanks for the clarification.

    • @hyperduality2838
      @hyperduality2838 3 года назад

      Angular momentum is quantized in physics L= nh.
      Angular momentum is a fundamental.
      E = fh for photons or pure energy.
      Energy is dual to mass -- Einstein.
      Dark energy is dual to dark matter.
      "Always two there are" -- Yoda.
      "Science without religion is lame, religion without science is blind" -- Einstein.
      Science is dual to religion -- Einstein.

  • @Vidrinskas
    @Vidrinskas 2 года назад

    Congrats to the senior wrangler in 1912. You earned it. 🤣

  • @migarsormrapophis2755
    @migarsormrapophis2755 3 года назад +2

    yeeeee eeeeeeeeeeeeeee

  • @gabrielevigilante5460
    @gabrielevigilante5460 3 года назад