Simultaneous equations (linear and non-linear) - Corbettmaths

Поделиться
HTML-код
  • Опубликовано: 19 дек 2024

Комментарии • 10

  • @chloepaigeex
    @chloepaigeex 3 года назад +33

    this really helped me thank you!! i have my maths mock next week and I was stressing about this part of it

  • @premalathaemmanuel7116
    @premalathaemmanuel7116 6 лет назад +16

    Sir how do you get that mode on your calculator where there is a blinking cursor?

  • @The_trio_plus
    @The_trio_plus 8 месяцев назад +3

    Thank you so much bro 🙏🙏

  • @darlinqt
    @darlinqt 2 месяца назад +1

    Is this for higher or foundation maths ?

  • @oscarpetter1434
    @oscarpetter1434 7 лет назад +16

    thanks a very clear video and a great help!!!

  • @user-ir2er8fn5f
    @user-ir2er8fn5f 6 лет назад +9

    At around 6:14, shouldn’t you have subtracted 30, giving you x^2-11x-30?

    • @corbettmaths
      @corbettmaths  6 лет назад +21

      No, I actually kept the 30 on the right hand side and brought the other terms to that side

  • @CupcakeRiyoko
    @CupcakeRiyoko 6 лет назад +25

    Confusing... you didn't explain why you multiplied it by -1

    • @corbettmaths
      @corbettmaths  6 лет назад +81

      If I had the equation 3x = 9, I would be able to multiply everything by 2 to get 6x = 18. If I had the equation -4x = -8, I could add 4x to both sides to get 0 = -8 + 4x and then I could add 8 to both sides to get 8 = 4x. A shortcut if you have an equation like -4x = -8, is to multiply both numbers by -1. So -4x times -1 is 4x and -8 times -1 is 8 (as a negative times a negative = positive). The step where I multiplied by -1, all the terms were negative, so I times everything by -1 to make them positive. (I also cheekily changed their order).