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another method is adding and subtracting 2 in the Numerator and then apply linearity
Solution:∫(e^x)/(e^x+2)*dx = ----------------Substitution: u = e^x+2 du = e^x*dx dx = du/e^x----------------= ∫(e^x)/u*du/e^x= ∫1/u*du = ln|u|+C = ln|e^x+2|+C
Am i banned from posting?
another method is adding and subtracting 2 in the Numerator and then apply linearity
Solution:
∫(e^x)/(e^x+2)*dx =
----------------
Substitution: u = e^x+2 du = e^x*dx dx = du/e^x
----------------
= ∫(e^x)/u*du/e^x= ∫1/u*du = ln|u|+C = ln|e^x+2|+C
Am i banned from posting?