NIB-Notation series - Part 48 - REACHING SUPER-BRACKETS!!
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- Опубликовано: 11 июн 2024
- Lucky user:
@eyelashmitefan20000
@GreeterRAC
@Bartek72491
@user-hh1dn7ti8n
@oleksandrhutsuliak1047
First music: Echoes - LFZ (Meikal Remix)
• LFZ - Echoes (Meikal R...
Second music: Lost - Kontinuum (feat. Savoi)
• Kontinuum - Lost (feat...
Motion backgrounds by @AAvfx , @FreeVideoBackgroundloops and @Freevideobacks :
Most of the background are "stolen" from Part 45-Part 47.
Additional from @Freevideobacks
• No Copyright Video, Ba...
• No Copyright Video, Ba...
• No Copyright Video, Ba...
• No Copyright Video, Ba...
• No Copyright Video, Ba...
• No Copyright Video, Ba...
• No Copyright Video, Ba...
===INFORMATION!===
Green = Birds Array Notation
Cyan = Bowers Exploding Array Function
Red = Casading-E Notation
Yellow = Strong Array Notation
For the pitch backgrounds:
Ordinal (from fgh)
Bashicu-Matrix System / Y-Sequence
Reference:
I arrange my notation based on this:onedrive.live.com/?authkey=%2...
Want to know how Birds Array Notation, Hyper-E notation, Strong-Array Notation and Fast-Hierarchy works?
Then check out this: googology.fandom.com/wiki/Goo...
or watch this:
• Ultimate Large Numbers...
Inspiration:
@notnt2048 : He made numbers -infinity to infinity series
@mathisr.v3627 : He is likely a friend of NO!
@FF2K24 : Very enthusiastic on making "Numbers 0 to TEON"
@PapyrusedMations : Another awesome fictional googology youtubers
@douglasshamlinjr.392 : Main sources of making this video
@BAT4423HGB : Subscribe to this channel
Join my discord server!:
/ discord
More videos coming soon!
Q: Why 69?
A: Because why not :P
Q: Where do you get the sound on intro?
A: Google Translate :)
Q: What the heck is that backgrounds from Intro 2.0?
A: That's actually NIBN-series from Part 1-30.
Me be like: *12 HOURS!? I CAN'T WAIT THIS 12 HOURS THO*
YES
nice.
The end of volume 3!
We've reached epsilon-zero in the fast-growing hierarchy!
Sorry, i missed premiere, i was at school :/
It's ok 😉
It 5.00am for me when u play
69(00)
= 1(10)
= 0((0)0)
= 1(01)
= 1(000)
= 1(00)
= 1(00)
= 1(00)
= 1(00)
= 1(00)
= 2(0,1)
69420(00)
Birds Array Notation/BEAF: {10, 69420 [1\2] 2}
Bowels Exploding Array Function: {10, 69420 ([1]1) 2}
Extended Casading-E Notation: E69#^^#138839
Strong Array Notation: s(10, 69420 {1`2} 2)
Fast-Growing Hierarchy: f_{ε₀}(138840)
Bashicu Matrix System: (0,0)(1,1)
Y-sequence: (1,2,4)
Hardy Hierarchy: H_{ε₀}(138841)
Slow Growing Hierarchy: g_ψ₀{Ω₂}(138840)
Hyperfactorial Array Notation: 69421![1, 1, 1, 1, 2]
X-Sequence Hyper-Exponential Notation: 100{X↑↑X}138840
Username5243's Array Notation: 100[0{0,₁1}1]69420
Dollar Function: 138840$[[0]₂] (probably...)
DeepLineMadom’s Array Notation: 100[1{1/2}2]69420
Me
me
Me
me
Me
69420(00) !!!!!!
Kelleson?😂
Yoo bro you have 61K views
I have 75K views❤😂
Now 82 thousand wiews
I got your tips and made a definiton, do you wanna see? (It's a bit complicated)
Sure!
@@The-creator-of-NIBN Here you go:
Base rule: If there's just a 0-dimension, n(0) = 10^n
Nesting rule: If the first dimension is a 0-dimension, 1(0)& = 69&, (n+1)(0)& = (n(0)&)& where & is the unchanged remainder of the expression
Catastrophic rule: Otherwise... (b = the number on the left of all dimensions)
1. Find the first dimension.
2. If the dimension on the right is smaller, or equal but not a 0-dimension, go there.
3. If it's a 0-dimension...
1. Delete it.
2. Go to the left of the dimension that you've just deleted.
3. If it's a single-dimension, get b copies of it, with each having the number in them one less than the original.
4. If it has two or more dimensions in it, and the first one is a 0-dimension, get b copies of it, with each having their first 0-dimension deleted.
5. If it's a double-dimension...
1. Copy it, and put the copy on the left of the original one.
2. Change the 0-dimension, in the copy, to b.
6. Otherwise...
1. Get a copy of the picked dimension.
2. Put the new dimension to the left of the picked one.
3. Apply this entire algorithm inside the new dimension.
4. If it's bigger than a 0-dimension, but only has a number in it...
1. Get b copies of it, with each having their number decreased by 1.
2. Replace the original dimension with the new ones.
5. If it has other dimensions in it...
1. If it has two or more dimensions in it, and the first one is a 0-dimension; Get b copies of that dimension with the first dimension in them being deleted, and replace the original dimension with the new ones.
2. If it only has a 0-dimension in it, replace it with b.
3. Otherwise, apply the entire algorithm inside that dimension.
6. Change b to 69.
7. End the process (all active algorithms).
@@The-creator-of-NIBN Here you go:
Base rule: If there's just a 0-dimension, n(0) = 10^n
Nesting rule: If the first dimension is a 0-dimension, 1(0)& = 69&, (n+1)(0)& = (n(0)&)& where & is the unchanged remainder of the expression
Catastrophic rule: Otherwise... (b = the number on the left of all dimensions)
1. Find the first dimension.
2. If the dimension on the right is smaller, or equal but not a 0-dimension, go there.
3. If it's a 0-dimension...
1. Delete it.
2. Go to the left of the dimension that you've just deleted.
3. If it's a single-dimension, get b copies of it, with each having the number in them one less than the original.
4. If it has two or more dimensions in it, and the first one is a 0-dimension, get b copies of it, with each having their first 0-dimension deleted.
5. If it's a double-dimension...
1. Copy it, and put the copy on the left of the original one.
2. Change the 0-dimension, in the copy, to b.
6. Otherwise...
1. Get a copy of the picked dimension.
2. Put the new dimension to the left of the picked one.
3. Apply this entire algorithm inside the new dimension.
4. If it's bigger than a 0-dimension, but only has a number in it...
1. Get b copies of it, with each having their number decreased by 1.
2. Replace the original dimension with the new ones.
5. If it has other dimensions in it...
1. If it has two or more dimensions in it, and the first one is a 0-dimension; Get b copies of that dimension with the first dimension in them being deleted, and replace the original dimension with the new ones.
2. If it only has a 0-dimension in it, replace it with b.
3. Otherwise, apply the entire algorithm inside that dimension.
6. Change b to 69.
7. End the process (all active algorithms).
@@The-creator-of-NIBN I will, but it doesn't work here, so I'll just put it on your discord server
@@XxXxX_Arandomguy_XxXxXwhere's the discord server
Why do you love the number 69420‽
Because of the combination between 69 and 420
Okay, but WHY the number 69 and 420? Like, it nice(pun intended) but why not 10, or 100, or heck, 1000. Why 69 and 420? Also, you need to formalize the notation too. Try to like, add a base to the notation or document it. Heck, you can post the notation to Googology Wiki too!
Volume 4 In FGH Is From Epsilon 0 to Gamma 0.
Well nope
It's from 69(00) to 69(0,1)
@@The-creator-of-NIBNso Epsilon 0 to Church Kleen Ordinal?
After analysing some numbers, I am now not sure what is 69(0,1) in BAN
@@The-creator-of-NIBNbut we are talking with FGH not BAN
Where is the 69420(0,1)?
That's still far away...
What comes after 69(00)?
There will be like
69(10)
69(01)
69(00)
...
How big is 69(0,1)?
Probably around {10,69 [1[1/(1,2)2]2] 2}
Please Change to June 12 at 12:00 PM now
What is beyond 1(0,_,_,_,_...1)?
Not decided yet
69(0`1)?
we are not even close to that number
YES