Support this course by joining Wrath of Math to access exclusive and early linear algebra videos, original music, plus the lecture notes used in my videos at the premium tier! ruclips.net/channel/UCyEKvaxi8mt9FMc62MHcliwjoin Linear Algebra course: ruclips.net/p/PLztBpqftvzxWT5z53AxSqkSaWDhAeToDG Linear Algebra exercises: ruclips.net/p/PLztBpqftvzxVmiiFW7KtPwBpnHNkTVeJc
You are the best! In my algebra classes i just write the topic then or sleep or play with my phone. I don’t listen to the teacher, just search the topic.
Ah, thank you for explaning this simple concept. Missed a few classes of linear algebra back in 12th grade and used to run away from linear algebra, Even had to revise matrix multiplication in my 4th semester as an ECE undergrad. We had a question on finding out rank of matrix in the midsem of an introductory course for Deep Learning, thanks for clearing this out sir !!
Thank god, ty man. My teacher just throws a bunch of pictures and has a lot of little comments that clutter and confuse the slides. This was clean, simple, and straight to it.
i have my math final exam tomorrow and i was always confused about how to find the rank, but now im very perfect with it and its all cause of you sir, THANKYOU SOO MUCH!!!
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
Great video! However, Regarding the last example, I think we need to reduce 3 to be 0, depending that we have a rule of all zeros except the pivot in any column.
There is a leading 1 directly below the -7, this prohibits the matrix from being in RREF, for which it is necessary that all leading 1s have 0s above and below them. Note a leading 1 is a leading nonzero entry in a row. So we would not say the leading entry of row 2 is the 0 in column 1, but rather the leading entry of row 2 is the 1 in column 2.
Love the video. However, I have one question. How is a zero matrix in RREF. Following rule #2 for REF, 'All zeros must be at the bottom of the matrix'. In example f, the first two rows are zeros, which should possibly violate rule #2 right? Thanks in advance!
Thanks for watching and for the question! By "at the bottom" we mean below all nonzero rows. For a zero matrix, every row is vacuously below all nonzero rows, because there are no nonzero rows. Does that make sense?
@@WrathofMath That makes complete sense now, thank you so much! I'd just like to add that this is probably the *BEST* video out there to understand REF and RREF. Your video on Gaussian Elimination is also literally the best one out there.
Thanks so much! I work very hard to create the most clear and helpful video on each topic - so to know I reach that goal at times is a great compliment!
example 'e' at 6:16 is actually NOT a RREF right? because the fourth column has 3 1 0 0, so other than 1 and 0s there is also a 3. You said it's a RREF and my guess is that it's actually just REF :|
Thanks for watching and what I said is correct. The reason is that we only need 0's in columns with leading 1s. If a column contains a leading 1, all other entries must be 0s. But column 4 has no leading 1, does that make sense?
You are correct that the final answer is in row echelon form, that was our goal. To get it in RREF, we'd subtract 3*R2 frmo R1, to turn the 3 into a 0. Also, the second to last matrix we had (I might have said this in the video) is in REF according to some definitions which do not require leading 1s for REF.
The 4th column does not contain a leading 1 because a leading 1 is a 1 that, in its row, is the first nonzero entry. Only columns 1 and 2 of matrix d contain leading 1s.
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
Two reasons 1) RREF has requirements about leading 1s. Since this matrix has no leading 1s, there is certainly nothing violating the conditions about leading 1s. 2) RREF requires zero rows to be "at the bottom" but more formally what we mean by "bottom" is below all the nonzero rows. So trivially this property is fulfilled also. Does that help?
Same. According to RREF definition it is not RREF, because the leading 1 on the last column is not accompanied by zeroes evertwhere else, because the leading 1 is accompanied by the number 4. The rules seem to be very clear so it must be a mistake.
Thanks for watching and for the question! C4 does not contain a leading 1 because the 1 in C4 is the not the first nonzero entry in its row. The first nonzero entry in its row is located in C1, so it is C1 which contains a leading 1.
1) Any rows of zeros are below all other rows 2) Every nonzero row has 1 as its leading entry 3) Each leading 1 occurs further to the right than the 1 in the row above it 4) Each column containing a leading 1, has 0s everywhere else
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
Support this course by joining Wrath of Math to access exclusive and early linear algebra videos, original music, plus the lecture notes used in my videos at the premium tier!
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Linear Algebra course: ruclips.net/p/PLztBpqftvzxWT5z53AxSqkSaWDhAeToDG
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This Video saved me to a great extent in my Linear Algebra course.
Glad to help - thanks for watching!
Did you go on to take another math class after that?
@@PunmasterSTP yes had a prob & stat course after that.
@@academicstuff548 That's cool! How'd you like it?
You are the best! In my algebra classes i just write the topic then or sleep or play with my phone. I don’t listen to the teacher, just search the topic.
Ah, thank you for explaning this simple concept.
Missed a few classes of linear algebra back in 12th grade and used to run away from linear algebra, Even had to revise matrix multiplication in my 4th semester as an ECE undergrad.
We had a question on finding out rank of matrix in the midsem of an introductory course for Deep Learning, thanks for clearing this out sir !!
Glad to help - thanks for watching and good luck!
why the hell am i studying this in 1st year bachelor of business administration
Don’t worry….I’m in 1st Sem of masters…and I’m still stuck on this😂
While I'm studying this in my junior class😊
@@zion932I have to study this as a Freshman LOL
@@tactixianchess1409 it was kinda tiring part.
😂😂😂
Thank god, ty man. My teacher just throws a bunch of pictures and has a lot of little comments that clutter and confuse the slides. This was clean, simple, and straight to it.
Glad to help, thanks for watching!
i have my math final exam tomorrow and i was always confused about how to find the rank, but now im very perfect with it and its all cause of you sir, THANKYOU SOO MUCH!!!
Glad it helped, good luck!
Great video!
I am an engineering student and this video helped me a lot, thank you.
Awesome - thanks for watching!
Thanks so much for explaining. I was getting different answers when I didn’t do it a certain way
2:47
If you were my teacher I would never miss your class ❤️tqsm
The best lesson😢😢😢😢i have ever found on the internet
Thank you! Many more in my linear algebra playlist
Currently taking a franken-class of linear algebra and multivariable calculus concepts with R. This cleared up so much confusion. Thank you!
What course are you doing?
Dang, that sounds like an intense class! What is it called and what degree are you going for?
In the example(e.) is not in RREF ,because there is a 3 in the 4th column above 1.
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
thanks so much for explanation i thought the same as him@@JakubMazur-v5s
this cleared up the topic so much, thank you!
Thanks for the video. It was super helpful.
Glad it was helpful!
You are great ❤ ... Thanks for explaining this complicated topic so easily.
Glad to help - thanks for watching!
am an engineering student and this video helped me a lot, thank you.
Glad to help, thanks for watching;
Thank you, the explanation was so understandable and simple
Great video! However, Regarding the last example, I think we need to reduce 3 to be 0, depending that we have a rule of all zeros except the pivot in any column.
Thank you, sir!
Nice class sir
Why is d. in row echelon form? The fourth row has a leading 4
u r outstanding in teaching Algebra
Thank you!
Thank you good sir. My professor has a speech impediment (inability to share his information with his students efficiently or at all)
My bro gonnah hipnotise us with those baby blues
🔵 🔵
Thanks for these videos.But i have question how d is in rref when last column has leading 1 but the other entry is 3?
I have the same question.
exactly. I think he was wrong. you need to reduce the 3 to be 0 as well.
Thanks sensei. I'm just a night here before the exam
Easy and excellent explanation
Thank you! Doing my best to explain all of Linear Algebra!
From where did you learn to explain? you're very good at it.
thank you
Glad to help, thanks for watching!
hiiii this helped a lot thank you sm for making those videos!
Glad to help!
Thank you..
you saved my life for my tomorrow exam thank you
Happy to help, good luck!
Thank you so much! I finally understood it.
Awesome, thanks for watching!
good explanation
Thank you!
You’re a saviour!
Glad to help!
THANK U SO MUCH
THANK YOU FOR WATCHING
Love from India
Thanks, love back from Cape Cod, USA!
Thank you so much from Myanmar 🇲🇲😭❤️
Thanks for watching!
thank you sir
it was very helpfull tnx teacher
You are welcome! Glad it helped!
bro just skipped the boring part and gave us the ultimate explanation
Thank you for this.
Glad to help!
Thank you ❤
Welcome!
Nice video! 😊
Thank you Ezra! Looking forward to building my Lin Alg playlist this year!
Thank you Brother
Glad to help - thanks for watching!
thanks mate!
You're welcome!
thanks
Thank you ... good explanation :))
Glad to help - thanks for watching!
Wow thnks vry helpful.
Glad to help - thanks for watching!
Thanks bhaiya 😀😊
g at 6:56 is in RREF. The -7 is not in the column with a leading 1. The 1 and -7 are in the same row not columns.
There is a leading 1 directly below the -7, this prohibits the matrix from being in RREF, for which it is necessary that all leading 1s have 0s above and below them. Note a leading 1 is a leading nonzero entry in a row. So we would not say the leading entry of row 2 is the 0 in column 1, but rather the leading entry of row 2 is the 1 in column 2.
this was equivalent 5 lectures of linear algebra
Row echelon form? More like "Really awesome videos; you're taking the math world by storm!" 👍
Will you make a video about explaining the definition of a determinant in depth
Yes I will - I will be working on lots of lin alg this summer!
Love the video. However, I have one question. How is a zero matrix in RREF. Following rule #2 for REF, 'All zeros must be at the bottom of the matrix'. In example f, the first two rows are zeros, which should possibly violate rule #2 right? Thanks in advance!
Thanks for watching and for the question! By "at the bottom" we mean below all nonzero rows. For a zero matrix, every row is vacuously below all nonzero rows, because there are no nonzero rows. Does that make sense?
@@WrathofMath That makes complete sense now, thank you so much! I'd just like to add that this is probably the *BEST* video out there to understand REF and RREF. Your video on Gaussian Elimination is also literally the best one out there.
Thanks so much! I work very hard to create the most clear and helpful video on each topic - so to know I reach that goal at times is a great compliment!
TY
Hey how do i get the notes of this video lectures?
“Each column containing a leading one has a zero in all its other entries” but example d does not qualify this
example 'e' at 6:16 is actually NOT a RREF right? because the fourth column has 3 1 0 0, so other than 1 and 0s there is also a 3. You said it's a RREF and my guess is that it's actually just REF :|
Thanks for watching and what I said is correct. The reason is that we only need 0's in columns with leading 1s. If a column contains a leading 1, all other entries must be 0s. But column 4 has no leading 1, does that make sense?
@@WrathofMathI had this question as well, thanks for clarification
9:53 so the final answer here is in row echelon form right? So if we need a RREF , we should convert that three into 1. Am i correct?
You are correct that the final answer is in row echelon form, that was our goal. To get it in RREF, we'd subtract 3*R2 frmo R1, to turn the 3 into a 0.
Also, the second to last matrix we had (I might have said this in the video) is in REF according to some definitions which do not require leading 1s for REF.
Its great
But is it must that the leading entry be 1 for row echolon form ?
It depends on the author. Howard Anton's elementary linear algebra is the textbook for my playlist, and it requires 1s.
I still do not get the e because in the 2nd to last column, there was a 3 above the 1 and this means it doesn't satisfy the 4th condition
In the last column of d part we have a leading 1 and other element is not zero, then how is it a rref?
It is not a leading 1 because it is not the first nonzero entry in its row
you make things so difficult
Lmao😂😂😂😂
d is not in RREF as 4th column has a leading 1 but other entry in 4th column is 4 instead of 4 so it is not in RREF
The 4th column does not contain a leading 1 because a leading 1 is a 1 that, in its row, is the first nonzero entry. Only columns 1 and 2 of matrix d contain leading 1s.
in e example the 4th column contains 3 so that is not in row reduced echelon form
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
All properties need to be satisfies ??
4:22 in this section the the b) is rref . Can you give me the linear equations of this rref ?
Can u pls explain again why f is a RREF bcs its fully 0
Two reasons
1) RREF has requirements about leading 1s. Since this matrix has no leading 1s, there is certainly nothing violating the conditions about leading 1s.
2) RREF requires zero rows to be "at the bottom" but more formally what we mean by "bottom" is below all the nonzero rows. So trivially this property is fulfilled also.
Does that help?
6:06 i still dont get why 4 is rref
Same. According to RREF definition it is not RREF, because the leading 1 on the last column is not accompanied by zeroes evertwhere else, because the leading 1 is accompanied by the number 4.
The rules seem to be very clear so it must be a mistake.
in d question we have a leading one in c4 but the other entry is 4 so how is it in rre form
Thanks for watching and for the question! C4 does not contain a leading 1 because the 1 in C4 is the not the first nonzero entry in its row. The first nonzero entry in its row is located in C1, so it is C1 which contains a leading 1.
can anyone please explain why why d and e part is in RREF form at 7:00
1) Any rows of zeros are below all other rows
2) Every nonzero row has 1 as its leading entry
3) Each leading 1 occurs further to the right than the 1 in the row above it
4) Each column containing a leading 1, has 0s everywhere else
Clap for yourself
Can you link the video to Gaussian Elimination please- can’t seem too find it in the description
ruclips.net/video/seet9VyHo3Q/видео.html
What about d bro
Which one is the anton textr
amzn.to/43xAWEz
Homie graduated from Yap University 💀
fr
how could e. be RREF ? 4th column contain 1 and 3
Yes but it doesn't contain a leading 1, so it doesn't need to be all zeroes.
1:14 We don't care about what WekaPidEA said
e is not in RREF
i think same because 4th column contain 1 and 3
But the 1 in the 4th column of 2nd row is not a leading one. The leading 1 of the 2nd row is placed in a 3rd column that doesn't have any non-zero values in it ;) Thus it is actually RREF
Bacholer of science PMC
you got one question wrong!!!!!
which?
@@WrathofMath
nah sorry bro, i got it wrong myself, great video tho, i liked the video
1st year b tech student here😅
That's awesome - thanks for watching and good luck!
You look like carl of mr beast
Too bookish. I need more natural and intuitive.
extremely poor explanation TBH
Thank you
You're welcome!
thanks.
My pleasure - thanks for watching!
Thank you
You're welcome!