i want to say please correct in visual side the function f = y3 is correct but after some time seeing tube just 4th slide second step in blue color it appears y2 please correct it
It's something that if you spend a little time to reconizing what basic curves look like (y=x^2, y=x, (y=sqrt(x)/ y=x^1/2), y=e^x, etc) its easy then to identify curves as he did. Also, think about it, y(2) = sqrt(2) and y(4)= (sqrt(4)= 2) in which the graph shows just that thus you got a function that is y=sqrt(x) Hope that helps.
@@burningzombiez It's just a bit confusing because in a previous example on another video the bounds are obtained using the values from the given vector F instead.
Best Green Theorem explanation video ever!! Cheers
Thank you for saving my exam
Thank you. Your videos are very clear and very helpful.
Very useful video, cheers from Brazil!
Your videos are great! Keep up good work.
thanx alot ..
please keep making vids like these ..
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Excellently explained
why did you change your notation in this vid,instead of using the same notation as the first greens therom vid? i love your videos,very helpful.
i want to say please correct in visual side the function f = y3 is correct but after some time seeing tube just 4th slide second step in blue color it appears y2 please correct it
in the first example how did you know that the curve C3 is y=sqrt(x)?
iwas thinking the same too lol
It's something that if you spend a little time to reconizing what basic curves look like (y=x^2, y=x, (y=sqrt(x)/ y=x^1/2), y=e^x, etc) its easy then to identify curves as he did. Also, think about it, y(2) = sqrt(2) and y(4)= (sqrt(4)= 2) in which the graph shows just that thus you got a function that is y=sqrt(x) Hope that helps.
@@burningzombiez It's just a bit confusing because in a previous example on another video the bounds are obtained using the values from the given vector F instead.
thanks, it was very useful
extremely helpful!
Thank you!
THANKS A LOT
thanks for the vedio