Good info..I'm a new at this and trying to learn exactly what your video is about. I tried to copy all your formats but towards the end your camera work prevented me from doing so. I followed up until you got into wattage of the resistor. Suggestion.....take wider views of what you're doing so we can see the whole picture. Thanks for you help
"Thank You", thank you very much 😀 Your presentation/video was REALLY great, but I got lost, when you put 2 x 1k resistors in parallel 🤔 I thought 1x 1k resistor would be ALL you would need 🤔🤔 Let me know, I look forward to hearing from you 😎😀😎
Do you know if I can tap off of a existing LED on a circuit board to anther LED to view at a different location...about 3 foot away ? Is wire size important ? Thanks
The answer depends on the LED & copper that you use. Not all LEDs work at the same voltage & draw the same amount of current. Therefore, your circuit *may* need to be modified to support your new device & the additional resistance of the 3 ft wire. You *may* need to change the current limiting resistor or increase the source voltage/power. In general, higher loads create more voltage drops & use more of the available supply voltage & power. Having typed all of that ^^, it is also possible that your circuit card is powered by a power supply that has sufficient current to support another LED of the same type --although, it may cause both LEDs to run dimmer when connected in series or in parallel with your other LED/s--although not necessarily--a lot depends on how much of the available power is being drawn from your existing power source.
What if one of your led has a different voltage drop ? How would you use the formula then? Or do you have to wire it differently like in its own series circuit?
hello there. i am using 10 red 5mm led's in parallel on 5V with 15ohm 2W resistor but the resistor is heating up like crazy. i measured the voltage drop on this type of led its exactly 2V. is there anything else that i should know that's making my resistor to heat up? should i calculate the wattage of the resistor using the original 5V or the (power supply output voltage - voltage drop on the led) ?
the bottom value should be in brackets also (0.02 x 3) then (0.02 x 9) for the next sum. If your calc doesnt come up with the right answer make sure you do this.
Jason Robicheau Look up the formula for calculating resistance in parallel. He's assuming a 2V voltage drop on a 5V circuit which means he's assuming the LED uses 3V (i.e. 5V-2V=3V). Using Ohm's law we can calculate the resistance of the LED at (3V/.02A=150Ω). Treat those LEDs in parallel as 150Ω resistors when doing your calculations. If you have a LED that has a different voltage drop, calculate it's resistance & then add it according to the formula for calculating resistance in parallel & that should work for you.
Thanks a lot, Mr.Cody. Your video is very much helpful.
Hello Cody, This is a great tutorial and has helped me a lot. Thank you very much.... John :)
Thanks a lot :) really helpful and very concise vid
Thank you!
Good info..I'm a new at this and trying to learn exactly what your video is about. I tried to copy all your formats but towards the end your camera work prevented me from doing so. I followed up until you got into wattage of the resistor. Suggestion.....take wider views of what you're doing so we can see the whole picture. Thanks for you help
Great video thanks
"Thank You", thank you very much 😀 Your presentation/video was REALLY great, but I got lost, when you put 2 x 1k resistors in parallel 🤔 I thought 1x 1k resistor would be ALL you would need 🤔🤔 Let me know, I look forward to hearing from you 😎😀😎
does the watt need to be close to the what you need for the lights or can they much higher?
is the 10 volt you calculating to find the watts of the resistor is the the volt drop
Do you know if I can tap off of a existing LED on a circuit board to anther LED to view at a different location...about 3 foot away ? Is wire size important ?
Thanks
The answer depends on the LED & copper that you use.
Not all LEDs work at the same voltage & draw the same amount of current.
Therefore, your circuit *may* need to be modified to support your new device & the additional resistance of the 3 ft wire. You *may* need to change the current limiting resistor or increase the source voltage/power. In general, higher loads create more voltage drops & use more of the available supply voltage & power.
Having typed all of that ^^, it is also possible that your circuit card is powered by a power supply that has sufficient current to support another LED of the same type --although, it may cause both LEDs to run dimmer when connected in series or in parallel with your other LED/s--although not necessarily--a lot depends on how much of the available power is being drawn from your existing power source.
What if one of your led has a different voltage drop ? How would you use the formula then? Or do you have to wire it differently like in its own series circuit?
can you make a video on how to make a led booster circuit, so if you had less voltage you could still power 9 leds
hello there. i am using 10 red 5mm led's in parallel on 5V with 15ohm 2W resistor but the resistor is heating up like crazy. i measured the voltage drop on this type of led its exactly 2V. is there anything else that i should know that's making my resistor to heat up? should i calculate the wattage of the resistor using the original 5V or the (power supply output voltage - voltage drop on the led) ?
what need to be fixed the watts of the resistor or the ohms of the resistors?
the bottom value should be in brackets also
(0.02 x 3) then (0.02 x 9) for the next sum.
If your calc doesnt come up with the right answer make sure you do this.
how low of the resistor can i use from the require amount
How would you find the voltage dropped in the formula R=(Vs-"Vd").
How is it calculated when you got individuals resistors
Check my other video
Jason Robicheau Look up the formula for calculating resistance in parallel.
He's assuming a 2V voltage drop on a 5V circuit which means he's assuming the LED uses 3V (i.e. 5V-2V=3V). Using Ohm's law we can calculate the resistance of the LED at (3V/.02A=150Ω). Treat those LEDs in parallel as 150Ω resistors when doing your calculations. If you have a LED that has a different voltage drop, calculate it's resistance & then add it according to the formula for calculating resistance in parallel & that should work for you.
ok, so how would you do 126 led's??
use the formula