Hi teacher how I can solve difficult problems about boiling point elevation, freezing point depression, osmotic pressure and vapour pressure? Please answer this question
It would be the total molality of ALL of the solutes - note that if it is an ionic compound that completely disociates, you might need to multiply it by a factor - for example, MgCl2 would break into three ions so its amount would have a triple effect.
@@JonBergmann1 okay, say for example I have etyhlene glycol and MgCl2 solved in water. I have 200 g glycol and 200 g MgCl2 and 600 g of water. Could I do like this: 200g glycol/62.07 (molar mass)=3.2. It has i factor=1 so then I take 3.2/0.6 (water in kg)=5.4. Then I multiply that with 1.86 (constant for water) and get 10 degrees. Then I do the same thing for MgCl2 but use I factor= 3 instead. So 200/95=2.1 moles. 2.1/0.6 times 1.86 times 3 which is 20. Then I add 20 to 10 and get 30. So the frezzing point should be 0-30=-30. Is this correct?
Hey my good sir! This video is very informative, I'd like to thank you for that. But can you do something about the screeching of the pen? Thanks hehehe
Kf of water is 1.86 not 0.51 because 0.51 is its Kb
Clear and straight to the point. Thanks for that, I appreciate teachers like you :]
this is incredible, excellent teaching style. thank you sooooooooo much
Glad it was helpful. Have a great day
i feel like i'm being taught by mr bean :D
That was my first thought when I saw him!!
Exactly
u guys are dicks lol
Kf of water is 1.86
Kf is 1.86 :)
I agree with you
yea even now Idek why he didnt do Kb...)
U are the greatest of all time
I'm soooo amazed how this guy's writing backwards in a readable handwriting and also he looks like Mr. bean HAHAHA
Many have said that I look like Mr. Bean? LOL
Kf of h2o is 1.86 not 0.51...
Yes you are right
Thanks, Sir. You are great
Thank you! Helped for my pre-exam studying
Glad it helped!
Hi teacher how I can solve difficult problems about boiling point elevation, freezing point depression, osmotic pressure and vapour pressure?
Please answer this question
What do you do if you have two solvents mixed with water. Can you calculate them by their own using blagdens law. Or do you do something else
It would be the total molality of ALL of the solutes - note that if it is an ionic compound that completely disociates, you might need to multiply it by a factor - for example, MgCl2 would break into three ions so its amount would have a triple effect.
@@JonBergmann1 okay, say for example I have etyhlene glycol and MgCl2 solved in water. I have 200 g glycol and 200 g MgCl2 and 600 g of water. Could I do like this: 200g glycol/62.07 (molar mass)=3.2. It has i factor=1 so then I take 3.2/0.6 (water in kg)=5.4. Then I multiply that with 1.86 (constant for water) and get 10 degrees. Then I do the same thing for MgCl2 but use I factor= 3 instead. So 200/95=2.1 moles. 2.1/0.6 times 1.86 times 3 which is 20. Then I add 20 to 10 and get 30. So the frezzing point should be 0-30=-30. Is this correct?
@@tysken0251 yes - well done
Hey my good sir! This video is very informative, I'd like to thank you for that. But can you do something about the screeching of the pen? Thanks hehehe
how is he writing backwards
I'm not, I simply use software to do a horizontal flip after shooting the video
Sir thats the 0.51 is kb not kf.
Kf is -1.86
good catch