Alkenes & Alkynes Oxidation Reduction and Oxidative Cleavage

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  • Опубликовано: 29 окт 2024

Комментарии • 77

  • @alisonhenley1365
    @alisonhenley1365 6 лет назад +12

    still a little confusing, but we are getting there. Thanks Leah! I think oxidation just isnt my thing haha. But like you said, if you see each pi bond as an oxygen that will be formed, it makes more sense.

    • @Leah4sci
      @Leah4sci  5 лет назад

      Glad the video helped you understand the topic better! You are very much welcome!

  • @roll96shreyashimukherjee32
    @roll96shreyashimukherjee32 6 лет назад +2

    This is short and precise. Good for revision. Thank you , Leah.

    • @Leah4sci
      @Leah4sci  10 месяцев назад

      You're so welcome!

  • @lingshaju8100
    @lingshaju8100 Год назад

    Thank you for the amazing videos. It's really helpful for my MCAT preparation🤩

    • @Leah4sci
      @Leah4sci  Год назад

      You're very welcome!

  • @thynguyen911
    @thynguyen911 8 лет назад +2

    Thank you!! You're very good at explaining!!

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      You're so very welcome!

  • @ToniAnn65
    @ToniAnn65 6 лет назад +7

    a level chemistry is so hard... being a science student is hard

    • @Leah4sci
      @Leah4sci  5 лет назад +4

      Don't give up! keep pushing! :)

    • @akshayyadav6331
      @akshayyadav6331 5 лет назад +5

      Come to india 😂😂😂😂 then u think being science student in their is so easy ..

    • @priyadarshanam1524
      @priyadarshanam1524 4 года назад +3

      @@akshayyadav6331 damn 😂😂

    • @aydaabdolmanafi
      @aydaabdolmanafi 10 месяцев назад

      Being a pharmacy student is a bigger challenge 😢

  • @favourafolabi9589
    @favourafolabi9589 3 года назад

    Thanks for the step by step explanation

    • @Leah4sci
      @Leah4sci  3 года назад

      You're so welcome!

  • @danielmwanamonga6880
    @danielmwanamonga6880 11 месяцев назад

    I have a question 🤧... I've watched the video but kinda failed to apply the concept.. I don't know where I'm missing it
    Reacting octene(C8 H16) with KMnO4 under hot basic conditions giving propanoic acid and pentanoic acid.. but according to your video, reacting an alkene with KMnO4 should give an alkene and carboxylic acid

    • @Leah4sci
      @Leah4sci  11 месяцев назад

      In my example for oxidative cleavage using KMnO4 in hot basic conditions, we had an alkene that was di-substituted on one side of the pi bond. That meant one side, when cleaved, was unable to oxidize any further than a ketone. In your example, if you're cleaving 1-octene, neither side is di-substituted which leaves room for further oxidation.

  • @inspiritinfinite1091
    @inspiritinfinite1091 6 лет назад

    Thanks so much your video really helped me.. I don't know what I would have done without you:(

    • @Leah4sci
      @Leah4sci  6 лет назад +1

      You're welcome!
      Glad I could help!

  • @hassanbasrimohdhusaini8044
    @hassanbasrimohdhusaini8044 7 лет назад +1

    Helps a lot, thanks!

  • @anishabisht4213
    @anishabisht4213 5 лет назад +1

    2:58 so if addition of these 3 won't show oxidation, then these also won't show reduction too right?

    • @Leah4sci
      @Leah4sci  4 года назад

      Correct. There is no net effect on the oxidation state of the molecule by the addition of a water molecule, alcohol or hydrogen halide to an alkene.

  • @durianicecream5132
    @durianicecream5132 8 лет назад +2

    8:03 when using KMnO4 to form CO2 the reaction condition is hot and acidic?

    • @priyadarshanam1524
      @priyadarshanam1524 4 года назад +1

      Yes, but I think I'm 4 years late 😅

    • @Leah4sci
      @Leah4sci  7 месяцев назад

      Hot and basic, then you acidify in the next step

  • @sophiaaaa777
    @sophiaaaa777 11 месяцев назад

    oh my gosh that was amazinggggg

    • @Leah4sci
      @Leah4sci  11 месяцев назад

      So glad you enjoyed it!

  • @tamilbiology5078
    @tamilbiology5078 3 года назад

    Upload a video on kmno4 mediated oxidation of alkenes with mechanism please mam

    • @Leah4sci
      @Leah4sci  2 года назад

      For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

  • @mantis2048
    @mantis2048 6 лет назад +1

    You drew the syn addition as anti addition

    • @Leah4sci
      @Leah4sci  6 лет назад

      At which specific point in the video?

  • @dvkreddychem
    @dvkreddychem 3 года назад

    Love u your teaching madam

  • @abdullahjj3464
    @abdullahjj3464 8 лет назад +2

    thank you so much

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      You're so welcome!

  • @al23057374
    @al23057374 8 лет назад +1

    well said

  • @lamcato5700
    @lamcato5700 7 лет назад +1

    thank you

  • @davidoppong441
    @davidoppong441 2 года назад

    thanks 😊

  • @jjvaldes100
    @jjvaldes100 8 лет назад +1

    Thank you🙌👍.

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      You're so welcome!

  • @lamcato5700
    @lamcato5700 7 лет назад +1

    nice video

  • @hubbiemid6209
    @hubbiemid6209 3 года назад

    3:56 isnt that is a trans diol if u rotate the bond

    • @Leah4sci
      @Leah4sci  3 года назад

      If we considered the rotation of sigma bonds, then no diol would every be considered cis or trans. In saying this is a syn diol, I am trying to communicate that the alcohol groups are added to the same side of the alkene. It’s more about the mechanism of the addition, rather than the final structure itself.

  • @joycelynwesoamo9954
    @joycelynwesoamo9954 7 лет назад +1

    Every Good

    • @Leah4sci
      @Leah4sci  7 лет назад

      glad you enjoyed it!

  • @meera-m7734
    @meera-m7734 4 года назад

    how does cl and H cancel out?

    • @Leah4sci
      @Leah4sci  4 года назад

      Thanks for asking! Halogens, just like oxygen, are highly electronegative and considered to be strong oxidizing agents. Therefore, in a hydrohalogenation reaction, one carbon of the pi bond is oxidized by the addition of a bond to a halogen while the other carbon is reduced by the addition of a bond to hydrogen. The oxidation and reduction cancels out and does NOT affect the overall oxidation state of the molecule.

  • @idriabdullah3838
    @idriabdullah3838 3 года назад

    you are amazing

  • @imperilazanotti4056
    @imperilazanotti4056 8 лет назад

    thank you very very clear explanation and also you have the same voice as selena gomez hahaha keep going ;)

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      I take that as a compliment, thanks! And you're very welcome!

  • @skiddies9634
    @skiddies9634 3 года назад

    When your exam is in half an hour

    • @Leah4sci
      @Leah4sci  3 года назад

      How did your exam turn out?

    • @skiddies9634
      @skiddies9634 3 года назад

      Very good! I'm pretty confident in the rest of the topics, this is the only one I specifically struggle with and your video really helped. Thank you so much!

  • @fabriany
    @fabriany 8 лет назад +1

    Excelente! :)

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      thank you!

  • @shwethadharmalingam8931
    @shwethadharmalingam8931 8 месяцев назад

    12:23

    • @Leah4sci
      @Leah4sci  8 месяцев назад

      Did you have a question about this?

    • @shwethadharmalingam8931
      @shwethadharmalingam8931 8 месяцев назад

      Oh no I just noted down the time stamp so that I could go back to it if I forgot how the reaction worked. Thankyou for asking! @@Leah4sci

  • @052_p.siddeshwargoud8
    @052_p.siddeshwargoud8 3 года назад

    Bokka

  • @mamtashukla1806
    @mamtashukla1806 3 года назад

    for jee aspirants its a joke

    • @Leah4sci
      @Leah4sci  3 года назад

      Not sure what you mean

  • @gorlemularaju5665
    @gorlemularaju5665 7 лет назад +1

    thank you mam

    • @Leah4sci
      @Leah4sci  10 месяцев назад

      You're welcome!

  • @te083tejaspatil8
    @te083tejaspatil8 7 лет назад +1

    thank you mam

    • @Leah4sci
      @Leah4sci  10 месяцев назад

      You are welcome!