Bob Ross doesn't repeat himself.. Bob Ross.... Rossss... doesn't repeat... doesn't.... doesn't repeat... repeat himself... himselfff... him..... selff.... like this.
0:52 - a good way to notate the negative symbol is to understand that the negative means from numbers less than the limit value (left to right), whereas the positive symbol notates the numbers greater than the limit value (right to left -opposite of reading)
pianolearnen its simple the question ask the limit from the right so pick a number slightly higher than 0 in this case you could choose half It will -2(1/2)+1= -1+1
I know this thread is old, but the limit of -2x+1 as x-> 0 is 1. Lincoln mercedes gave the answer for the limit as x-> 1/2. That's a long distance from 0. Try finding the limit at 0.0001 (from right) and -0.0001 (from left). The answer is 1. If you graph it, you can clearly see that as x approaches 1/2 then y approaches 0, and as x approaches 0, y approaches 1. www.desmos.com/calculator/uuv9qxdddt
![Megan Thee Stallion - Mamushi (Remix) [feat. TWICE] [Official Audio]](http://i.ytimg.com/vi/5c0_u9PsrsQ/mqdefault.jpg)
Your voice is so chill. You're like the Bob Ross of math.
Bob Ross doesn't repeat himself.. Bob Ross.... Rossss... doesn't repeat... doesn't.... doesn't repeat... repeat himself... himselfff... him..... selff.... like this.
This!! It fits perfectly
@@VndNvwYvvSvvLOL
at 5:29 shouldn't it be -5 instead of 5
Thank you I was wondering if I didn't understand something or it was just a simple mistake
he meant negative five and said it and wrote it in both other places but its good to know even maths experts make mistakes haha!
Still not fixed this 8 years later lol
0:52 - a good way to notate the negative symbol is to understand that the negative means from numbers less than the limit value (left to right), whereas the positive symbol notates the numbers greater than the limit value (right to left -opposite of reading)
5:28 the limit is negative 5 ;) Great video btw !
oh thanks i thought im getting dumber
lol this was tripping me up i had to check the comments to be sure 🥲
omg thank you so much...now i finally understand what’s going on in my precal class
Thanks, great man. Useful for me. Nice lecture. God bless you.
JazakAllāhu Khayrun
Easy understand and good teaching👍
Explained it 100x better than my textbook did, thanks!
Easy to understand and very helpful👍
God bless you Khan
Thank you this is very helpful I really understand it now (:
This was great, easy maths
Thx that was so helpful :)
This really helped me. Thanks! :)
Thank you for posting this vid! It helped me a lot :)
This channel give me a lot
thanks, this video is great!
Tysm it helped!
thank you
Finally I got this
0:21 NEIN NEIN NEIN NEIN NEIN NEIN NEIN NEIN NEIN
Thank you for bringing comedy into my life during the terrible time i am currently having trying to learn calc during a pandemic
is that what all the one-sided limit about???
i mean it wont be any harder?
what about the previous examples? the previous discontinued graphs that had no limit? if this is applied do they have limits?
When the limit of both left and side are not equal doesn't that also mean that the function is not continued
You saved me
Thanks! (What grade is this on Kahn Academy?)
My sub box says its learning time!
Sadly I still didnt get it....
Im still confused
What is the limit as x -> 0 from the right of [-2x + 1]? the answer is 0 apparently but i keep getting 1.
pianolearnen its simple the question ask the limit from the right so pick a number slightly higher than 0 in this case you could choose half
It will -2(1/2)+1= -1+1
I know this thread is old, but the limit of -2x+1 as x-> 0 is 1. Lincoln mercedes gave the answer for the limit as x-> 1/2. That's a long distance from 0. Try finding the limit at 0.0001 (from right) and -0.0001 (from left). The answer is 1. If you graph it, you can clearly see that as x approaches 1/2 then y approaches 0, and as x approaches 0, y approaches 1. www.desmos.com/calculator/uuv9qxdddt
man i think im in luv with u
Thank you for the vid. I understood perfectly 👌
RIP X
Watching after the test 😥
I thought that limits don't exist at sharp points?
iSayMonica There should be no limit at four because that is a sharp point gj Khan Academy always can trust u
+iSayMonica Wrong. There defiantly CAN be a limit at a sharp point. You're thinking of a derivative. You can't differentiate a sharp point.
Literally still don’t understand
I love u
This guy is a broken record lol