regarding u(t), it's not the impulse signal we are deriving... It's the response of the impulse signal i.e, that expression which we are getting, which is valid at t>=0
To anyone who is reading this, I have a question. At 2:54 , she said the laplace transform of del(t) is 1. But I thought the impulse test signal, del(t)=1 for t=0 while del(t)=0 for t =/= 0. So the laplace transform is supposed to be 1/s for t=0. Right?
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Shouldn't the final response c(t) be c(t)=1/tau e^-t/tau u(t)?
yep
I am Very Thankfull to you maam ☺☺
impulse signal is =1 for t=0 how we take the value of u(t) for t> or equal to 0 ? time 5:48
and why donot the a is replaced by the 1/tow ?? time 6:00
She forgots, perhaps?
regarding u(t), it's not the impulse signal we are deriving... It's the response of the impulse signal i.e, that expression which we are getting, which is valid at t>=0
Good lecture ❤
what was the main significance of tow..
tow is nothing but a constant nothing more than that
Be constant my friend.
Time Constant
4 semester ka syllabus hai
How to find Steady state error (ess)?
Why tuo taking outside before partial fraction there no use!!!
Because we want to fit c(s) into standard inverse laplace transform formula
To anyone who is reading this, I have a question. At 2:54 , she said the laplace transform of del(t) is 1.
But I thought the impulse test signal, del(t)=1 for t=0 while del(t)=0 for t =/= 0. So the laplace transform is supposed to be 1/s for t=0. Right?
ruclips.net/video/hmvAukGi6sA/видео.html
laplace transform of impulse function is 1 just remember it
in that video, she was wrong...u check for del(t) at t=0....It's integration is 1...
Thank you
where are you from
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