Yes both have same cross section length and inclination with global axis so values of stiffness matrix elements will not change, but the orientation of both members is opposite this will change the sign.
It's done member wise and what are the nodes associated with that member. Watch @ 1:40 Also refer previous video ruclips.net/video/vuqdVhxcSiw/видео.html
@@Kirank-81 is the angle going to the 1st quadrant? Like for example if I have an angle of 45 from the 2nd quadrant. I will subtract it from 180 and it will be 135 angle? Is that right?
Very useful. Thank you 🙏🏻
Nicely explained ... 👍
thank you!
I am confused with matrix of member 6. On the signs. Can you please explain. Thank you
Member 6 is inclined at a angle of 50.1° and hence substitute theta=50.1° to find cos(c) sine(s) &cos*sin(cs) terms.
Yeah but when do we put minus?
Should member 5 and 6 matrix be the same?
Yes both have same cross section length and inclination with global axis so values of stiffness matrix elements will not change,
but the orientation of both members is opposite this will change the sign.
Hi sir, why at 20:19 is 1/AE and not AE?
How do you know where to label the numbers on each member's matrix
It's done member wise and what are the nodes associated with that member. Watch @ 1:40
Also refer previous video ruclips.net/video/vuqdVhxcSiw/видео.html
How to know the value of c, cs?
V nice
please provide solution for this
how do you rearranged and get those displacement values? at 21:20
did u find it
simply as we solved matrix in intermediate level.
The length at Member 6 and 5 how dd you compute to get it.... kindly please get back to me asap
Pythagorean theorem
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What represent ( cs) and (c) and (s) please help me
S-sin
CS-cos
CS-cos × sin
Theta-orientation of members with respect to+ve x axis
@@Kirank-81how will u know the value of it? I am confuse please help
Compute the angle by considering the triangle formed by the truss members@@gj57josh62
@@Kirank-81 is the angle going to the 1st quadrant? Like for example if I have an angle of 45 from the 2nd quadrant. I will subtract it from 180 and it will be 135 angle? Is that right?
Can I ask you something about the solution including fabrication errors and thermal changes? May I have your email adress?
Yes
kiran.koraddi@gmail.com