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Remainder theorem that if a polynomial which maybe represented by f(x) has a factor of (x-k), then the remainder is f(k)=0.If a factor is (ax-b),then the remainder is f(b/a)=0.(as ax-b=0 ,x= b/a)
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Why must x be equal to a though?
Thank you for your question. We've let x=a because we are working out what f(a) is (and proving that it is 0)
it does not have to equal a (its a function so x can take any value) but u can still check the case where x does equal a
Remainder theorem that if a polynomial which maybe represented by f(x) has a factor of (x-k), then the remainder is f(k)=0.
If a factor is (ax-b),then the remainder is f(b/a)=0.(as ax-b=0 ,x= b/a)
👍
Why must x be equal to a though?
Thank you for your question. We've let x=a because we are working out what f(a) is (and proving that it is 0)
it does not have to equal a (its a function so x can take any value) but u can still check the case where x does equal a