1:05 start 1:47 fundamental principle of multiplication 3:58 Q 10:20 Q 15:55 Q 19:29 Q 22:19 Q 28:32 Remark - sets 30:12 Q 34:18 Remark 35:18 Selection 38:33 Q 40:59 Q 47:24 Q 52:13 Q 54:29 Observation (Total no of selection) 57:52 Q 1:01:38 Q 1:03:10 Observation (Advance level) 1:08:18 Q 1:15:26 Geometrical Counting 1:15:40 Q 1:18:26 Q 1:22:24 Q 1:24:40 Q 1:27:56 Selection and Arrangement 1:32:05 Q 1:33:19 Gap method and block method 1:37:45 Q application 1:39:21 Q few objects alike 1:41:28 Q 1:45:15 Some special problems 1:45:20 Derangement problem 1:49:20 Dictionary problem 1:55:31 Divisors ,sum of Divisors and exponent of prime p in n! 2:04:37 Circular arrangement 2:11:21 Distribution of objects 2:16:02 Formation of groups 2:29:01 Distribution of alike objects 2:42:30 Last Question 2:45:03 The End Your welcome.
at 38:41, I used a different approach. For at most 3 red balls, we can calculate total ways - (cases with 4 red balls). 12C4 - 5C4 = 490. Is this method correct?? at 1:18:32, I used that in total there will be 7C2 lines made, and of those 4 points 4C2 lines are made (which is basically 1 line), so total number of lines = 7C2 - 4C2 + 1 = 16. (Replacing 4C2 lines with just 1 line because points are collinear). Is this approach correct??
1:25:32 koi bta skta h . 6 m se koi si bhi 2 choose krni h na. To hm consecutive line ko select nhi kr skte kya Kyunki koi si bhi 2 choose krna h?. Plz reply any one:
Hello, I'm quite late but still. We can choose consecutive lines for a rectangle (Bec a square is a Rectangle too). By writing 4C2*5C2, we are taking 2 random lines, thus it includes both separate and consecutive lines. Hope it helps.
I’ve always feared this chapter, but this one video made me enjoy the learning. Besides the fact that I’m not even preparing for jee.. he’s made such difficult questions easy to comprehend.❤
47:02 Um hey I tried to do this question by complementary approach but I'm missing some cases. Can u point out my mistake? Here's my method: No. Of ways to attempt the paper choosing atleast 1 question from each section= Total ways to attempt the 15 questions - ways in which no question is attempted from either one or 2 sections. Total ways = 15C5 Ways in which no question is attempted from two sections = 3×5C5 Ways in which no question is attempted from one section = [3(5C4×5C1) + 3(5C3×5C2) + 3(5C2×5C3) + 3(5C1×5C4)] Here, 3(5C4×5C1) shows that candidate attempted 4 questions from 1 section and 1 question from another section. 3(5C4×5C1) is not same as 3(5C1×5C4) as... It's better explained with example. A B C A B C A B C 4 1. 4. 1. 4. 1 And A B C. A B C. A B C 1 4. 1. 4. 1. 4 but my answer isn't correct. Please help
@@Patrick_Bateman71 But it is matching... check probably you did a calculation error. 15C5=3003 3x5C5=3 3[5x5+10x10+10x10+5x5]=3x250=750 Hence 3003-3-750=2250 which is the given answer. Good thought process though!
Bhai ek alike kaise hoga 1 hi select karna hai sab me se toh 1 same (alike) hone ka sense kya hai so 1 alike nhi ho sakta aur agar hoga bhi toh kiske saath hoga
1:05 start
1:47 fundamental principle of multiplication
3:58 Q
10:20 Q
15:55 Q
19:29 Q
22:19 Q
28:32 Remark - sets
30:12 Q
34:18 Remark
35:18 Selection
38:33 Q
40:59 Q
47:24 Q
52:13 Q
54:29 Observation (Total no of selection)
57:52 Q
1:01:38 Q
1:03:10 Observation (Advance level)
1:08:18 Q
1:15:26 Geometrical Counting
1:15:40 Q
1:18:26 Q
1:22:24 Q
1:24:40 Q
1:27:56 Selection and Arrangement
1:32:05 Q
1:33:19 Gap method and block method
1:37:45 Q application
1:39:21 Q few objects alike
1:41:28 Q
1:45:15 Some special problems
1:45:20 Derangement problem
1:49:20 Dictionary problem
1:55:31 Divisors ,sum of Divisors and exponent of prime p in n!
2:04:37 Circular arrangement
2:11:21 Distribution of objects
2:16:02 Formation of groups
2:29:01 Distribution of alike objects
2:42:30 Last Question
2:45:03 The End
Your welcome.
Thanks brother
Thanks bhaiya ❤
🎉
Your nahi you're hota hai akalmand insaan
✅👉MVSAT Registration Link : vsat.vedantu.com/?Ref_code=VVD8111
Okkkk
my fiitjee coaching didn't teach so well as he did and that too i was in a top batch
@@Anushkasingh-w5q maths faculty ofc
Can u please give your study material
Batch
And Location
I am currently in FIITJEE BOKARO CLASS 11 A02 Batch
I am also but my teacher taught......
Mere fiitjee branch pe kal start ho rahi hai ye ch
1:41:16
we can also use total words - words in which vowels always together
Unbelievable content💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💚💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜💜🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡🧡❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤💞💞💞💞💞💞💞💞💞💞💞💞💞💞💞💞💞❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️💗💗💗💗💗💗💗
at 38:41, I used a different approach. For at most 3 red balls, we can calculate total ways - (cases with 4 red balls). 12C4 - 5C4 = 490. Is this method correct??
at 1:18:32, I used that in total there will be 7C2 lines made, and of those 4 points 4C2 lines are made (which is basically 1 line), so total number of lines = 7C2 - 4C2 + 1 = 16. (Replacing 4C2 lines with just 1 line because points are collinear). Is this approach correct??
Most method by which you get correct ans is correct in PnC. I've not watched till the timestamps 👍
yes dude it is im in fiitjee and this is the (shortcut method)
Bhai Tera iit Nikla kya?
Sir, ajj mera birthday aapka ashirwaad chahiye tha .Physically toh nahi mila paya virtually hi mera pranam swikar kijiyega 🙏🙇🏼♂️
Regards Angshudeep
53:03 i approached another way
2*5C2*6C3
(In 1st set of the team i eleminated student A and In 2nd set of team I eleminated student B)
47:10 Selection with constraint cases insight
So true
Sir at 2:11:14 you have made 7 boys actually there should be 6. 😊 Thanks for the tremendous lecture and effort btw
Is it enough for class 11?
51:00 questions to be remember
💝
1:20:00 🙂
1:25:00
2:10:00
yoo, that was sick! : knock knock, kaun TERA BAAP NAHI, TERA BHAIIII AYAAAAA!!!!!
Sir vdo timing 1:02:53 wala question mai 4x3^4 hona chahiye ya 3^4x3^4x3^4x3^4
Great explanation sir ji 🙏
38:26
Sir yaha har H and W m se 2 choose krne ki possibility h so 2*2*2*2=16
Aise kr skte h kya?
1:25:32 koi bta skta h .
6 m se koi si bhi 2 choose krni h na.
To hm consecutive line ko select nhi kr skte kya
Kyunki koi si bhi 2 choose krna h?.
Plz reply any one:
Yrr mai y soch rha hu ki session m h. lines 7 hogyi aur v. Lines 6
Lg rha h sir ne question hi glt dia tha 🙃
Hello, I'm quite late but still. We can choose consecutive lines for a rectangle (Bec a square is a Rectangle too). By writing 4C2*5C2, we are taking 2 random lines, thus it includes both separate and consecutive lines. Hope it helps.
1:01:05 the reaction was epic 😂😂🎉🎉
I’ve always feared this chapter, but this one video made me enjoy the learning. Besides the fact that I’m not even preparing for jee.. he’s made such difficult questions easy to comprehend.❤
47:02 Um hey I tried to do this question by complementary approach but I'm missing some cases. Can u point out my mistake?
Here's my method:
No. Of ways to attempt the paper choosing atleast 1 question from each section= Total ways to attempt the 15 questions - ways in which no question is attempted from either one or 2 sections.
Total ways = 15C5
Ways in which no question is attempted from two sections = 3×5C5
Ways in which no question is attempted from one section = [3(5C4×5C1) + 3(5C3×5C2) + 3(5C2×5C3) + 3(5C1×5C4)]
Here,
3(5C4×5C1) shows that candidate attempted 4 questions from 1 section and 1 question from another section.
3(5C4×5C1) is not same as 3(5C1×5C4) as... It's better explained with example.
A B C A B C A B C
4 1. 4. 1. 4. 1
And
A B C. A B C. A B C
1 4. 1. 4. 1. 4
but my answer isn't correct. Please help
@@Patrick_Bateman71 I think uh should subtract the case in which candidate choose no question coz it is also one of the case ..Hope it will help uh
@@Patrick_Bateman71 But it is matching... check probably you did a calculation error.
15C5=3003
3x5C5=3
3[5x5+10x10+10x10+5x5]=3x250=750
Hence 3003-3-750=2250 which is the given answer. Good thought process though!
@Afnaan-sd4ws Jumping
wasnt able to do the first or second in the selection topic, but did this one 41:01
45:00
52:00
1:00:00
1:06:00
1:11:00
1:27:00
1:31:00
58:08 here 5c3 if for both A and B but agar ek ko hataya toh total boys toh 6 bachege na 6c3 hona chahiye can someone explain
same question
Bro ek ko htaya h or ek pehle s selct bhi to krlia h
Sir at 54:25 and is 400
Great lecture.... Thank you very much sir... 💝
Bhai ye 11 cbse class ke liye theek hai
God Bless you sir....
I wish if you could take offline classes at Durgapur ( Kota of West Bengal)...
I could send my daughter for offline classes..
50:00 wale question ke c) part ka ans galat hai pdf mein
35:00 selection ko pel dete hai ...waah sir waah
Can somebody tell that at 2:21:18 if all the books were same then how will we solve?
2:11:11 helll nahhhhhh😭😭
he is an amazing teacher
Thankyou sir ❤
Kya chapter h wah maza aa gaya
Ha bht question easy bhi aur kuch dimaag khau 😂
33:42
33:16 full of sets
This Sir made Maths Such A mood Refreshing Subject When I feel Disturbed I only See Sirs Maths Videos And I fell Good After that
Sir is it sufficient for jee mains ? Only concept
36:20 op moment
great explaination😍
Very very very very very nice video sir 👍😁
1:09:57 sir 3 diff 1 alike bhi to ho skta tha
Edit: 1 alike to kuch hota hi nhi h 3 diff aur 1 alike ka mtlb h 4 diff😅
Bhai ek alike kaise hoga 1 hi select karna hai sab me se toh 1 same (alike) hone ka sense kya hai so 1 alike nhi ho sakta aur agar hoga bhi toh kiske saath hoga
Wonderful lecture sir ❤❤❤❤
1:49:23 this is what relatives ask after exam.😅
34:56 & 35:05 😂😂😂 amazing😍👍😍 started
Thnks bhai ye clip dhundh rha thaa tumhare comment se mil gaya
Gajab sir maza aa gaya 👌❤️
1 chapter kr rha hu mne socha ye kisi or se interlink nhi hoga but ye sb interlink hai..😥😥😥
(Ap and gp)
Sir how to find rank of the any word
Bhai bhikari ajabi hai, Jo detha he or letha bhi hai 2:35:03 2:35:05 2:35:06 2:34:34 2:34:36
Thank you sir 💖
Thanks a lot Sir Amazing session
Your teaching method is very great 😊
1:14:00
2:39:57 try ka ans 55-28=17 aaaya
27*
26:58,soham
You are wonderful sir 👌
Thankyou sir ♥️♥️
Thank uh so much sir❤️
Best lecture on permutation and combn ❤❤❤thanks sir
Sir your another video on permutations and combinations is 6 hrs long what is the difference between that video and this video
question jyada honge bhai
Session pdf please sir........ ❤️❤️❤️
Description mai hai
@@ashishtiwary7947 thanks brother 😘
Thanks for your kindness✨🌼
1:20:48
thank you so much sir, it was a very helpful session💕
Thankyou so much sir for such understandable explanations for this chapter. I feel confident now 😇
Maja aa gaya sir❤❤❤
2:01:00
02:11:09
Thankyouuuu sir love youuuu❤
great explanation mera bhai mera bhai
good
he is giving almost 85% digestive Concept free
Complete Permutation & Combination in One Shot |Class11 Maths | JEE 2024 | Arvind Sir| Vedantu JEE
Can I watch dis for April attempt??
Yes me too
28:34 i literally got scared 💀
Maza a gya
Bhaii 🙌🙌✌️
thank you sir
very help vedio
Thank u sir for this amazing lecture ❤️
Bahut bahut shukriya sir ji
Better than my iitpk coaching institute
Sir waiting for next class Probability
36:44 🤣🤣🤣🤣
Awesome 💯💯💯💯💯💯💯💯💯💯 💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯💯 sir
1:28:06
Thankyou sir
Bhai maja aa gaya
Fact checked the guy from 1:01:04
Shai baat hai bhai aaya par sir acha lagta hai
Sir isme aapne grid problem nahi le
BERLIN of coaching industry
sir Session PDF Pleaseeee
Mera bhai ❤️
Sir muze kuch bhi samaz me nahi aya as a student my doubts are not clear.
Same
What is good marks in jee
190+
Jee 2024 kyun likha h
class 10th ke liye foundation hai ye
Jo abhi 11 m h unka jee 2024 batch h....u can count
Sir propebility kab ayega
@Soham Malpure please share the links
??
My Maths Finuer...
2:45:31 end of his bakwas😂
Sir IT WILL BE ENOUGH?
Us say v jaeyda
2 hr 45 min full chapter, really ??
Who are watching in 2🤩24 👇🏻
Mememememmememememememmeme