A good way to determine the cross product operation is to write out ijki. When you move to the right, e.g. from i to j you add the term, when you move left, e.g. i to k, you subtract the term. So for the the i direction you'd have (A_y * B_z - A_z * B_y) A_y * B_z is positive since you moved from left to right and A_z * B_y is negative (subtracted) since you moved from right to left.
In 0:59 time frame, you said that "a vector can formed as a sum of the scalar products of each of these basis vectors..." In the left hand side, it is a vector so it is obvious that it must be vector also in the right hand side, but in the quoted message, it's a scalar product which has a scalar value. It's contradicting. Can you please make some clarifications? Thank you, I've been really looking for some basic materials to learn Electrodynamics, and I think I found the right startup.
There typically is. He just multiplied the j-hat expression by -1 to reverse the terms so that I-j-k hat all added together. However, I think that just complicates the easier way to find the determinant. If I didn't already know how to find it, I think I would have been confused.
A good way to determine the cross product operation is to write out ijki. When you move to the right, e.g. from i to j you add the term, when you move left, e.g. i to k, you subtract the term.
So for the the i direction you'd have (A_y * B_z - A_z * B_y)
A_y * B_z is positive since you moved from left to right and
A_z * B_y is negative (subtracted) since you moved from right to left.
If you are still active, I cannot understand your approach. Please elaborate
Yep. That works too. Whatever helps you remember.
great series, helps in brushing up the basics. thumb's up!
Amazing Intro to the electrodynamics besides Griffiths is the great book for Intro to Electrodynamics and J.D.Jackson gives the priceless numerical :)
In the ciruit of fig. Below find the effetive capacitance and charge stored in each capacitor?
In 0:59 time frame, you said that "a vector can formed as a sum of the scalar products of each of these basis vectors..." In the left hand side, it is a vector so it is obvious that it must be vector also in the right hand side, but in the quoted message, it's a scalar product which has a scalar value. It's contradicting. Can you please make some clarifications? Thank you, I've been really looking for some basic materials to learn Electrodynamics, and I think I found the right startup.
There typically is. He just multiplied the j-hat expression by -1 to reverse the terms so that I-j-k hat all added together. However, I think that just complicates the easier way to find the determinant. If I didn't already know how to find it, I think I would have been confused.
I think the second term in the determinant should be -ve as per the rules of determinant.
No bro u are wrong