F = m×a a = Δv/Δt Frequency Ticker Timer is: f = 50 Hertz Time per Timer Tick is: T = 1/f 1/Hz = second 1/50 = 0,02 Measured over 5 Ticks is: 5 × 0,02 = 0,1 s Average Gravitational Acceleration is: 9,8 m/s² 10 mm = 1 cm = 0,01 m 10 g = 0,01 kg ------------------------------------------------------------------------------------------------------------ average velocity equals distance over time: v = Δs/Δt change in velocity equals final velocity minus initial velocity these series: velocity(n) = Segment(n) / 0,1 second ------------------------------------------------------------------------------------------------------------- ---------------- Run 1: Probe = 10 g Trolley = C1 + 40 g Tape 1: Segment 1: = 39 mm Segment 2: = 41 mm Segment 3: = 44mm ---------------- Run 2: Probe = 20 g Trolley = C1 + 30 g Tape 2: Segment 1: = 54 mm Segment 2: = 61 mm Segment 3: = 66 mm ---------------- Run 3: Probe = 30 g Trolley = C1 + 20 g Tape 3: Segment 1: = 62 mm Segment 2: = 68 mm Segment 3: = 79 mm ---------------- Run 4: Probe = 40 g Trolley = C1 + 10 g Tape 4: Segment 1: = 86 mm Segment 2: = 98 mm Segment 3: = 109 mm ---------------- Run 5: Probe = 50 g Trolley = C1 + 0 g Tape 5: Segment 1: = 90,5 mm Segment 2: = 105 mm Segment 3: = 118 mm ------------------------------------------------------------- Assignment: What is the mass of the Trolley C1? --------------------------------------------------------------
I'm not sure if I'm doing it wrong or what, but I got a negative acceleration for tape 2 and 4, if I ignore that negative, still tape 4 has the same acceleration as tape 1
![Newton's 2nd Law of Motion in Physics Explained - [1-5-6]](/img/1.gif)
Who else came here for experiment
Me
Me 😂
😂 I'm doing mine tmr
Doing mine today
@@nathan2friendly887 are you done ?
F = m×a
a = Δv/Δt
Frequency Ticker Timer is:
f = 50 Hertz
Time per Timer Tick is:
T = 1/f
1/Hz = second
1/50 = 0,02
Measured over 5 Ticks is:
5 × 0,02 = 0,1 s
Average Gravitational Acceleration is:
9,8 m/s²
10 mm = 1 cm = 0,01 m
10 g = 0,01 kg
------------------------------------------------------------------------------------------------------------
average velocity equals distance over time: v = Δs/Δt
change in velocity equals final velocity minus initial velocity
these series: velocity(n) = Segment(n) / 0,1 second
-------------------------------------------------------------------------------------------------------------
---------------- Run 1:
Probe = 10 g
Trolley = C1 + 40 g
Tape 1:
Segment 1: = 39 mm
Segment 2: = 41 mm
Segment 3: = 44mm
---------------- Run 2:
Probe = 20 g
Trolley = C1 + 30 g
Tape 2:
Segment 1: = 54 mm
Segment 2: = 61 mm
Segment 3: = 66 mm
---------------- Run 3:
Probe = 30 g
Trolley = C1 + 20 g
Tape 3:
Segment 1: = 62 mm
Segment 2: = 68 mm
Segment 3: = 79 mm
---------------- Run 4:
Probe = 40 g
Trolley = C1 + 10 g
Tape 4:
Segment 1: = 86 mm
Segment 2: = 98 mm
Segment 3: = 109 mm
---------------- Run 5:
Probe = 50 g
Trolley = C1 + 0 g
Tape 5:
Segment 1: = 90,5 mm
Segment 2: = 105 mm
Segment 3: = 118 mm
-------------------------------------------------------------
Assignment:
What is the mass of the Trolley C1?
--------------------------------------------------------------
you saved me so much time , thank you
Thanks a ton man
Saved me so much time God Bless
Signing in for the experiment in 2024.
It was good and very clear but you never explain the most difficult part for me right, the part where you divided the segments in half
Wow i love this!!! Hi I am a teacher. I would like to see more of these experiments i can show my learners.
Can you please help me with experiment of physical sciences
You a good teacher ✨
How can I draw a graph of force against acceleration
Thank you very much for posting this experiment. Its very helpful for my understanding.
Nah, this took NPC to the next level! 💀
Lol
Where can I get the questions and memo of this experiment
Where can I get the questions and the memo
Did you find it??@@RonnieMango-uf7kc
What safety precautions were considered during the experiment
Questions ; How did you gets 19mm as distance travelled
How do I calculate the gradient of the graph?
Gradient=y2-y1/x2-x1
Thank you so much for this video ,it really is helpful🙈
Where can i find the worksheets Part A, B and C? Do you have them online? I teach online so this is perfect to present as a practical.
Hi Willian, you can contact Kondi or Deva from the NECT (www.nect.org.za) for copies of the videos and supporting materials. Good luck!
@@classact5191 hi I wanna know the question
Relationship between acceleration and the net force on the trolley?
4:12 this part is confusing for me
Hi can i get the MEMO PLEASE
How about if u are told to use a space length of 10
I'm not sure if I'm doing it wrong or what, but I got a negative acceleration for tape 2 and 4, if I ignore that negative, still tape 4 has the same acceleration as tape 1
how come a mass be 20 gram while Hanger for the 1st time was 5g and the mass piece is 5g!?
that's what I'm trying to figure out😭
Hi can anyone help me here?
What is the function of the mass box
kayron and sean i know u are watching this
How can I calculate the gradient of the graph
Did you figure it out?
Hello, can i get the memo of this
Lol
how can l draw a graph with the results
My name is Aamir Khan , I am he , the rizzler aka rizzly bear aka rizzasaurus rex. I like big nyash
😂😂✌only nyash that we want
Aren't you from kc
who else is here from Think digital
me😭 bro do you have the memo
bro i hope you still got the memo
John and Joyce 💃💃💃
Who here from PBHS 👀
Memo??
where can i get these apparatus for my kids?
So when we are writing methods we are writing them in past tense??
ANYONE ELSE FROM FOREST ??????
11A?😂
Lento eyenziwa umiss kheri angiythandi sibhala imaths ksasa😭😮💨
11c
i see you boy 11B here
Zau bad ka nako
استغفر الله العظيم رب العرش العظيم
Gay
Lots of love from us big foot finders😮😮😮😮😮❤❤❤❤❤❤❤❤❤❤
Gadget 😬
Respectfully you guys explained nothing 🫶
fr and im doing an experiment on this 😪
@@Lihleza Same it's due tomorrow
Memo pls
How can I draw a graph showing relationship between the dependent and independent