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(106)+2ab+(106)=214 ((2^3)+2ab+(2^3). (1^1)+1ab+(2^3) (2^3) (ab ➖ 3+ab+2).
a=2,b=42
There are infinitely many solutions.S={ ( (a,b) : b=(214-a^2)/(2a+1) ∧ 0≤a ∧ a
Thanks for sharing your solution! It's a great reminder to always consider the domain of the variables. 🙏🤩
(106)+2ab+(106)=214 ((2^3)+2ab+(2^3). (1^1)+1ab+(2^3) (2^3) (ab ➖ 3+ab+2).
a=2,b=42
There are infinitely many solutions.
S={ ( (a,b) : b=(214-a^2)/(2a+1) ∧ 0≤a ∧ a
Thanks for sharing your solution! It's a great reminder to always consider the domain of the variables. 🙏🤩